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MathsMediumMCQ2022 ยท 25 Jul Shift 1

Q71.If the absolute maximum value of the function ๐‘“๐‘ฅ= x2 - 2x + 7e4x3 - 12x2 - 180x + 31in the interval -3, 0 is ๐‘“๐›ผ, then (1) ๐›ผ= 0 (2) ๐›ผ= - 3 (3) ๐›ผโˆˆ-1, 0 (4) ๐›ผโˆˆ-3, - 1

What This Question Tests

This question tests the ability to find the absolute maximum value of a function over a given interval by finding critical points using the derivative and evaluating the function at critical points and interval endpoints.

Concepts Tested

Absolute maximum value of a functionDerivativesCritical pointsExponential function properties

Formulas Used

f'(x) = 0 for critical points

First derivative test

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