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PhysicsMediumNumerical2021 · 25 Jul Shift 2

Q27.From the given data, the amount of energy required to break the nucleus of aluminium 2713Al is __________ x × 10−3 J Mass of neutron = 1. 00866 u Mass of proton = 1. 00726 u Mass of Aluminium nucleus = 27. 18846 u (Assume 1 u corresponds to x J of energy) (Round off to the nearest integer) of its initial value in 30 years. The half-life of

What This Question Tests

This question assesses the ability to calculate the mass defect and then use it to determine the binding energy of an aluminium nucleus based on the given mass-energy conversion factor.

Concepts Tested

Mass defectBinding energyMass-energy equivalence

Formulas Used

Δm = (Z*m_p + N*m_n) - m_nucleus

E_binding = Δm * c²

E = x * Δm (where 1u = x J)

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