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3,340 questions across 23 years of JEE Main β€” find and practise any topic!

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Q77.The position vectors of the vertices A, B and C of a triangle are 2 ^i - 3 ^j + 3 ^k, 2 ^i + 2 ^j + 3 ^k and - ^i + ^j + 3 ^k respectively. Let 𝑙 denotes the length of the angle bisector AD of ∠BAC where D is on the line segment BC, then 2𝑙2 equals : (1) 49 (2) 42 (3) 50 (4) 45

202427 Jan Shift 2Vectors
MathsMedium

Q78.Let β†’a = aiΛ†i + a2Λ†j + a3Λ†k and b = b1Λ†i + b2Λ†j + b3Λ†k be two vectors such that β†’a = 1;β†’aβ‹… b = 2 and b = 4. If Γ— βˆ’3b, then the angle between b and β†’cis equal to : β†’c= 2(β†’a β†’ β†’ β†’ b) JEE Main 2024 (30 Jan Shift 1) JEE Main Previous Year Paper (1) cosβˆ’1( √32 ) (2) cosβˆ’1(βˆ’1√3 ) 2 ) 3 (3) cosβˆ’1(βˆ’βˆš32 ) (4) cosβˆ’1(

202430 Jan Shift 1Vectors
MathsMedium

Q78.Let β†’a = ^i + ^j + ^k,β†’b = 2^i + 4^j βˆ’5^k and β†’c = x^i + 2^j + 3^k, x ∈R. If β†’d is the unit vector in the direction of β†’b + β†’c such that β†’a β‹…β†’d = 1, then (β†’a Γ— β†’b) β‹…β†’c is equal to (1) 11 (2) 3 (3) 9 (4) 6

202404 Apr Shift 2Vectors
MathsMedium

Q78.Let y = y(x) be the solution of the differential equation (2x loge x) dxdy + 2y = x3 loge x, x > 0 and y (eβˆ’1) = 0. Then, y(e) is equal to (1) βˆ’3e (2) βˆ’32e (3) βˆ’23e (4) βˆ’2e

202406 Apr Shift 1Differential Equations
MathsMedium

Q78.If the mirror image of the point 𝑃( 3, 4, 9 ) in the line π‘₯βˆ’1 = 𝑦+ 1 = π‘§βˆ’2 is 𝛼, 𝛽, 𝛾, then 14𝛼+ 𝛽+ 𝛾 is: 3 2 1 (1) 102 (2) 138 (3) 108 (4) 132 π‘₯+ 3 π‘¦βˆ’4 𝑧+ 1

202401 Feb Shift 23D Geometry
MathsMedium

Q78.If the shortest distance between the lines is √n L2 : β†’r = 2(1 + ΞΌ)^i + 3(1 + ΞΌ)^j + (5 + ΞΌ)^k, ΞΌ ∈R , where gcd(m, n) = 1, then the value of m + n equals (1) 390 (2) 384 (3) 377 (4) 387

202408 Apr Shift 1Vectors
MathsMedium

Q78.If β†’a = Λ†i + 2Λ†j + Λ†k, b = 3(Λ†i βˆ’Λ†j + Λ†k) is equal to Γ— βˆ’ b β†’aβ‹…((β†’c β†’ β†’ b) βˆ’β†’c) (1) 32 (2) 24 (3) 20 (4) 36

202427 Jan Shift 1Vectors
MathsMedium

Q78.Let OAβ†’ = 2β†’a, OB = 6β†’a + 5β†’b and OC = 3β†’b, where O is the origin. If the area of the parallelogram with βˆ’βˆ’β†’ β†’ adjacent sides OA and OC is 15 sq. units, then the area (in sq. units) of the quadrilateral OABC is equal to : (1) 32 (2) 40 (3) 38 (4) 35

202409 Apr Shift 1Vectors
MathsMedium

Q78.Let β†’a = 2^i + Ξ±^j + ^k,β†’b = βˆ’^i + ^k, β†’c = Ξ²^j βˆ’^k, where Ξ± and Ξ² are integers and Ξ±Ξ² = βˆ’6. Let the values of the √21 ordered pair (Ξ±, Ξ²), for which the area of the parallelogram of diagonals β†’a + β†’b and β†’b + β†’c is , be (Ξ±1, Ξ²1) 2 and (Ξ±2, Ξ²2). Then Ξ±21 + Ξ²21 βˆ’Ξ±2Ξ²2 is equal to (1) 19 (2) 17 (3) 24 (4) 21

