Practice Questions

Q39.Solute A associates in water. When 0 . 7 g of solute A is dissolved in 42 . 0 g of water, it depresses the freezing point by 0 . 2 °C. The percentage association of solute A in water, is [Given: Molar mass of A = 93 g mol-1. Molal depression constant of water is 1 . 86 K kg mol-1] (1) 50% (2) 60% (3) 70% (4) 80%

Q39.Given below are two statements: Statement I: For KI, molar conductivity increases steeply with dilution. Statement II: For carbonic acid, molar conductivity increases slowly with dilution. In the light of the above statements, choose the correct answer from the options given below (1) Statement I is correct and Statement II is (2) Both Statement I and Statement II are false incorrect (3) Statement I is true but Statement II is false (4) Statement I is false but Statement II is true

Q39.Halogenation of which one of the following will yield m-substituted product with respect to methyl group as a major product? (1) (2) (3) (4)

Q39.Given below are two statements : Statement I : According to the Ellingham diagram, any metal oxide with higher ΔG° is more stable than the one with lower ΔG° . Statement II : The metal involved in the formation of oxide placed lower in the Ellingham diagram can reduce the oxide of a metal placed higher in the diagram. In the light of the above statements, choose the most appropriate answer from the options given below (1) Both Statement I and Statement II are correct. (2) Both Statement I and Statement II are incorrect. (3) Statement I is correct but Statement II is (4) Statement I is incorrect but Statement II is incorrect. correct.

Q39.A compound 'A' on reaction with 'X' and 'Y produces the same major product but different by product 'a' and 'b'. Oxidation of 'a' gives a substance produced by ants. JEE Main 2022 (25 Jul Shift 1) JEE Main Previous Year Paper ​ 'X' and 'Y' respectively are (1) KMnO4 / H+and dil. KMnO4, 273 K (2) KMnO4,(dilute), 273 K and KMnO4 / H+ (3) KMnO4 / H+ and O3, H2O / Zn (4) O3, H2O / Zn and KMnO4 / H+

Q40.Sulphur dioxide is one of the components of polluted air. SO2 is also a major contributor to acid rain. The correct and complete reaction to represent acid rain caused by SO2 is : (1) 2 SO2 + O2 →2 SO3 (2) SO2 + O3 →SO3 + O2 (3) SO2 + H2O2 →H2 SO4 (4) 2 SO2 + O2 + 2H2O →2H2 SO4 Q41. 42. 12% (w/v) solution of NaCl causes precipitation of a certain sol in 10 hours. The coagulating value of NaCl for the sol is [Given : Molar mass : Na = 23. 0 g mol−1; Cl = 35. 5 g mol−1 ] (1) 36 mmolL−1 (2) 36 mol L−1 (3) 1440 mol L−1 (4) 1440 m molL−1

Q40.Given below are two statements : Statement I: The pentavalent oxide of group- 15 element, E2O5 , is less acidic than trivalent oxide, E2O3 , of the same element. Statement II : The acidic character of trivalent oxide of group 15 elements, E2O3 , decreases down the group. In light of the above statements, choose most appropriate answer from the options given below (1) Both Statement I and Statement II are true. (2) Both Statement I and Statement II are false. (3) Statement I is false but statement II is true. (4) Statement I true, but statement II is false.

Q40.Match List - I with List - II. JEE Main 2022 (27 Jun Shift 1) JEE Main Previous Year Paper List-I List-II A Lyophilic colloid I Liquid-liquid colloid B Emulsion II Protective colloid C Positively charged colloid III FeCl3 + NaOH D Negatively charged colloid IV FeCl3+ hot water Choose the correct answer from the options given below (1) (A) −(II), (B) −(I), (C) −(IV), (D) −(III) (2) (A) −(III), (B) −(I), (C) −(IV), (D) −(II) (3) (A) −(II), (B) −(I), (C) −(III), (D) −(IV) (4) (A) −(III), (B) −(II), (C) −(I), (D) −(IV)

Q40.Two solutions A and B are prepared by dissolving 1 g of non-volatile solutes X and Y. respectively in 1 kg of water. The ratio of depression in freezing points for A and B is found to be 1 : 4. The ratio of molar masses of X and Y is (1) 1 : 4 (2) 1 : 0. 25 (3) 1 : 0. 20 (4) 1 : 5

Q40.Identify the correct statement for the below given transformation. (1) A - CH3CH2CH = CH - CH3, (2) A - CH3CH2CH = CH - CH3, B - CH3CH2CH2CH = CH2, Saytzeff products B - CH3CH2CH2CH = CH2, Hafmann products (3) A - CH3CH2CH2CH = CH2, (4) A - CH3CH2CH2CH = CH2, B - CH3CH2CH = CHCH3, B - CH3CH2CH = CHCH3, Hofmann products Saytzeff products

Q40.White phosphorus reacts with thionyl chloride to give (1) PCl5, SO2 and S2 Cl2 (2) PCl3, SO2 and S2 Cl2 (3) PCl3, SO2 and Cl2 (4) PCl5, SO2 and Cl2

Q40.Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A : Dissolved substances can be removed from a colloidal solution by diffusion through a parchment paper. Reason R : Particles in a true solution cannot pass through parchment paper but the collodial particles can pass through the parchment paper. In the light of the above statements, choose the correct answer from the options given below (1) Both A and R are correct and R is the correct (2) Both A and R are correct but R is not the correct explanation of A explanation of A (3) A is correct but R is not correct (4) A is not correct but R is correct

