Practice Questions
1,013 questions across 23 years of JEE Main β find and practise any topic!
Found 1,013 results
Q73.Let π be a differentiable function such that π₯2ππ₯- π₯= 4 π₯π‘ ππ‘ ππ‘, π1 = 2 Then 18 π3 is equal to β«0 3. (1) 210 (2) 160 (3) 150 (4) 180
Q73.Let π΄= {π₯ββ: π₯+ 3 + π₯+ 4 β€3}, π΅= π₯ββ: 3π₯βπ= 1 10π < 3-3π₯, where [π‘] denotes greatest integer function. Then, (1) π΅βπΆ, π΄β π΅ (2) π΄β©π΅= π (3) π΄βπ΅, π΄β π΅ (4) π΄= π΅
Q73.Let ππ₯= 2π₯+ tan-1π₯ and ππ₯= logπβ1 + π₯2 + π₯, π₯β0, 3. Then (1) There exists π₯β0, 3 such that π'π₯< π'π₯ (2) max ππ₯> max ππ₯ (3) There exist 0 < π₯1 < π₯2 < 3 such that ππ₯< ππ₯, (4) min π'π₯= 1 + max π'π₯ βπ₯βπ₯1, π₯2 Q74. 1 + sin2π₯ cos2π₯ sin2π₯ π π Let ππ₯= sin2π₯ 1 + cos2π₯ sin2π₯ , x β 6, 3 . If πΌ and π½ respectively are the maximum and the sin2π₯ cos2π₯ 1 + sin2π₯ minimum values of π, then 19 19 (1) π½2 - 2βπΌ= 4 (2) π½2 + 2βπΌ= 4 9 (3) πΌ2 - π½2 = 4β3 (4) πΌ2 + π½2 = 2
Q74.The number of relations, on the set {1, 2, 3} containing (1, 2) and (2, 3) which are reflexive and transitive but not symmetric, is _________. . If B = , then the sum of all the elements of the matrix β50n=1 Bn is [β1 β1 ] A[ 1 1 ]
Q74.For πΌ, π½, πΎ, πΏββ, if β« π₯ 2π₯+ and πΆ is constant of π π₯ π 2π₯logππ₯ππ₯= πΌ1 π₯π π½π₯- 1πΎ π₯π πΏπ₯+ πΆ, where π= βπ=β 0 π!1 integration, then πΌ+ 2π½+ 3πΎ- 4πΏ is equal to (1) 1 (2) 4 (3) -4 (4) -8
Q74.Let P(S) denote the power set of S = {1, 2, 3, β¦ , 10} . Define the relations R1 and R2 on P(S) as AR1B if (A β©Bc) βͺ(B β©Ac) = Ο and AR2 B if A βͺBc = B βͺAc, βA, B βP(S) . Then : (1) both R1 and R2 are equivalence relations (2) only R1 is an equivalence relation (3) only R2 is an equivalence relation (4) both R1 and R2 are not equivalence relations 1 1 β3 then,
Q75.An arc ππ of a circle subtends a right angle at its centre π. The mid point of the arc ππ is π . If βππ= βπ’, βππ = βπ£ and βππ= πΌβπ’+ π½βπ£, then πΌ, π½2, are the roots of the equation (1) π₯2 + π₯- 2 = 0 (2) π₯2 - π₯- 2 = 0 (3) 3π₯2 - 2π₯- 1 = 0 (4) 3π₯2 + 2π₯- 1 = 0
Q75.If S = {x βR sinβ1( βx2+2x+2x+1 ) βsinβ1( βx2+1x ) βxβS(sin((x2 + x + 5) Ο2 ) βcos((x2 + x + 5)Ο)) is equal to _________.
Q75.Let πΌπ₯= β«π₯2π₯ ( π₯ tanπ₯+ 1 2 ππ₯ If πΌ0 = 0, then πΌπ4 is equal to ) (1) ( π+ 4 ) 2 π2 (2) ( π+ 4 ) 2 π2 loge 16 + 4 ( π+ 4 ) loge 16 - 4 ( π+ 4 ) (3) ( π+ 4 ) 2 π2 (4) ( π+ 4 ) 2 π2 loge 32 - 4 ( π+ 4 ) loge 32 + 4 ( π+ 4 )
Q76.The area enclosed by the closed curve πΆ given by the differential equation ππ¦ π₯+ π = 0, π¦1 = 0 is 4π. Let π ππ₯+ π¦- 2 and π be the points of intersection of the curve πΆ and the π¦-axis. If normals at π and π on the curve πΆ intersect π₯-axis at points π and π respectively, then the length of the line segment π π is (1) 2β3 (2) 2β3 3 (3) 2 (4) 4β3 3 JEE Main 2023 (01 Feb Shift 1) JEE Main Previous Year Paper
Q76.Let the solution curve π¦= π¦( π₯) of the differential equation ππ¦ 3π₯5tan-1π₯33 π¦= 2π₯ exp π₯3 - tan-1π₯3 pass through ππ₯- 1 + π₯6 2 β( 1 + π₯) 6 the origin. Then π¦( 1 ) is equal to: (1) exp4 - π (2) expπ- 4 4β2 4β2 (3) exp1 - π (4) exp4 + π 4β2 4β2 β β
