Practice Questions
10,171 questions across 23 years of JEE Main β find and practise any topic!
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Q76.Let y = y(x) be the solution of the differential equation sec xdy + {2(1 βx) tan x + x(2 βx)}dx = 0 such that y(0) = 2. Then y(2) is equal to : (1) 2 (2) 2{1 βsin(2)} (3) 2{sin(2) + 1} (4) 1
Q77.Let A(2, 3, 5) and C(β3, 4, β2) be opposite vertices of a parallelogram ABCD if the diagonal ββ BD = Λi + 2Λj + 3Λk then the area of the parallelogram is equal to (1) 1 2 β410 (2) 21 β474 (3) 1 2 β586 (4) 21 β306 β β β
Q77.The temperature ππ‘ of a body at time π‘= 0 is 160Β° πΉ and it decreases continuously as per the differential ππ equation ππ‘= βπΎπβ80, where πΎ is positive constant. If π15 = 120Β° πΉ, then π45 is equal to (1) 85Β° πΉ (2) 95Β° πΉ (3) 90Β° πΉ (4) 80Β° πΉ
Q77.Let βa = 4^i β^j + ^k,βb = 11^i β^j + ^k and βc be a vector such that (βa + βb) Γ βc = βc Γ (β2βa + 3βb). If (2βa + 3βb) β βc = 1670, then |βc|2 is equal to : (1) 1609 (2) 1618 (3) 1600 (4) 1627 β
Q77.The set of all Ξ±, for which the vectors βa = Ξ±t^i + 6^j β3^k and βb = t^i β2^j β2Ξ±t^k are inclined at an obtuse angle for all t βR, is (1) (β43 , 1) (2) [0, 1) (3) (β43 , 0] (4) (β2, 0] L1 : βr = (2 + Ξ»)^i + (1 β3Ξ»)^j + (3 + 4Ξ»)^k, Ξ» βR m
Q77.Let βa = 2^i + ^j β^k, b = ((βaΓ (^i + ^j)) Γ^i) Γ^i. Then the square of the projection of βa on b is : (1) 1 (2) 2 3 3 (3) 2 (4) 1 5 β
Q77.Let x = x(t) and y = y(t) be solutions of the differential equations dxdt + ax = 0 and dydt + by = 0 respectively, a, b βR. Given that x(0) = 2 ; y(0) = 1 and 3 y(1) = 2 x(1), the value of t, for which x(t) = y(t), is : (1) log 2 2 (2) log4 3 3 4 2 (3) log3 4 (4) log 3 β β andβcbe the vector such that βaΓβc= b and βaβ βc= 3, then
Q77.Let three vectors βa = Ξ±^i + 4^j + 2^k, b = 5^i + 3^j + 4^k,βc= x^i + y^j + z^k form a triangle such that βc = βa ββb and the area of the triangle is 5β6. If Ξ± is a positive real number, then |βc|2 is equal to: (1) 16 (2) 14 (3) 12 (4) 10 β ββββ
Q77.Consider a π₯π΄π΅πΆ where π΄1, 3, 2, π΅β2, 8, 0 and πΆ3, 6, 7. If the angle bisector of β π΅π΄πΆ meets the line π΅πΆ at π·, then the length of the projection of the vector βπ΄π· on the vector βπ΄πΆ is: (1) 37 (2) β38 2β38 2 39 (3) (4) β19 2β38
Q77.Let βπ= ^π+ πΌ ^π+ π½ ^π , πΌ, π½βπ . Let a vector βπ be such that the angle between βπ and βπ is π and βπ = 6, If 4 βπΒ· βπ= 3β2, then the value of πΌ2 + π½2 | βπΓ βπ|2 is equal to (1) 90 (2) 75 (3) 95 (4) 85 2 is equal to
Q77.Consider three vectors βa,βb, βc. Let |βa| = 2, |βb| = 3 and βa = βb Γ βc. If Ξ± β[0, 3 ] is the angle between the vectors βb and βc, then the minimum value of 27|βc ββa|2 is equal to: (1) 110 (2) 124 (3) 121 (4) 105
Q77.If y = y(x) is the solution of the differential equation dydx + 2y = sin(2x), y(0) = 43 , then y ( Ο8 ) is equal to: JEE Main 2024 (05 Apr Shift 1) JEE Main Previous Year Paper (1) eΟ/8 (2) eΟ/4 (3) eβΟ/4 (4) eβΟ/8
Q77.The position vectors of the vertices A, B and C of a triangle are 2 ^i - 3 ^j + 3 ^k, 2 ^i + 2 ^j + 3 ^k and - ^i + ^j + 3 ^k respectively. Let π denotes the length of the angle bisector AD of β BAC where D is on the line segment BC, then 2π2 equals : (1) 49 (2) 42 (3) 50 (4) 45
Q77.Let βπ= 3 ^π+ ^πβ2 ^π, π= 4 ^π+ ^π+ 7 ^π and βπ= ^πβ3 ^π+ 4 ^π be three vectors. If a vectors βπ satisfies βπΓ βπ= βπΓ βπ and βπβ βπ= 0, then βπβ ^πβ ^πβ ^π is equal to (1) 24 (2) 36 (3) 28 (4) 32
Q77.Let y = y(x) be the solution of the differential equation (1 + x2) dxdy + y = etanβ1 x , y(1) = 0. