Practice Questions
1,770 questions across 23 years of JEE Main β find and practise any topic!
Found 1,770 results
Q75.Let [t] denote the greatest integer less than or equal to t. Then the value of the integral β«101β3 ([sin(Οx)] + e[cos(2Οx)])dx is equal to (1) 52(1βe) (2) 52 e e (3) 52(2+e) (4) 104 e e
Q75.Let = , where a, b, c are constants. represent a circle passing through the point (2, 5). Then the dx bx+cy+a shortest distance of the point (11, 6) from this circle is (1) 10 (2) 8 (3) 7 (4) 5 dy 2xβy(2yβ1)
Q75.The area of the region {(x, y) : |x β1| β€y β€β5 βx2} (1) 5 2 sinβ1( 53 ) β12 (2) 5Ο4 β32 (3) 3Ο 4 + 23 (4) 5Ο4 β12 + = 1 pass through the point
Q75.The area of the smaller region enclosed by the curves y2 = 8x + 4 and x2 + y2 + 4β3x β4 = 0 is equal to (1) 1 + + 3 (2 β12β3 8Ο) (2) 13 (2 β12β3 6Ο) (3) 1 β12β3 + β12β3 + 3 (4 8Ο) (4) 13 (4 6Ο)
Q75.Let f(x) = 2 cosβ1 x + 4 cotβ1 x β3x2 β2x + 10, x β[β1, 1]. If [a, b] is the range of the function, then 4a βb is equal to (1) 11 (2) 11 βΟ (3) 11 + Ο (4) 15 βΟ
Q75.The integral β«10 [11x ] 7 (1) 1 β6 ln( 76 ) (2) 1 + 6 ln( 76 ) (3) 1 β7 ln( 76 ) (4) 1 + 7 ln( 76 )
Q76.Let π¦= π¦π₯ be the solution curve of the differential equation ππ¦ 2π₯2 + 11π₯+ 13 π₯+ 3 π₯> - 1, which ππ₯+ π₯3 + 6π₯2 + 11π₯+ 6π¦= π₯+ 1, passes through the point 0, 1. Then π¦1 is equal to 1 3 (1) (2) 2 2 5 7 (3) (4) 2 2
Q76.If y = y(x) is the solution of the differential equation x dxdy + 2y = xex, y(1) = 0 then the local maximum value of the function z(x) = x2y(x) βex, x βR is (1) 1 βe (2) 0 (3) 1 (4) 4 e βe 2
Q76.Let π¦= π¦π₯ be the solution of the differential equation π₯+ 1π¦' - π¦= e3π₯π₯+ 12, with π¦0 = 13. Then, the point 4 π₯= - for the curve π¦= π¦π₯ is 3 (1) not a critical point (2) a point of local minima (3) a point of local maxima (4) a point of inflection
Q76.Consider a curve y = y(x) in the first quadrant as shown in the figure. Let the area A1 is twice the area A2 . Then the normal to the curve perpendicular to the line 2x β12y = 15 does NOT pass through the point __ JEE Main 2022 (27 Jul Shift 2) JEE Main Previous Year Paper β (1) (6, 21) (2) (8, 9) (3) (10, β4) (4) (12, β15)
Q76.If π¦= π¦π₯, π₯β0, π be the solution curve of the differential equation 2 sin22π₯ ππ¦ 8sin22π₯+ 2sin4π₯π¦= ππ₯+ 2π-4π₯2sin2π₯+ cos2π₯, with π¦π = π-π, then π¦π is equal to 4 6 2 2π 3 (2) 3 (1) β3π-2π2 β3π 1 2π 3 (4) 3 (3) β3π-2π1 β3π JEE Main 2022 (28 Jul Shift 1) JEE Main Previous Year Paper
Q77.If two distinct point Q, R lie on the line of intersection of the planes βx + 2y βz = 0 and 3x β5y + 2z = 0 and PQ = PR = β18 where the point P is (1, β2, 3), then the area of the triangle PQR is equal to (1) 2 3 β38 (2) 43 β38 (3) 8 3 β38 (4) β1523
Q77.Let βa = Λi βΛj + 2Λk and let b be a vector such that βaΓ b = 2Λi βΛk and βaβ b = 3 . Then the projection of b on the β vector βaβ b is: (1) 2 (2) β21 2β37 (3) 2 (4) 2 3 3 β73