202409 Apr Shift 2Vectors & 3D
MathsMedium

Q78.Let β†’a = 2^i + 5^j βˆ’^k,β†’b = 2^i βˆ’2^j + 2^k andβ†’cbe three vectors such that (β†’c +^i) Γ— (β†’a + β†’b +^i) = β†’a Γ— (β†’c +^i). If β†’a β‹…β†’c = βˆ’29, then β†’c β‹…(βˆ’2^i + ^j + ^k) is equal to: (1) 15 (2) 12 (3) 10 (4) 5

202405 Apr Shift 2Vectors
MathsMedium

Q78.Let O be the origin and the position vector of A and B be 2Λ†i + 2Λ†j + Λ†k and 2Λ†i + 4Λ†j + 4Λ†k respectively. If the internal bisector of ∠AOB meets the line AB at C , then the length of OC is (1) 3 2 √31 (2) 32 √34 (3) 3 4 √34 (4) 23 √31

202429 Jan Shift 1Differential Equations
MathsMedium

Q78.Let a unit vector which makes an angle of 60∘ with 2^i + 2^j βˆ’^k and angle 45∘ with ^i βˆ’^k be C. Then β†’ is : C + + (βˆ’12^i 1 ^j βˆ’βˆš23 ^k) 3√2 (1) √2 + βˆ’ + 3 + 21 )^i 1 )^j + √23 )^k ^i βˆ’12 ^k (2) ( √31 ( √31 3√2 ( √31 2√2 (3) √2 ^i + + 3 3√2 1 ^j βˆ’12 ^k (4) βˆ’βˆš23 ^i + √23 ^j + ( 21 3 )^k

202404 Apr Shift 1Vectors
MathsMedium

Q78.If the line 2βˆ’x 3 = 4Ξ»+13yβˆ’2 = 4 βˆ’z makes a right angle with the line x+33ΞΌ = 1βˆ’2y6 = 5βˆ’z7 , then 4Ξ» + 9ΞΌ is equal to : (1) 4 (2) 13 (3) 5 (4) 6

202405 Apr Shift 13D Geometry
MathsMedium

Q78.Let β†’a = ^i + 2^j + 3^k, b = 2^i + 3^j βˆ’5^k andβ†’c= 3^i βˆ’^j + Ξ»^k be three vectors. Letβ†’rbe anit vector along β†’b + β†’c. If β†’r β‹…β†’a = 3, then 3Ξ» is equal to: (1) 21 (2) 30 (3) 25 (4) 27

202408 Apr Shift 2Vectors
MathsMedium

Q78.Let 𝛼, 𝛽, 𝛾 be mirror image of the point 2, 3, 5 in the line π‘₯βˆ’1 = π‘¦βˆ’2 = π‘§βˆ’3 . Then 2𝛼+ 3𝛽+ 4𝛾 is equal to 2 3 4 (1) 32 (2) 33 (3) 31 (4) 34 π‘₯βˆ’1 𝑦+ 1 𝑧+ 4

202431 Jan Shift 23D Geometry
MathsMedium

Q78.The distance of the point 𝑄( 0, 2, – 2 ) form the line passing through the point 𝑃( 5, – 4, 3 ) and perpendicular to the lines β†’π‘Ÿ= βˆ’3 ^𝑖+ 2 ^π‘˜+ πœ†2 ^𝑖+ 3 ^𝑗+ 5 ^π‘˜, πœ†βˆˆβ„ and β†’π‘Ÿ= ^π‘–βˆ’2 ^𝑗+ ^π‘˜+ πœ‡βˆ’ ^𝑖+ 3 ^𝑗+ 2 ^π‘˜, πœ‡βˆˆβ„ is (1) √86 (2) √20 (3) √54 (4) √74

202431 Jan Shift 13D Geometry
MathsMedium

Q79.Let (Ξ±, Ξ², Ξ³) be the foot of perpendicular from the point (1, 2, 3) on the line x+35 = yβˆ’12 = z+43 . then 19(Ξ± + Ξ² + Ξ³) is equal to : (1) 102 (2) 101 (3) 99 (4) 100

