Practice Questions
3,340 questions across 23 years of JEE Main β find and practise any topic!
Found 3,340 results
Q76.If y = y ( x ) is the solution curve of the differential equation x2 - 4dy - y2 - 3ydx = 0, x > 2, y(4) = 3 and 2 the slope of the curve is never zero, then the value of y ( 10 ) equals : 3 3 (1) 1 (2) 1 + 2β2 1 + ( 8 ) 4 3 3 (3) (4) 1 1 - 2β2 1 - ( 8 ) 4
Q76.A function y = f(x) satisfies f(x) sin 2x + sin x β(1 + cos2 x)f β²(x) = 0 with condition f(0) = 0. Then f( Ο2 ) is equal to (1) 1 (2) 0 (3) β1 (4) 2 β β β
Q76.If sin( xy ) = loge x + Ξ±2 is the solution of the differential equation x cos( xy ) dxdy = y cos( xy ) + x and y(1) = Ο3 , then Ξ±2 is equal to (1) 3 (2) 12 (3) 4 (4) 9 βββ
Q76.The area enclosed by the curves π₯π¦+ 4π¦= 16 and π₯+ π¦= 6 is equal to: (1) 28 β30logπ2 (2) 30 β28logπ2 (3) 30 β32logπ2 (4) 32 β30logπ2 2
Q76.Let πΌ be a non-zero real number. Suppose π: π βπ is a differentiable function such that π0 = 1 and π₯βββππ₯=lim 1. If π'π₯= πΌππ₯+ 3, for all π₯βπ , then πβlogπ2 is equal to ________. JEE Main 2024 (01 Feb Shift 2) JEE Main Previous Year Paper (1) 1 (2) 5 (3) 9 (4) 7
Q76.One of the points of intersection of the curves y = 1 + 3x β2x2 and y = x1 is ( 21 , 2). Let the area of the region enclosed by these curves be 1 (lβ5 + m) βn loge(1 + β5), where l, m, n βN. Then l + m + n is 24 equal to (1) 29 (2) 31 (3) 30 (4) 32
Q76.The area (in sq. units) of the region described by {(x, y) : y2 β€2x, and y β₯4x β1} is (1) 11 (2) 8 32 9 (3) 11 (4) 9 12 32
Q76.The integral β«Ο/40 3 sin136x+5sincosx x (1) 3Ο β50 loge 2 + 20 loge 5 (2) 3Ο β25 loge 2 + 10 loge 5 (3) 3Ο β10 loge(2β2) + 10 loge 5 (4) 3Ο β30 loge 2 + 20 loge 5
Q76.The differential equation of the family of circles passing through the origin and having centre at the line y = x is : (1) (x2 βy2 + 2xy)dx = (x2 βy2 β2xy)dy (2) (x2 + y2 + 2xy)dx = (x2 + y2 β2xy)dy (3) (x2 + y2 β2xy)dx = (x2 + y2 + 2xy)dy (4) (x2 βy2 + 2xy)dx = (x2 βy2 + 2xy)dy Ο
Q76.Let the area of the region enclosed by the curves y = 3x, 2y = 27 β3x and y = 3x βxβx be A . Then 10A is equal to (1) 172 (2) 162 (3) 154 (4) 184
Q77.Let βπ= ^π+ πΌ ^π+ π½ ^π , πΌ, π½βπ . Let a vector βπ be such that the angle between βπ and βπ is π and βπ = 6, If 4 βπΒ· βπ= 3β2, then the value of πΌ2 + π½2 | βπΓ βπ|2 is equal to (1) 90 (2) 75 (3) 95 (4) 85 2 is equal to
Q77.Let y = y(x) be the solution of the differential equation (1 + x2) dxdy + y = etanβ1 x , y(1) = 0. Then y(0) is (1) 2 1 (eΟ/2 β1) (2) 21 (1 βeΟ/2) (3) 4 1 (1 βeΟ/2) (4) 14 (eΟ/2 β1)
Q77.Consider three vectors βa,βb, βc. Let |βa| = 2, |βb| = 3 and βa = βb Γ βc. If Ξ± β[0, 3 ] is the angle between the vectors βb and βc, then the minimum value of 27|βc ββa|2 is equal to: (1) 110 (2) 124 (3) 121 (4) 105
