Practice Questions

Q59.The spin-only magnetic moment value of an octahedral complex among CoCl3 ⋅4 NH3 , NiCl2 ⋅6H2O and PtCl4 ⋅2 HCl, which upon reaction with excess of AgNO3 gives 2 moles of AgCl is_____B.M. (Nearest Integer)

Q59.Catalyst A reduces the activation energy for a reaction by 10 kJ mol−1 at 300 K . The ratio of rate constants, kT, Catalysed is ex . The value of x is____[nearest integer] [Assume that the pre-exponential factor is same in Uncatalysed kT, both the cases. Given R = 8. 31 J K−1 mol−1 ]

Q60.Total number of relatively more stable isomer(s) possible for octahedral complex Cuen2SCN2 will be____ 1

Q60. If the initial pressure of a gas is 0. 03 atm, the mass of the gas adsorbed per gram of the adsorbent is____ ×10−2 g

Q60.Acidified potassium permanganate solution oxidises oxalic acid. The spin-only magnetic moment of the mangenese product formed from the above reaction is B.M.___(Nearest Integer) ¯

Q60.How many of the following drugs is/are example(s) of broad spectrum antibiotic? Ofloxacin, Penicillin G, Terpineol, Salvarsan

Q60.Number of complexes which will exhibit synergic bonding amongst, [Cr (CO)6], [Mn (CO)5] and [Mn2 (CO)10] is

Q60.Among the following the number of curves not in accordance with Freundlich adsorption isotherm is |x+3|−1 ∈[−6, 3] −{−2, 2} : T = {x ∈Z : x2 −7|x| + 9 ≤0}. Then the number of

Q60.The difference between spin only magnetic moment values of [Co (H2O)6] Cl2 and [Cr (H2O)6] Cl3 is

Q60.In the given reaction, The number of π electrons present in the product ′P′ is ____________.

Q60.In a linear tetrapeptide (Constituted with different amino acids), (number of amino acids) - (number of peptide bonds) is ¯

Q60.In the given reaction (Where Et is -C2H5) The number of chiral carbon/s in product A is

Q60.If CuH2O4 2 + absorbs a light of wavelength 600 nm for d - d transition, then the value of octahedral crystal field splitting energy for CuH2O6 2 + will be____ × 10-21 J [Nearest integer] (Given : h = 6 . 63 × 10-34Js and c = 3 . 08 × 108 ms-1)

Q60.In the cobalt-carbonyl complex : [Co2 (CO)8], number of Co −Co bonds is " X" and terminal CO ligands is " Y ". X + Y =___

Q60. Zymase NaOI−−C6H12O6 → A → B + CHI3 Δ The number of carbon atoms present in the product B is JEE Main 2022 (29 Jun Shift 1) JEE Main Previous Year Paper

Q60.Optical activity of an enantiomeric mixture is +12. 6° and the specific rotation of (+) isomer is +30°. The optical purity is____ %

Q61.The total number of 5-digit numbers, formed by using the digits 1, 2, 3, 5, 6, 7 without repetition, which are multiple of 6, is (1) 72 (2) 48 (3) 24 (4) 60

Q61.Let O be the origin and A be the point z1 = 1 + 2i . If B is the point z2, Re (z2) < 0 , such that OAB is a right angled isosceles triangle with OB as hypotenuse, then which of the following is NOT true? (1) arg z2 = π −tan−1 3 (2) arg(z1 −2z2) = −tan−1 34 (3) |z2| = √10 (4) |2z1 −z2| = 5

Q61.Let α and β be the roots of the equation x2 + (2i −1) = 0 . Then, the value of α8 + β8 is equal to (1) 50 (2) 250 (3) 1250 (4) 1550

Q61.The area of the polygon, whose vertices are the non-real roots of the equation z = iz2 is (1) 3√3 (2) 3√3 2 4 (3) √3 (4) √3 4 2

Q61.Let S = {x |x|−2 ≥0} and elements in S ∩T is JEE Main 2022 (28 Jul Shift 2) JEE Main Previous Year Paper (1) 7 (2) 5 (3) 4 (4) 3

Q61.Let 𝑆1 = 𝑧1 ∈𝐶: 𝑧1 - 3 = 2 and 𝑆2 = 𝑧2 ∈𝐶: 𝑧2 - 𝑧2 + 1 = 𝑧2 + 𝑧2 - 1 . Then, for 𝑧1 ∈𝑆1 and 𝑧2 ∈𝑆2, the least value of 𝑧2 - 𝑧1 is (1) 0 (2) 1 2 3 5 (3) (4) 2 2

Q61.If α, β are the roots of the equation x2 −(5 + 3√log3 −5√log5 3)x 3(3(log3 −1) the equation, whose roots are α + β1 and β + α1 , (1) 3x2 −20x −12 = 0 (2) 3x2 −10x −4 = 0 (3) 3x2 −10x + 2 = 0 (4) 3x2 −20x + 16 = 0

Q62.Let S be the set of all (α, β), π < α, β < 2π, for which the complex number 1+2i1−i sinsinαα is purely imaginary and β 1+i cos is purely real. Let Zαβ = sin 2α + i cos 2β, (α, β) ∈S . β 1−2i cos 1 +¯ Then ∑(α,β)∈S(iZαβ iZ αβ ) is equal to (1) 3 (2) 3i (3) 1 (4) 2 −i

Q62.If x = ∑∞n=0 an, y = ∑∞n=0 bn, z = ∑∞n=0 cn , where a, b, c are in A.P. and |a| < 1, |b| < 1, |c| < 1, abc ≠0, then (1) x, y, z are in A.P. (2) x, y, z are in G.P. (3) x 1 , 1y , 1z are in A.P. (4) x1 + 1y + 1z = 1 −(a + b + c)