Q76.Let f : R βR be a function defined by f(x) = logβm {β2(sin β2}, for some the range of f is [0, 2]. Then the value of m is _____ . (1) 5 (2) 3 (3) 2 (4) 4
Q76.Let P be a square matrix such that P 2 = I βP . For Ξ±, Ξ², Ξ³, Ξ΄ βN, if P Ξ± + P Ξ² = Ξ³l β29P and P Ξ± βP Ξ² = Ξ΄l β13P , then Ξ± + Ξ² + Ξ³ βΞ΄ is equal to (1) 18 (2) 40 (3) 22 (4) 24
Q76.Let βπ’= ^π- ^π- 2 ^π, βπ£= 2 ^π+ ^π- ^π, βπ£Β· βπ€= 2 and βπ£Γ βπ€= βπ’+ π βπ£, then βπ’Β· βπ€ is equal to 3 (1) 1 (2) 2 2 (3) 2 (4) - 3
Q77.The number of functions f : {1, 2, 3, 4} β{a βZ : |a| β€8} satisfying f(n) + n1 f(n + 1) = 1, β n β{1, 2, 3} is (1) 3 (2) 4 (3) 1 (4) 2 Ξ» (1 + | cos x|)Q78. , 0 < x < Ο2 |cos x| β§ ΞΌ, x = Ο2 is continuous at x = Ο2 , then If the function f(x) = β¨ cot 6x cot 4x β© e , Ο2 < x < Ο 9Ξ» + 6 logc ΞΌ + ΞΌ6 βe6Ξ» is equal to (1) 11 (2) 8 (3) 2e4 + 8 (4) 10
Q77. x + 1 x x If x x + Ξ» x = 89 (103x + 81), then Ξ», Ξ»3 are the roots of the equation x x x + Ξ»2 (1) 4x2 + 24x β27 = 0 (2) 4x2 β24x β27 = 0 (3) 4x2 + 24x + 27 = 0 (4) 4x2 β24x + 27 = 0
Q77.Let D be the domain of the function f(x) = sinβ1(log3x( 6+2β5xlog3 x )). If the range of the function defined by g(x) = x β[x], ( [x] is the greatest integer function), is (Ξ±, Ξ²), then Ξ±2 + Ξ²5 is equal to (1) 135 (2) 45 (3) 46 (4) 136
Q78.Let A = {1, 2, 3, 5, 8, 9} . Then the number of possible functions f : A βA such that f(m β n) = f(m) β f(n) for every m, n βA with m β n βA is equal to ax + bx2, a β 2b have a common extreme point,
Q78.Let (a, b) β(0, 2Ο) be the largest interval for which sinβ1(sin ΞΈ) βcosβ1(sin ΞΈ) > 0, ΞΈ β(0, 2Ο), holds . If Ξ±x2 + Ξ²x + sinβ1(x2 β6x + 10) + cosβ1(x2 β6x + 10) = 0 and Ξ± βΞ² = b βa, then Ξ± is equal to; JEE Main 2023 (31 Jan Shift 2) JEE Main Previous Year Paper (1) Ο (2) Ο 8 48 (3) Ο (4) Ο 16 12
Q78.One vertex of a rectangular parallelopiped is at the origin π and the lengths of its edges along π₯, π¦ and π§ axes are 3, 4 and 5 units respectively. Let π be the vertex ( 3, 4, 5 ) . Then the shortest distance between the diagonal ππ and an edge parallel to π§ axis, not passing through π or π is 12 (1) (2) 12β5 β5 12 12 (3) (4) 5β5 5
Q78.Let the foot of perpendicular of the point P(3, β2, β9) on the plane passing through the points (β1, β2, β3), (9, 3, 4), (9, β2, 1) be Q(Ξ±, Ξ², Ξ³). Then the distance Q from the origin is (1) β42 (2) β38 (3) β35 (4) β29
Q78.The line, that is coplanar to the line π₯+ 3 = π¦- 1 = π§- 5 , is -3 1 5 (1) π₯+ 1 = π¦- 2 = π§- 5 (2) π₯+ 1 = π¦- 2 = π§- 5 -1 2 4 -1 2 5 (3) π₯- 1 = π¦- 2 = π§- 5 (4) π₯+ 1 = π¦- 2 = π§- 5 -1 2 5 1 2 5
Q78.Consider a function f : N βR, satisfying f(1) + 2f(2) + 3f(3) + β¦ + xf(x) = x(x + 1)f(x) ; x β₯2 with f(1) = 1 . Then f(2022)1 + f(2028)1 is equal to JEE Main 2023 (29 Jan Shift 2) JEE Main Previous Year Paper (1) 8200 (2) 8000 (3) 8400 (4) 8100
Q78.If domain of the function loge( 6x2+5x+12xβ1 ) cosβ1( 2x2β3x+43xβ5 ) is is equal to JEE Main 2023 (08 Apr Shift 2) JEE Main Previous Year Paper
Q79.The set of all a βR for which the equation x|x β1| + |x + 2| + a = 0 has exactly one real root, is (1) (β7, β) (2) (ββ, β) (3) (β6, β3) (4) (ββ, β3) dx = Q80. β«β0 e3x+6e2x+11ex+66 (1) loge( 3227 ) (2) loge( 51281 ) (3) loge( 25681 ) (4) loge( 30227 )