202430 Jan Shift 13D Geometry
MathsMedium

Q79.Let P(x, y, z) be a point in the first octant, whose projection in the xy-plane is the point Q. Let OP = Ξ³ ; the angle between OQ and the positive x-axis be ΞΈ; and the angle between OP and the positive z-axis be Ο•, where O is the origin. Then the distance of P from the x-axis is ΞΈ cos2 Ο• (1) γ√1 βˆ’sin2 (2) Ο• cos2 ΞΈ γ√1 βˆ’sin2 ΞΈ sin2 Ο• (3) γ√1 + cos2 (4) Ο• sin2 ΞΈ γ√1 + cos2

202408 Apr Shift 13D Geometry
MathsMedium

Q79.Let the point, on the line passing through the points P(1, βˆ’2, 3) and Q(5, βˆ’4, 7), farther from the origin and at distance of 9 units from the point P, be (Ξ±, Ξ², Ξ³). Then Ξ±2 + Ξ²2 + Ξ³ 2 is equal to : (1) 165 (2) 160 (3) 155 (4) 150

202404 Apr Shift 13D Geometry
MathsMedium

Q79.Let 𝐿1: β†’π‘Ÿ= ^𝑖- ^𝑗+ 2 ^π‘˜+ πœ† ^𝑖- ^𝑗+ 2 ^π‘˜, πœ†βˆˆπ‘…, 𝐿2: β†’π‘Ÿ= ^𝑗- ^π‘˜+ πœ‡3 ^𝑖+ ^𝑗+ 𝑝 ^π‘˜, πœ‡βˆˆπ‘… and 𝐿3: β†’π‘Ÿ= 𝛿(𝑙 ^𝑖+ π‘š ^𝑗+ 𝑛 ^π‘˜), π›Ώβˆˆπ‘… be three lines such that 𝐿1 is perpendicular to 𝐿2 and 𝐿3 is perpendicular to both 𝐿1 and 𝐿2. Then the point which lies on 𝐿3 is (1) ( - 1, 7, 4 ) (2) ( - 1, - 7, 4 ) (3) ( 1, 7, - 4 ) (4) ( 1, - 7, 4 )

202430 Jan Shift 23D Geometry
MathsMedium

Q79.Let PQR be a triangle with R(βˆ’1, 4, 2). Suppose M(2, 1, 2) is the mid point of PQ . The distance of the centroid of Ξ”PQR from the point of intersection of the line xβˆ’20 = 2y = z+3βˆ’1 and xβˆ’11 = y+3βˆ’3 = z+11 is (1) 69 (2) 9 (3) √69 (4) √99

202429 Jan Shift 1Vectors
MathsMedium

Q79.The distance, of the point (7, βˆ’2, 11) from the line xβˆ’61 = yβˆ’40 = zβˆ’83 along the line xβˆ’52 = yβˆ’1βˆ’3 = zβˆ’56 , is : (1) 12 (2) 14 (3) 18 (4) 21

202427 Jan Shift 13D Geometry
MathsMedium

Q79.Consider the line L passing through the points (1, 2, 3) and (2, 3, 5). The distance of the point ( 113 , 113 , 193 ) from the line L along the line 3xβˆ’112 = 3yβˆ’111 = 3zβˆ’192 is equal to (1) 6 (2) 5 (3) 4 (4) 3

202409 Apr Shift 2Vectors
MathsMedium

Q79.If the shortest distance between the lines π‘₯βˆ’πœ† = π‘¦βˆ’2 = π‘§βˆ’1 and π‘₯βˆ’βˆš3 = π‘¦βˆ’1 = π‘§βˆ’2 is 1, then the sum of all βˆ’2 1 1 1 βˆ’2 1 possible values of πœ† is (1) 0 (2) 2√3 (3) 3√3 (4) βˆ’2√3

202401 Feb Shift 1Vectors
MathsMedium

Q79.The shortest distance between the lines xβˆ’3 2 = y+15βˆ’7 = zβˆ’95 and x+12 = yβˆ’11 = zβˆ’9βˆ’3 is (1) 8√3 (2) 4√3 (3) 5√3 (4) 6√3

202406 Apr Shift 13D Geometry
MathsMedium

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