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Practice Questions

10,171 questions across 23 years of JEE Main β€” find and practise any topic!

Found 10,171 results

Q62.The sum of the first 20 terms of the series 5 + 11 + 19 + 29 + 41 + . . . is (1) 3520 (2) 3450 (3) 3250 (4) 3420

202306 Apr Shift 1Sequences & Series
MathsMedium

Q62.If π‘Žπ‘›= 4𝑛2 - 16𝑛+ 15, then π‘Ž1 + π‘Ž2 + … . + π‘Ž25 is equal to: (1) 51 (2) 49 144 138 50 52 (3) (4) 141 147 1 15

202330 Jan Shift 1Sequences & Series
MathsMedium

Q62.If for z = Ξ± + iΞ², |z + 2| = z + 4(1 + i), then Ξ± + Ξ² and Ξ±Ξ² are the roots of the equation (1) x2 + 3x βˆ’4 = 0 (2) x2 + 7x + 12 = 0 (3) x2 + x βˆ’12 = 0 (4) x2 + 2x βˆ’3 = 0

202308 Apr Shift 1Complex Numbers
MathsMedium

Q62.Let z1 = 2 + 3i and z2 = 3 + 4i . The set S = {z ∈C : |z βˆ’z1|2 βˆ’|z βˆ’z2|2 = |z1 βˆ’z2|2} represents a (1) straight line with sum of its intercepts on the (2) hyperbola with the length of the transverse axis 7 coordinate axes equals 14 (3) straight line with the sum of its intercepts on the (4) hyperbola with eccentricity 2 coordinate axes equals βˆ’18

202325 Jan Shift 1Complex Numbers
MathsMedium

Q62.Let C be the circle in the complex plane with centre z0 = 12 (1 + 3i) and radius r = 1. Let z1 = 1 + i and the complex number z2 be outside circle C such that |z1 βˆ’z0||z2 βˆ’z0| = 1 . If z0, z1 and z2 are collinear, then the smaller value of |z2|2 is equal to (1) 5 (2) 7 2 2 (3) 13 (4) 3 2 2

202312 Apr Shift 1Complex Numbers
MathsMedium

Q62.Let z be a complex number such that zβˆ’2iz+i = 2, z β‰ βˆ’i. Then z lies on the circle of radius 2 and centre (1) (2, 0) (2) (0, 2) (3) (0, 0) (4) (0, βˆ’2)

202325 Jan Shift 2Complex Numbers
MathsMedium

Q62.Let A = {ΞΈ ∈(0, 2Ο€) : 1+2i1βˆ’i sinsinΞΈΞΈ is purely imaginary} Then the sum of the elements is in A is (1) 4Ο€ (2) 3Ο€ (3) Ο€ (4) 2Ο€

202308 Apr Shift 2Complex Numbers
MathsMedium

Q62.Let 𝑀1 be the point obtained by the rotation of 𝑧1 = 5 + 4𝑖 about the origin through a right angle in the anticlockwise direction, and 𝑀2 be the point obtained by the rotation of 𝑧2 = 3 + 5𝑖 about the origin through a right angle in the clockwise direction. Then the principal argument 𝑀1 - 𝑀2 is equal to (1) πœ‹- tan-18 (2) -πœ‹+ tan-133 9 5 (3) -πœ‹+ tan-18 (4) πœ‹- tan-133 9 5

202311 Apr Shift 1Complex Numbers
MathsMedium

Q62.Let the first term a and the common ratio π‘Ÿ of a geometric progression be positive integers. If the sum of squares of its first three terms is 33033, then the sum of these three terms is equal to (1) 241 (2) 231 (3) 210 (4) 220 1 13 1 13

202310 Apr Shift 1Sequences & Series
MathsMedium

Q62.For three positive integers 𝑝, π‘ž, π‘Ÿ, π‘₯π‘π‘ž2 = π‘¦π‘žπ‘Ÿ= 𝑧𝑝2π‘Ÿ and π‘Ÿ= π‘π‘ž+ 1 such that 1 3, 3log𝑦π‘₯, 3 log𝑧𝑦, 7logπ‘₯𝑧 are in A.P. with common difference 2. The π‘Ÿ- 𝑝- π‘ž is equal to (1) 2 (2) 6 (3) 12 (4) -6

202324 Jan Shift 1Coordination Compounds
ChemistryMedium

Q62.If the center and radius of the circle = 2 are respectively 𝛼, 𝛽 and 𝛾, then 3𝛼+ 𝛽+ 𝛾 is equal to 𝑧- 3 (1) 11 (2) 9 (3) 10 (4) 12

202301 Feb Shift 1Complex Numbers
MathsMedium

Q63.Let x and y be distinct integers where 1 ≀x ≀25 and 1 ≀y ≀25. Then, the number of ways of choosing x and y, such that x + y is divisible by 5 , is _____ .