Q40.Match List-I with List-II List-I List-II (A) negatively charged sol (I) Fe2 O3 ⋅xH2 O (B) macromolecular colloid (II) CdS sol (C) positively charged sol (III) Starch (D) Cheese (IV) a gel Choose the correct answer from the options given below JEE Main 2022 (28 Jun Shift 2) JEE Main Previous Year Paper (1) (A) −(II), (B) −(III), (C) −(IV), (D) −(I) (2) (A) −(II), (B) −(I), (C) −(II), (D) −(IV) (3) (A) −(II), (B) −(III), (C) −(I), (D) −(IV) (4) (A) −(I), (B) −(III), (C) −(II), (D) −(IV)

Q40.Incorrect statement for Tyndall effect is (1) The refractive indices of the dispersed phase and (2) The diameter of the dispersed particles is much the dispersion medium differ greatly in smaller than the wavelength of the light used. magnitude. (3) It is used to distinguish a true solution from a (4) During projection of movies in the cinemas hall, colloidal solution. Tyndall effect is noticed.

Q40.In metallurgy the term "gangue" is used for (1) Contamination of undesired earthy materials. (2) Contamination of metals, other than desired metal (3) Minerals which are naturally occuring in pure (4) Magnetic impurities in an ore. form

Q40.Match List I with List II List-I List-II Pollutant Disease /sickness A Sulphate (> 500 ppm) I Methemoglobinemia B Nitrate (> 50 ppm) II Brown mottling of teeth C Lead (> 50 ppb) III Laxative effect D Fluoride (> 2 ppm) IV Kidney damage Choose the correct answer from the options given below (1) A −IV, B −I, C −II, D −III (2) A −III, B −I, C −IV, D −II (3) A −II, B −IV, C −I, D −III (4) A −II, B −IV, C −III, D −I

Q41.The molar conductivity of a conductivity cell filled with 10 moles of 20 mL NaCl solution is Λm1 and that of 20 moles another identical cell heaving 80 mL NaCl solution is Λm2 , The conductivities exhibited by these two cells are same. The relationship between Λm2 and Λm1 is (1) Λm2 = 2Λm1 (2) Λm2 = Λm1/2 (3) Λm2 = Λm1 (4) Λm2 = 4Λm1

Q41.Boiling point of a 2% aqueous solution of a nonvolatile solute A is equal to the boiling point of 8% aqueous solution of a non-volatile solute B . The relation between molecular weights of A and B is. JEE Main 2022 (27 Jul Shift 1) JEE Main Previous Year Paper (1) MA = 4MB (2) MB = 4MA (3) MA = 8MB (4) MB = 8MA

Q41.Concentrated HNO3 reacts with Iodine to give (1) HI, NO2 and H2O (2) HIO2, N2O and H2O (3) HIO3, NO2 and H2O (4) HIO4, N2O and H2O

Q41.Which of the following is a correct statement? (1) Brownian motion destabilises sols. (2) Any amount of dispersed phase can be added to emulsion without destabilising it. (3) Mixing two oppositely charged sols in equal (4) Presence of equal and similar charges on amount neutralises charges and stabilises colloidal particles provides stability to the colloids. colloidal solution.

Q41.Match List - I with List - II. List-I List-II A Concentration of gold ore I Aniline B Leaching of alumina II NaOH C Froth stabiliser III SO2 D Blister copper IV NaCN Choose the correct answer from the options given below. (1) (A) −(IV), (B) −(III), (C) −(II), (D) −(I) (2) (A) −(IV), (B) −(II), (C) −(I), (D) −(III) (3) (A) −(III), (B) −(II), (C) −(I), (D) −(IV) (4) (A) −(II), (B) −(IV), (C) −(III), (D) −(I)

Q41.Leaching of gold with dilute aqueous solution of NaCN in presence of oxygen gives complex A, which on reaction with zinc forms the elemental gold and another complex B. A and B, respectively are (1) AuCN2 - and ZnCN4 2 - (2) AuCN4 - and ZnCN2OH2 2 - (3) AuCN2 - and ZnOH4 2 - (4) AuCN4 2 - and ZnCN6 4 -

Q41.Given below are two statements: one is labelled as Assertion and the other is labelled as Reason. Assertion: Flourine forms one oxoacid. Reason: Flourine has smallest size amongst all halogens and is highly electronegative. In the light of the above statements, choose the most appropriate answer from the Question: options given below. (1) Both assertion and reason are correct and reason is the correct explanation of assertion. (2) Both assertion and reason are correct and but reason is not the correct explanation of assertion. (3) Assertion is correct and reason is incorrect (4) Assertion is incorrect and reason is correct

Q41.In neutral or alkaline solution, MnO−4 oxidises thiosulphate to (1) S2O2−7 (2) S2O2−8 (3) SO2−3 (4) SO2−4

Q41.Given below are the critical temperatures of some of the gases: Gas Critical temperature K He 5 . 2 CH4 190 CO2 304 . 2 NH3 405 . 5 The gas showing least adsorption on a definite amount of charcoal is (1) He (2) CH4 (3) CO2 (4) NH3