Practice Questions

Q56.An organic compound ‘X’ showing the following solubility profile is: (1) m-Cresol (2) o-Toluidine (3) Oleic acid (4) Benzamide

Q57.What will be the major product when m-cresol is reacted with propargyl bromide (HC ≡C −CH2Br) in presence of K2CO3 in acetone? (1) (2) (3) (4)

Q57.The major product of the following reaction is: JEE Main 2019 (10 Apr Shift 1) JEE Main Previous Year Paper (1) (2) (3) CH3CH = CH −CH2NH2 (4)

Q57.The polymer obtained from the following reactions is (1) (2) (3) (4)

Q57.An aromatic compound ′A′ having molecular formula C7H6O2 , on treating with aqueous ammonia and heating forms compound ′B′. The compound ′B′ on reaction with molecular bromine and potassium hydroxide provides compound ′C′ having molecular formula C6H7N. The structure of ′A′ is: JEE Main 2019 (10 Jan Shift 2) JEE Main Previous Year Paper (1) (2) (3) (4)

Q57.A compound 'X' on treatment with Br /NaOH, provided C3H9 N, which gives positive carbylamine test. Compound X′ is: (1) CH3COCH2NHCH3 (2) CH3CH2COCH2NH2 (3) CH3CH2CH2CONH2 (4) CH3CON(CH3)2

Q57.The decreasing order of ease of alkaline hydrolysis for the following esters is (1) III > II > IV > I (2) III > II > I > IV (3) IV > II > III > I (4) II > III > I > IV

Q57.The major product Y in the following reaction is: (1) (2) (3) (4)

Q57.The major product obtained in the following reaction is: (1) (2) (3) (4)

Q57.The major product of the following reaction is: (1) (2) (3) (4)

Q57.In the following reaction HCl −Aldehyde + Alcohol → Acetal Aldehyde Alcohol HCHO t −BuOH CH3 CHO MeOH The best combination is: (1) HCHO and MeOH (2) CH3 CHO and t −BuOH (3) CH3 CHO and MeOH (4) HCHO and t- BuOH

Q57.The major product obtained in the following reaction is: (1) (2) (3) (4) JEE Main 2019 (09 Jan Shift 2) JEE Main Previous Year Paper

Q57.The major product of the following reaction is: JEE Main 2019 (09 Apr Shift 1) JEE Main Previous Year Paper (1) (2) (3) (4)

Q57.Acid strength given below the correct decreasing order will be : (1) NO2CH2COOH > FCH2COOH > CNCH2COOH > ClCH2COOH(2) NO2CH2COOH > NCCH2COOH > FCH2COOH > ClCH2COO (3) CNCH2COOH > O2NCH2COOH > FCH2COOH > (4)ClCH2COOHFCH2COOH > NCCH2COOH > NO2CH2COOH > ClCH2COO

Q58.The homopolymer formed from 4-hydroxy-butanoic acids is. (1) (2) (3) (4)

Q58.The increasing basicity order of the following compounds is: (1) (D) < (C) < (B) < (A) (2) (D) < (C) < (A) < (B) (3) (A) < (B) < (C) < (D) (4) (A) < (B) < (D) < (C)

Q58.Which of the following is not a correct method of the preparation of benzyl amine from cyano benzene? (1) H2 / Ni (2) (i) HCl / H2O (ii) NaBH4 (3) (i) SnCl2 + HClgas (ii) NaBH4 (4) (i) LiAlH4 (ii) H3O+

Q58.The increasing order of reactivity of the following compounds towards reaction with alkyl halides directly is: (i) (ii) (iii) (iv) (1) (i) < (ii) < (iii) < (iv) (2) (ii) < (i) < (iii) < (iv) (3) (ii) < (i) < (iv) < (iii) (4) (i) < (iii) < (iv) < (ii)

Q58.The major product of the following reaction is: LiAlH4 −CH3CH = CHCO2CH3 → (1) CH3CH2CH2CO2CH3 (2) CH3CH = CHCH2OH (3) CH3CH2CH2CH2OH (4) CH3CH2CH2CHO

Q58.The major product of the following reaction is: (1) (2) (3) (4)

Q58.Major product of the given below reaction: (1) (2) (3) (4)

Q58.Coupling of benzene diazonium chloride with 1 - naphthol in alkaline medium will give: (1) (2) (3) (4)

Q58.Ethylamine (C2H5NH2) can be obtained from N-ethylphthalimide on treatment with: (1) CaH2 (2) NH2NH2 (3) H2O (4) NaBH4

Q58.An organic compound ‘A’ is oxidized with Na2O2 followed by boiling with HNO3 . The resultant solution is then treated with ammonium molybdate to yield a yellow percipitate. Based on a above observation, the element present in the given compound is: (1) Fluorine (2) Phosphorus (3) Nitrogen (4) Sulphur

Q59.Aniline dissolved in dilute HCl is reacted with sodium nitrite at 0°C. This solution was added dropwise to a solution containing an equimolar mixture of aniline and phenol in dilute HCl . The structure of the major product is (1) (2) (3) (4)