202325 Jan Shift 1Permutation & Combination
MathsMedium

Q63.All words, with or without meaning, are made using all the letters of the word π‘€π‘‚π‘π·π΄π‘Œ. These words are written as in a dictionary with serial numbers. The serial number of the word π‘€π‘‚π‘π·π΄π‘Œ is JEE Main 2023 (13 Apr Shift 2) JEE Main Previous Year Paper (1) 327 (2) 328 (3) 324 (4) 326

202313 Apr Shift 2Chemical Kinetics
ChemistryMedium

Q63.The number of arrangements of the letters of the word "INDEPENDENCE" in which all the vowels always occur together is (1) 16800 (2) 33600 (3) 18000 (4) 14800

202308 Apr Shift 1Permutation & Combination
MathsMedium

Q63.The number of five-digit numbers, greater than 40000 and divisible by 5 , which can be formed using the digits 0, 1, 3, 5, 7 and 9 without repetition, is equal to (1) 132 (2) 120 (3) 72 (4) 96

202312 Apr Shift 1Permutation & Combination
MathsMedium

Q63.Let π‘Ž1, π‘Ž2, π‘Ž3, . . . . , π‘Žπ‘› be n positive consecutive terms of an arithmetic progression. If 𝑑> 0 is its common difference, then lim 𝑑 1 + 1 + … + 1 is π‘›β†’βˆžβˆš 𝑛 βˆšπ‘Ž1 + βˆšπ‘Ž2 βˆšπ‘Ž2 + βˆšπ‘Ž3 βˆšπ‘Žπ‘›- 1 + βˆšπ‘Žπ‘› (1) 1 (2) βˆšπ‘‘ βˆšπ‘‘ (3) 1 (4) 2 𝑛

202306 Apr Shift 1Limits & Continuity
MathsMedium

Q63.If all the six digit numbers x1x2x3x4x5x6 with 0 < x1 < x2 < x3 < x4 < x5 < x6 are arranged in the increasing order, then the sum of the digits in the 72th number is _______.

202329 Jan Shift 1Permutation & Combination
MathsMedium

Q63.The number of seven digits odd numbers, that can be formed using all the seven digits 1, 2, 2, 2, 3, 3, 5 is

202330 Jan Shift 2Permutation & Combination
MathsMedium

Q63.If the number of words, with or without meaning. which can be made using all the letters of the word MATHEMATICS in which C and S do not come together, is (6!)k then k is equal to (1) 2835 (2) 5670 (3) 1890 (4) 945

202308 Apr Shift 2Permutation & Combination
MathsMedium

Q63.All the letters of the word PUBLIC are written in all possible orders and these words are written as in a dictionary with serial numbers. Then the serial number of the word PUBLIC is (1) 576 (2) 578 (3) 580 (4) 582

202306 Apr Shift 2Permutation & Combination
MathsMedium

Q63.If 𝑆𝑛= 4 + 11 + 21 + 34 + 50 + … to 𝑛 terms, then 60𝑆29 - 𝑆9 is equal to (1) 223 (2) 226 (3) 220 (4) 227

202310 Apr Shift 2Sequences & Series
MathsMedium

Q63.Number of integral solutions to the equation x + y + z = 21 , where x β‰₯1, y β‰₯3, z β‰₯4 , is equal to _____ .

202301 Feb Shift 2Permutation & Combination
MathsMedium

Q63.Let a1, a2, a3, … …. be an A.P. If a7 = 3, the product (a1a4) is minimum and the sum of its first n terms is zero then n! βˆ’4an(n+2) is equal to (1) 381 (2) 9 4 (3) 33 (4) 24 4

202331 Jan Shift 2Sequences & Series
MathsMedium

Q63.If the coefficient of π‘₯7 in π‘Žπ‘₯- and the coefficient of π‘₯-5 in π‘Žπ‘₯+ are equal, then π‘Ž4𝑏4 is equal to: 𝑏π‘₯2 𝑏π‘₯2 (1) 11 (2) 44 (3) 22 (4) 33. πœ‹ 2πœ‹ 4πœ‹ 8πœ‹ 16πœ‹ Q64.96 cos cos cos cos cos is equal to 33 33 33 33 33 (1) 3 (2) 1 (3) 4 (4) 2

202310 Apr Shift 1Binomial Theorem
MathsMedium

Q63.Let S = {z ∈C βˆ’{i, 2i} z2βˆ’3izβˆ’2 ∈R}. JEE Main 2023 (11 Apr Shift 2) JEE Main Previous Year Paper

202311 Apr Shift 2Complex Numbers
MathsMedium

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