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Practice Questions

3,340 questions across 23 years of JEE Main β€” find and practise any topic!

Found 3,340 results

Q12.For positive integers n, if 4an = (n2 + 5n + 6) and Sn = βˆ‘nk=1 ( ak1 ), then the value of (1) 540 (2) 675 (3) 1350 (4) 135

202528 Jan Shift 2Sequences & Series
MathsMedium

Q12.The area (in sq. units) of the region {(x, y) : 0 ≀y ≀2|x| + 1, 0 ≀y ≀x2 + 1, |x| ≀3} is (1) 80 (2) 64 3 3 (3) 32 (4) 17 3 3

202528 Jan Shift 1Definite Integration & Area
MathsMedium

Q12.Let β†’a = 3^i βˆ’^j + 2^k, b =β†’aΓ— (^i βˆ’2^k) andβ†’c= b Γ— ^k. Then the projection ofβ†’cβˆ’2^j on β†’a is : (1) 2√14 (2) √14 (3) 3√7 (4) 2√7

202524 Jan Shift 2Vectors
MathsMedium

Q12.Let A = {1, 2, 3, 4} and B = {1, 4, 9, 16}. Then the number of many-one functions f : A β†’B such that 1 ∈f( A) is equal to : (1) 151 (2) 139 (3) 163 (4) 127

202522 Jan Shift 2Sets Relations Functions
MathsMedium

Q12.Let |z1 βˆ’8 βˆ’2i| ≀1 and |z2 βˆ’2 + 6i| ≀2, z1, z2 ∈C . Then the minimum value of |z1 βˆ’z2| is : (1) 13 (2) 10 (3) 3 (4) 7

202529 Jan Shift 1Complex Numbers
MathsMedium

Q12.The remainder, when 7103 is divided by 23 , is equal to : (1) 6 (2) 17 (3) 9 (4) 14

202529 Jan Shift 2Sequences & Series
MathsMedium

Q12. (Ξ» βˆ’1)x + (Ξ» βˆ’4)y + Ξ»z = 5 If the system of equations Ξ»x + (Ξ» βˆ’1)y + (Ξ» βˆ’4)z = 7 has infinitely many solutions, then Ξ»2 + Ξ» is (Ξ» + 1)x + (Ξ» + 2)y βˆ’(Ξ» + 2)z = 9 equal to (1) 6 (2) 10 (3) 20 (4) 12

202523 Jan Shift 1Determinants
MathsMedium

Q13.A spherical chocolate ball has a layer of ice-cream of uniform thickness around it. When the thickness of the ice-cream layer is 1 cm , the ice-cream melts at the rate of 81 cm3/min and the thickness of the ice-cream layer decreases at the rate of 1 cm/min. The surface area (in cm2 ) of the chocolate ball (without the ice- 4Ο€ cream layer) is : (1) 196Ο€ (2) 256Ο€ (3) 225Ο€ (4) 128Ο€

202523 Jan Shift 2Applications of Derivatives
MathsMedium

Q13.The sum, of the squares of all the roots of the equation x2 + |2x βˆ’3| βˆ’4 = 0, is (1) 3(3 βˆ’βˆš2) (2) 6(3 βˆ’βˆš2) (3) 6(2 βˆ’βˆš2) (4) 3(2 βˆ’βˆš2)

202528 Jan Shift 1Quadratic Equations
MathsMedium

Q13. The number of real solution(s) of the equation x2 + 3x + 2 = min{|x βˆ’3|, |x + 2|} is : (1) 1 (2) 0 (3) 2 (4) 3

202524 Jan Shift 2Quadratic Equations
MathsMedium

Q13.Suppose that the number of terms in an A.P. is 2k, k ∈N . If the sum of all odd terms of the A.P. is 40 , the sum of all even terms is 55 and the last term of the A.P. exceeds the first term by 27, then k is equal to : (1) 6 (2) 5 (3) 8 (4) 4 y+2

202522 Jan Shift 2Sequences & Series
MathsMedium

Q13.The number of words, which can be formed using all the letters of the word "DAUGHTER", so that all the vowels never come together, is (1) 36000 (2) 37000 (3) 34000 (4) 35000

202523 Jan Shift 1Permutation & Combination
MathsMedium

Q13.If Ξ±x + Ξ²y = 109 is the equation of the chord of the ellipse x29 + y24 = 1 , whose mid point is ( 52 , 12 ), then Ξ± + Ξ² is equal to : (1) 58 (2) 46 (3) 37 (4) 72

202529 Jan Shift 2Ellipse
MathsMedium

Q14. The function f : (βˆ’βˆž, ∞) β†’(βˆ’βˆž, 1), defined by f(x) = 2xβˆ’2βˆ’x2x+2βˆ’x is : (1) Neither one-one nor onto (2) Onto but not one-one (3) Both one-one and onto (4) One-one but not onto

