Q51.The maximum number of orbitals which can be identified with n = 4 and ml = 0 is ______ JEE Main 2024 (04 Apr Shift 2) JEE Main Previous Year Paper
What This Question Tests
This question tests the fundamental understanding of quantum numbers and their relationship to the number of orbitals, specifically how 'n' and 'ml' values define possible orbitals.
Concepts Tested
Formulas Used
ml values: -l to +l
📚 NCERT Sections This Tests
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.4 — The Ground State Energy Of Hydrogen Atom Is –13.6 Ev. What Are The
Physics Class 12 · Chapter 12
12.4 The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
📋 Question Details
- Chapter
- Atomic Structure
- Topic
- Quantum Numbers and Orbitals
- Year
- 2024
- Shift
- 04 Apr Shift 2
- Q Number
- Q51
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 2: Atomic Structure
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Q79.Which of the following sets of quantum numbers is correct for an electron in 4f orbital? (1) n = 4, l = 3, m = +4, s = + 12 (2) n = 3, I = 2, m = −2, S = + 12 (3) n = 4, I = 3, m = +1, s = + 12 (4) n = 4, I = 4, m −4, s = −12