Practice Questions
10,171 questions across 23 years of JEE Main — find and practise any topic!
Found 10,171 results
Q39.Given below are two statements: Statement I: For KI, molar conductivity increases steeply with dilution. Statement II: For carbonic acid, molar conductivity increases slowly with dilution. In the light of the above statements, choose the correct answer from the options given below (1) Statement I is correct and Statement II is (2) Both Statement I and Statement II are false incorrect (3) Statement I is true but Statement II is false (4) Statement I is false but Statement II is true
Q39.Given below are two statements : one is labelled as Assertion and the other is labelled as Reason. Assertion: At 10 °C, the density of a 5 M solution of KCl [atomic masses of K & Cl are 39 & 35. 5 g mol−1 respectively], is ' x' gml−1 . The solution is cooled to −21 °C. The molality of the solution will remain unchanged. Reason: The molality of a solution does not change with temperature as mass remains unaffected with temperature. In the light of the above statements, choose the correct answer from the options given below. (1) Assertion is true but Reason is false. (2) Assertion is false but Reason is true. (3) Both Assertion and Reason are true and Reason is (4) Both Assertion and Reason are true but Reason is the correct explanation of Assertion. not the correct explanation of Assertion.
Q39.Arrange the following in increasing order of reactivity towards nitration A. p-xylene B. bromobenzene C. mesitylene D. nitrobenzene E. benzene Choose the correct answer from the options given below (1) C < D < E < A < B (2) D < B < E < A < C (3) D < C < E < A < B (4) C < D < E < B < A
Q39.Two isomers ' A' and ' B' with molecular formula C4H8 give different products on oxidation with KMnO4 in acidic medium. Isomer ' A' on reaction with KMnO4 /H+ results in effervescence of a gas and gives ketone. The compound ' A' is (1) But- 1-ene. (2) cis-But- 2-ene. (3) trans-But- 2-ene. (4) 2-methyl propene. JEE Main 2022 (29 Jun Shift 1) JEE Main Previous Year Paper
Q39.Solute A associates in water. When 0 . 7 g of solute A is dissolved in 42 . 0 g of water, it depresses the freezing point by 0 . 2 °C. The percentage association of solute A in water, is [Given: Molar mass of A = 93 g mol-1. Molal depression constant of water is 1 . 86 K kg mol-1] (1) 50% (2) 60% (3) 70% (4) 80%
Q39.The correct stability order of the following diazonium salt is (1) (A) > (B) > (C) > (D) (2) (A) > (C) > (D) > (B) (3) (C) > (A) > (D) > (B) (4) (C) > (D) > (B) > (A) Q40. ˙Cl + CH4 →A + B A and B in the above atmospheric reaction step are (1) C2H6 and Cl2 (2) ˙C HCl2 and H2 (3) CH3˙ and HCl (4) C2H6 and HCl
Q39.Correct statement about photo-chemical smog is (1) It occurs in humid climate. (2) It is a mixture of smoke, fog and SO2 . (3) It is reducing smog. (4) It results from reaction of unsaturated hydrocarbons.
Q39.A compound 'A' on reaction with 'X' and 'Y produces the same major product but different by product 'a' and 'b'. Oxidation of 'a' gives a substance produced by ants. JEE Main 2022 (25 Jul Shift 1) JEE Main Previous Year Paper 'X' and 'Y' respectively are (1) KMnO4 / H+and dil. KMnO4, 273 K (2) KMnO4,(dilute), 273 K and KMnO4 / H+ (3) KMnO4 / H+ and O3, H2O / Zn (4) O3, H2O / Zn and KMnO4 / H+
Q39.Choose the correct option for the following reactions. (1) 'A' and 'B' are both Markovnikov addition (2) 'A' is Markovnikov product and 'B' is products. antiMarkovnikov product. (3) 'A' and 'B' are both anti-Markovnikov products. (4) 'B' is Markovnikov and 'A' is anti- Markovnikov product.
Q40.Two solutions A and B are prepared by dissolving 1 g of non-volatile solutes X and Y. respectively in 1 kg of water. The ratio of depression in freezing points for A and B is found to be 1 : 4. The ratio of molar masses of X and Y is (1) 1 : 4 (2) 1 : 0. 25 (3) 1 : 0. 20 (4) 1 : 5
Q40.In metallurgy the term "gangue" is used for (1) Contamination of undesired earthy materials. (2) Contamination of metals, other than desired metal (3) Minerals which are naturally occuring in pure (4) Magnetic impurities in an ore. form
Q40.Sulphur dioxide is one of the components of polluted air. SO2 is also a major contributor to acid rain. The correct and complete reaction to represent acid rain caused by SO2 is : (1) 2 SO2 + O2 →2 SO3 (2) SO2 + O3 →SO3 + O2 (3) SO2 + H2O2 →H2 SO4 (4) 2 SO2 + O2 + 2H2O →2H2 SO4 Q41. 42. 12% (w/v) solution of NaCl causes precipitation of a certain sol in 10 hours. The coagulating value of NaCl for the sol is [Given : Molar mass : Na = 23. 0 g mol−1; Cl = 35. 5 g mol−1 ] (1) 36 mmolL−1 (2) 36 mol L−1 (3) 1440 mol L−1 (4) 1440 m molL−1
Q40.Given below are two statements : Statement I: The pentavalent oxide of group- 15 element, E2O5 , is less acidic than trivalent oxide, E2O3 , of the same element. Statement II : The acidic character of trivalent oxide of group 15 elements, E2O3 , decreases down the group. In light of the above statements, choose most appropriate answer from the options given below (1) Both Statement I and Statement II are true. (2) Both Statement I and Statement II are false. (3) Statement I is false but statement II is true. (4) Statement I true, but statement II is false.
