Practice Questions
3,340 questions across 23 years of JEE Main β find and practise any topic!
Found 3,340 results
Q62.The complex number z = Οiβ1 Ο is equal to: cos 3 +i sin 3 (1) β2i(cos 5Ο12 βi sin 5Ο12 ) (2) cos 12Ο βi sin 12Ο (3) β2(cos 12Ο + i sin 12Ο ) (4) β2(cos 5Ο12 + i sin 5Ο12 )
Q62.For two non-zero complex number z1 and z2 , if Re (z1z2) = 0 and Re (z1 + z2) = 0, then which of the following are possible? (A) Im (z1) > 0 and Im (z2) > 0 (B) Im (z1) < 0 and Im (z2) > 0 (C) Im (z1) > 0 and Im (z2) < 0 (D) Im (z1) < 0 and Im (z2) < 0 Choose the correct answer from the options given below: (1) B and D (2) B and C (3) A and B (4) A and C
Q62.Let π€1 be the point obtained by the rotation of π§1 = 5 + 4π about the origin through a right angle in the anticlockwise direction, and π€2 be the point obtained by the rotation of π§2 = 3 + 5π about the origin through a right angle in the clockwise direction. Then the principal argument π€1 - π€2 is equal to (1) π- tan-18 (2) -π+ tan-133 9 5 (3) -π+ tan-18 (4) π- tan-133 9 5
Q62.Let z1 = 2 + 3i and z2 = 3 + 4i . The set S = {z βC : |z βz1|2 β|z βz2|2 = |z1 βz2|2} represents a (1) straight line with sum of its intercepts on the (2) hyperbola with the length of the transverse axis 7 coordinate axes equals 14 (3) straight line with the sum of its intercepts on the (4) hyperbola with eccentricity 2 coordinate axes equals β18
Q62.Let the first term a and the common ratio π of a geometric progression be positive integers. If the sum of squares of its first three terms is 33033, then the sum of these three terms is equal to (1) 241 (2) 231 (3) 210 (4) 220 1 13 1 13
Q62.The number of ways of selecting two numbers a and b, a β{2, 4, 6, β¦ β¦ , 100} and b β{1, 3, 5, β¦ β¦ , 99} such that 2 is the remainder when a + b is divided by 23 is (1) 186 (2) 54 (3) 108 (4) 268 JEE Main 2023 (30 Jan Shift 2) JEE Main Previous Year Paper
Q62.Let z be a complex number such that zβ2iz+i = 2, z β βi. Then z lies on the circle of radius 2 and centre (1) (2, 0) (2) (0, 2) (3) (0, 0) (4) (0, β2)
Q62.For all π§βπΆ on the curve πΆ1: | π§| = 4, let the locus of the point z + 1 be the curve πΆ2. Then z (1) the curves C1 and C2intersect at 4 points (2) the curves πΆ1 lies inside πΆ2 (3) the curves πΆ1 and πΆ2 intersect at 2 points (4) the curves πΆ2 lies inside πΆ1
Q62.Eight persons are to be transported from city A to city B in three cars of different makes. If each car can accommodate at most three persons, then the number of ways, in which they can be transported, is (1) 1120 (2) 3360 (3) 1680 (4) 560 1
Q62.If the center and radius of the circle = 2 are respectively πΌ, π½ and πΎ, then 3πΌ+ π½+ πΎ is equal to π§- 3 (1) 11 (2) 9 (3) 10 (4) 12
Q62.For a βC, let A = {z βC :Re (a + z) >Im (a + z)} and B = {z βC :Re (a + z) <Im (a + z)} . Then among the two statements: (S1) : If Re (a), Im (a) > 0, then the set A contains all the real numbers (S2) : If Re (a), Im (a) < 0, then the set B contains all the real numbers, (1) Only (S2) is true (2) only (S1) is true (3) Both are true (4) Both are false z2+8izβ15 : Ξ± β1311 i βS, Ξ± βR β{0}, then 242Ξ±2 is equal to
Q62.If ππ= 4π2 - 16π+ 15, then π1 + π2 + β¦ . + π25 is equal to: (1) 51 (2) 49 144 138 50 52 (3) (4) 141 147 1 15
Q62.If for z = Ξ± + iΞ², |z + 2| = z + 4(1 + i), then Ξ± + Ξ² and Ξ±Ξ² are the roots of the equation (1) x2 + 3x β4 = 0 (2) x2 + 7x + 12 = 0 (3) x2 + x β12 = 0 (4) x2 + 2x β3 = 0
Q62.Let C be the circle in the complex plane with centre z0 = 12 (1 + 3i) and radius r = 1. Let z1 = 1 + i and the complex number z2 be outside circle C such that |z1 βz0||z2 βz0| = 1 . If z0, z1 and z2 are collinear, then the smaller value of |z2|2 is equal to (1) 5 (2) 7 2 2 (3) 13 (4) 3 2 2
Q62.For Ξ±, Ξ², z βC and Ξ» > 1 , if βΞ» β1 is the radius of the circle |z βΞ±|2 + |z βΞ²|2 = 2Ξ», then |Ξ± βΞ²| is equal to _____.
Q62.Let A = {ΞΈ β(0, 2Ο) : 1+2i1βi sinsinΞΈΞΈ is purely imaginary} Then the sum of the elements is in A is (1) 4Ο (2) 3Ο (3) Ο (4) 2Ο
Q63.The number of integers, greater than 7000 that can be formed, using the digits 3, 5, 6, 7, 8 without repetition is (1) 120 (2) 168 (3) 220 (4) 48 13+23+33......upto n terms
Q63.The letters of the word OUGHT are written in all possible ways and these words are arranged as in a dictionary, in a series. Then the serial number of the word TOUGH is : (1) 89 (2) 84 (3) 86 (4) 79
Q63.Let S = {z βC β{i, 2i} z2β3izβ2 βR}. JEE Main 2023 (11 Apr Shift 2) JEE Main Previous Year Paper
Q63.The number of numbers, strictly between 5000 and 10000 can be formed using the digits 1, 3, 5, 7, 9 without repetition, is (1) 6 (2) 12 (3) 120 (4) 72
Q63.If the coefficient of π₯15 in the expansion of ππ₯3 + 1 is equal to the coefficient of π₯-15 in the expansion of ππ₯ 3 1 15 1 ππ₯ 3 - , where π and π are positive real numbers, then for each such ordered pair π, π: ππ₯3 (1) π= π (2) ππ= 1 (3) π= 3π (4) ππ= 3
Q63.Let s1, s2, s3. . . . , s10 respectively be the sum of 12 terms of 10 A. Ps whose first terms are 1, 2, 3, . . . . , 10 and the common differences are 1, 3, 5, . . . , 19 respectively. Then β10i=1 si is equal to (1) 7220 (2) 7360 (3) 7260 (4) 7380
Q63.Let π1, π2, π3, . . . . , ππ be n positive consecutive terms of an arithmetic progression. If π> 0 is its common difference, then lim π 1 + 1 + β¦ + 1 is πβββ π βπ1 + βπ2 βπ2 + βπ3 βππ- 1 + βππ (1) 1 (2) βπ βπ (3) 1 (4) 2 π
Q63.Let x and y be distinct integers where 1 β€x β€25 and 1 β€y β€25. Then, the number of ways of choosing x and y, such that x + y is divisible by 5 , is _____ .
Q63.If the sum and product of four positive consecutive terms of a G.P., are 126 and 1296, respectively, then the sum of common ratios of all such GPs is 9 (1) 7 (2) 2 (3) 3 (4) 14