Q55.Number of optical isomers possible for 2 – chlorobutane ........
What This Question Tests
This question evaluates the understanding of optical isomerism by identifying the number of chiral centers in a given organic compound and calculating the maximum number of possible stereoisomers.
Concepts Tested
Formulas Used
Number of optical isomers = 2^n (where n is the number of chiral centers)
📚 NCERT Sections This Tests
5.12 — Write All The Geometrical Isomers Of [Pt(Nh3)(Br)(Cl)(Py)] And How Many Of
Chemistry Class 11 · Chapter 5
5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
5.11 — Draw All The Isomers (Geometrical And Optical) Of:
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5.11 Draw all the isomers (geometrical and optical) of: (i) [CoCl2(en)2] + (ii) [Co(NH3)Cl(en)2] 2+ (iii) [Co(NH3)2Cl2(en)]+
7.6 — Give Structures Of The Products You Would Expect When Each Of The
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7.6 Give structures of the products you would expect when each of the following alcohol reacts with (a) HCl –ZnCl2 (b) HBr and (c) SOCl2. (i) Butan-1-ol (ii) 2-Methylbutan-2-ol
📋 Question Details
- Chapter
- Organic: Stereochemistry
- Topic
- Optical Isomerism
- Year
- 2024
- Shift
- 01 Feb Shift 1
- Q Number
- Q55
- Type
- Numerical
- NCERT Ref
- Class 12 Chemistry Ch 10: Haloalkanes and Haloarenes