Q77.If the solution curve π¦= π¦π₯ of the differential equation π¦2 dπ₯+ π₯2 - π₯π¦+ π¦2dπ¦= 0, which passes through the point 1, 1 and intersects the line π¦= β3π₯ at the point πΌ, β3πΌ, then value of logπβ3πΌ is equal to π π (1) (2) 2 4 (3) π (4) π 6 12 JEE Main 2022 (25 Jun Shift 1) JEE Main Previous Year Paper
Q77.Let βa = Λi + Λj βΛk and βc= 2Λi β3Λj + 2Λk. Then the number of vectors b such that b Γβc=βa and β b β{1, 2, β¦ , 10} is (1) 0 (2) 1 (3) 2 (4) 3
Q77.If x = x(y) is the solution of the differential equation y dxdy = 2x + y3(y + 1)ey, x(1) = 0 ; then x(e) is equal to (1) ee(e3 β1) (2) e3(ee β1) (3) ee β1 (4) ee(e2 β1) Γ
Q78.Let π be the plane containing the straight line = = and perpendicular to the plane containing the 9 -1 -5 straight lines π₯ = π¦ = π§ and π₯ = π¦ = π§ If π is the distance of π from the point 2, - 5, 11, then π2 is equal to 2 3 5 3 7 8. 147 (1) (2) 96 2 32 (3) (4) 54 3
Q78.Let the foot of the perpendicular from the point (1, 2, 4) on the line x+24 = yβ12 = z+13 be distance of P from the plane 3x + 4y + 12z + 23 = 0 is (1) 50 (2) 63 13 13 (3) 65 (4) 4 13
Q78.Let the solution curve π¦= ππ₯ of the differential equation ππ¦ π₯π¦ = π₯4 + 2π₯ , π₯β-1, 1 pass through the ππ₯+ π₯2 - 1 β1 - π₯2 β3 origin. Then β« 2 ππ₯ππ₯ is equal to -β3 2 π 1 π β3 (1) - (2) - 3 4 3 4 (3) π - β3 (4) π - β3 6 4 6 2
Q78.Let βπ, βπ, βπ be three coplanar concurrent vectors such that angles between any two of them is same. If the product of their magnitudes is 14 and βπΓ βπΒ· βπΓ βπ+ βπΓ βπΒ· βπΓ βπ+ βπΓ βπΒ· βπΓ βπ= 168 then βπ+ βπ+ βπ is equal to (1) 10 (2) 14 (3) 16 (4) 18
Q78.Let βπ= π1 ^π+ π2 ^π+ π3 ^π, ππ> 0, π= 1, 2, 3 be a vector which makes equal angles with the coordinate axes ππ, ππ and ππ. Also, let the projection of βπ on the vector 3 ^π+ 4 ^π be 7 . Let βπ be a vector obtained by rotating βπ with 90Β°. If βπ, βπ and π₯-axis are coplanar, then projection of a vector βπ on 3 ^π+ 4 ^π is equal to (1) β7 (2) β2 (3) 2 (4) 7
Q78.The acute angle between the planes P1 and P2 , when P1 and P2 are the planes passing through the intersection of the planes 5x + 8y + 13z β29 = 0 and 8x β7y + z β20 = 0 and the points (2, 1, 3) and (0, 1, 2), respectively, is (1) Ο (2) Ο 3 4 (3) Ο (4) Ο 6 12 JEE Main 2022 (28 Jun Shift 1) JEE Main Previous Year Paper = 6 and
Q78.Let βa = Λi + Λj + 2Λk, b = 2Λi β3Λj + Λk and βc= Λi βΛj + Λk be the three given vectors. Let βvbe a vector in the β plane of βa and b whose projection on βcis 2 . If βv,Λj = 7 , then βv + is equal to β3 β (Λi Λk) (1) 6 (2) 7 (3) 8 (4) 9
Q78.The length of the perpendicular from the point (1, β2, 5) on the line passing through (1, 2, 4) and parallel to the line x + y βz = 0 = x β2y + 3z β5 is: (1) β212 (2) β92 (3) β732 (4) 1
Q79.If the foot of the perpendicular from the point A(β1, 4, 3) on the plane P : 2x + my + nz = 4, is (β2, 72 , 32 ), then the distance of the point A from the plane P , measured parallel to a line with direction ratios 3, β1, β4, is equal to (1) 1 (2) β26 (3) 2β2 (4) β14