Q40.Match List - I with List - II. JEE Main 2022 (27 Jun Shift 1) JEE Main Previous Year Paper List-I List-II A Lyophilic colloid I Liquid-liquid colloid B Emulsion II Protective colloid C Positively charged colloid III FeCl3 + NaOH D Negatively charged colloid IV FeCl3+ hot water Choose the correct answer from the options given below (1) (A) −(II), (B) −(I), (C) −(IV), (D) −(III) (2) (A) −(III), (B) −(I), (C) −(IV), (D) −(II) (3) (A) −(II), (B) −(I), (C) −(III), (D) −(IV) (4) (A) −(III), (B) −(II), (C) −(I), (D) −(IV)
Q40.Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A : Dissolved substances can be removed from a colloidal solution by diffusion through a parchment paper. Reason R : Particles in a true solution cannot pass through parchment paper but the collodial particles can pass through the parchment paper. In the light of the above statements, choose the correct answer from the options given below (1) Both A and R are correct and R is the correct (2) Both A and R are correct but R is not the correct explanation of A explanation of A (3) A is correct but R is not correct (4) A is not correct but R is correct
Q40.White phosphorus reacts with thionyl chloride to give (1) PCl5, SO2 and S2 Cl2 (2) PCl3, SO2 and S2 Cl2 (3) PCl3, SO2 and Cl2 (4) PCl5, SO2 and Cl2
Q40.Incorrect statement for Tyndall effect is (1) The refractive indices of the dispersed phase and (2) The diameter of the dispersed particles is much the dispersion medium differ greatly in smaller than the wavelength of the light used. magnitude. (3) It is used to distinguish a true solution from a (4) During projection of movies in the cinemas hall, colloidal solution. Tyndall effect is noticed.
Q40.Match List-I with List-II List-I List-II (A) negatively charged sol (I) Fe2 O3 ⋅xH2 O (B) macromolecular colloid (II) CdS sol (C) positively charged sol (III) Starch (D) Cheese (IV) a gel Choose the correct answer from the options given below JEE Main 2022 (28 Jun Shift 2) JEE Main Previous Year Paper (1) (A) −(II), (B) −(III), (C) −(IV), (D) −(I) (2) (A) −(II), (B) −(I), (C) −(II), (D) −(IV) (3) (A) −(II), (B) −(III), (C) −(I), (D) −(IV) (4) (A) −(I), (B) −(III), (C) −(II), (D) −(IV)
Q40.Match List I with List II List-I List-II Pollutant Disease /sickness A Sulphate (> 500 ppm) I Methemoglobinemia B Nitrate (> 50 ppm) II Brown mottling of teeth C Lead (> 50 ppb) III Laxative effect D Fluoride (> 2 ppm) IV Kidney damage Choose the correct answer from the options given below (1) A −IV, B −I, C −II, D −III (2) A −III, B −I, C −IV, D −II (3) A −II, B −IV, C −I, D −III (4) A −II, B −IV, C −III, D −I
Q40.Identify the correct statement for the below given transformation. (1) A - CH3CH2CH = CH - CH3, (2) A - CH3CH2CH = CH - CH3, B - CH3CH2CH2CH = CH2, Saytzeff products B - CH3CH2CH2CH = CH2, Hafmann products (3) A - CH3CH2CH2CH = CH2, (4) A - CH3CH2CH2CH = CH2, B - CH3CH2CH = CHCH3, B - CH3CH2CH = CHCH3, Hofmann products Saytzeff products
Q41.Given below are the critical temperatures of some of the gases: Gas Critical temperature K He 5 . 2 CH4 190 CO2 304 . 2 NH3 405 . 5 The gas showing least adsorption on a definite amount of charcoal is (1) He (2) CH4 (3) CO2 (4) NH3
Q41.The correct order of melting points of hydrides of group 16 elements is (1) H2S < H2Se < H2Te < H2O (2) H2O < H2S < H2Se < H2 Te (3) H2S < H2Te < H2Se < H2O (4) H2Se < H2S < H2Te < H2O
Q41.Given below are two statements: one is labelled as Assertion and the other is labelled as Reason. Assertion: Flourine forms one oxoacid. Reason: Flourine has smallest size amongst all halogens and is highly electronegative. In the light of the above statements, choose the most appropriate answer from the Question: options given below. (1) Both assertion and reason are correct and reason is the correct explanation of assertion. (2) Both assertion and reason are correct and but reason is not the correct explanation of assertion. (3) Assertion is correct and reason is incorrect (4) Assertion is incorrect and reason is correct
Q41.Given below are the oxides : Na2 O, As2 O3, N2O, NO and Cl2 O7 Number of amphoteric oxides is : (1) 0 (2) 1 (3) 2 (4) 3
Q41.In the industrial production of which of the following, molecular hydrogen is obtained as a bye product. (1) Na2 CO3 (2) NaOH (3) Na metal (4) NaHCO3