202524 Jan Shift 2Sets Relations Functions
MathsMedium

Q14.Let R = {(1, 2), (2, 3), (3, 3)} be a relation defined on the set {1, 2, 3, 4}. Then the minimum number of elements, needed to be added in R so that R becomes an equivalence relation, is: (1) 10 (2) 7 (3) 8 (4) 9

202523 Jan Shift 1Sets Relations Functions
MathsMedium

Q14.Let the foci of a hyperbola be (1, 14) and (1, βˆ’12). If it passes through the point (1, 6), then the length of its latus-rectum is : (1) 24 (2) 25 5 6 (3) 144 (4) 288 5 5 is equal to :

202522 Jan Shift 1Hyperbola
MathsMedium

Q14.The perpendicular distance, of the line xβˆ’1 2 = βˆ’1 = z+32 from the point P(2, βˆ’10, 1), is : (1) 6 (2) 5√2 (3) 4√3 (4) 3√5

202522 Jan Shift 23D Geometry
MathsMedium

Q14.The number of complex numbers z , satisfying |z| = 1 and zΒ―z + Β―zz = 1, is : (1) 4 (2) 8 (3) 10 (4) 6 Q15. ⎑ 0 ⎀ ⎑ 0 ⎀ ⎑4⎀ ⎑0⎀ ⎑2 ⎀ ⎑1 ⎀ Let A = [aij] be 3 Γ— 3 matrix such that A 1 = 0 , A 1 = 1 and A 1 = 0 , then a23 equals : ⎣ 0 ⎦ ⎣ 1 ⎦ ⎣3⎦ ⎣0⎦ ⎣2 ⎦ ⎣0 ⎦ (1) -1 (2) 2 (3) 1 (4) 0 2 x sin 2 dx equals : 3 3

202523 Jan Shift 2Complex Numbers
MathsMedium

Q14.Let Tr be the rth term of an A.P. If for some m, Tm = 251 , T25 = 201 , and 20 βˆ‘25r=1 Tr = 13, then 5 m βˆ‘2r=mm Tr is equal to (1) 98 (2) 126 (3) 142 (4) 112

202528 Jan Shift 1Sequences & Series
MathsMedium

Q15.Three defective oranges are accidently mixed with seven good ones and on looking at them, it is not possible to differentiate between them. Two oranges are drawn at random from the lot. If x denote the number of defective oranges, then the variance of x is (1) 28/75 (2) 18/25 (3) 26/75 (4) 14/25 x > 0 and f(2) = 3. Then f(6) is equal to

202528 Jan Shift 1Probability
MathsMedium

Q15. x + y + 2z = 6 If the system of linear equations : 2x + 3y + az = a + 1 where a, b ∈R, has infinitely many solutions, then βˆ’x βˆ’3y + bz = 2 b 7a + 3b is equal to : (1) 16 (2) 12 (3) 22 (4) 9 = 0, y ∈(βˆ’Ο€2 , Ο€2 ) with

202522 Jan Shift 2Matrices & Determinants
MathsMedium

Q15.Let a circle C pass through the points (4, 2) and (0, 2), and its centre lie on 3x + 2y + 2 = 0. Then the length of the chord, of the circle C , whose mid-point is (1, 2), is : (1) √3 (2) 2√2 (3) 2√3 (4) 4√2

202529 Jan Shift 2Circles
MathsMedium

Q15. A and B alternately throw a pair of dice. A wins if he throws a sum of 5 before B throws a sum of 8 , and B wins if he throws a sum of 8 before A throws a sum of 5 . The probability, that A wins if A makes the first throw, is (1) 8 (2) 9 17 19 (3) 9 (4) 8 17 19

202524 Jan Shift 1Definite Integration & Area
MathsMedium

Q15.Let ABC be a triangle formed by the lines 7x βˆ’6y + 3 = 0, x + 2y βˆ’31 = 0 and 9x βˆ’2y βˆ’19 = 0. Let the point (h, k) be the image of the centroid of Ξ”ABC in the line 3x + 6y βˆ’53 = 0. Then h2 + k2 + hk is equal to: (1) 47 (2) 37 (3) 36 (4) 40 is:

202529 Jan Shift 1Straight Lines
MathsMedium

Q15.If f(x) = ∫ 1 dx, f(0) = βˆ’6, then f(1) is equal to : x1/4(1+x1/4) (1) 4 (loge 2 βˆ’2) (2) 2 βˆ’loge2 2 (3) loge 2 + 2 (4) 4 (loge 2 + 2)

202528 Jan Shift 2Indefinite Integration
MathsMedium

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