Q77.Let three vectors βa = Ξ±^i + 4^j + 2^k, b = 5^i + 3^j + 4^k,βc= x^i + y^j + z^k form a triangle such that βc = βa ββb and the area of the triangle is 5β6. If Ξ± is a positive real number, then |βc|2 is equal to: (1) 16 (2) 14 (3) 12 (4) 10 β ββββ
Q77.Let βπ= 3 ^π+ ^πβ2 ^π, π= 4 ^π+ ^π+ 7 ^π and βπ= ^πβ3 ^π+ 4 ^π be three vectors. If a vectors βπ satisfies βπΓ βπ= βπΓ βπ and βπβ βπ= 0, then βπβ ^πβ ^πβ ^π is equal to (1) 24 (2) 36 (3) 28 (4) 32
Q77.Let βa = 2^i + ^j β^k, b = ((βaΓ (^i + ^j)) Γ^i) Γ^i. Then the square of the projection of βa on b is : (1) 1 (2) 2 3 3 (3) 2 (4) 1 5 β
Q77.Let βa = 4^i β^j + ^k,βb = 11^i β^j + ^k and βc be a vector such that (βa + βb) Γ βc = βc Γ (β2βa + 3βb). If (2βa + 3βb) β βc = 1670, then |βc|2 is equal to : (1) 1609 (2) 1618 (3) 1600 (4) 1627 β
Q77.The set of all Ξ±, for which the vectors βa = Ξ±t^i + 6^j β3^k and βb = t^i β2^j β2Ξ±t^k are inclined at an obtuse angle for all t βR, is (1) (β43 , 1) (2) [0, 1) (3) (β43 , 0] (4) (β2, 0] L1 : βr = (2 + Ξ»)^i + (1 β3Ξ»)^j + (3 + 4Ξ»)^k, Ξ» βR m
Q77.Let OAβ =βa, OBβ = 12βa+ 4βb and OCβ = βb, where O is the origin. If S is the parallelogram with adjacent sides OA and OC, then area of the areaquadrilateralof S OABC is equal to _____ (1) 6 (2) 10 (3) 7 (4) 8
Q77.Let x = x(t) and y = y(t) be solutions of the differential equations dxdt + ax = 0 and dydt + by = 0 respectively, a, b βR. Given that x(0) = 2 ; y(0) = 1 and 3 y(1) = 2 x(1), the value of t, for which x(t) = y(t), is : (1) log 2 2 (2) log4 3 3 4 2 (3) log3 4 (4) log 3 β β andβcbe the vector such that βaΓβc= b and βaβ βc= 3, then
Q77.The temperature ππ‘ of a body at time π‘= 0 is 160Β° πΉ and it decreases continuously as per the differential ππ equation ππ‘= βπΎπβ80, where πΎ is positive constant. If π15 = 120Β° πΉ, then π45 is equal to (1) 85Β° πΉ (2) 95Β° πΉ (3) 90Β° πΉ (4) 80Β° πΉ
Q77.If y = y(x) is the solution of the differential equation dydx + 2y = sin(2x), y(0) = 43 , then y ( Ο8 ) is equal to: JEE Main 2024 (05 Apr Shift 1) JEE Main Previous Year Paper (1) eΟ/8 (2) eΟ/4 (3) eβΟ/4 (4) eβΟ/8
Q77.Consider a π₯π΄π΅πΆ where π΄1, 3, 2, π΅β2, 8, 0 and πΆ3, 6, 7. If the angle bisector of β π΅π΄πΆ meets the line π΅πΆ at π·, then the length of the projection of the vector βπ΄π· on the vector βπ΄πΆ is: (1) 37 (2) β38 2β38 2 39 (3) (4) β19 2β38
Q77.Let A(2, 3, 5) and C(β3, 4, β2) be opposite vertices of a parallelogram ABCD if the diagonal ββ BD = Λi + 2Λj + 3Λk then the area of the parallelogram is equal to (1) 1 2 β410 (2) 21 β474 (3) 1 2 β586 (4) 21 β306 β β β
Q77.Let π¦= π¦π₯ be the solution of the differential equation ππ¦ 2π₯π₯+ π¦3 βπ₯π₯+ π¦β1, π¦0 = 1. Then, 1 + π¦1 ππ₯= β2 β2 equals: (1) 4 (2) 3 4 + βπ 3 ββπ 2 1 (3) (4) 1 + βπ 2 ββπ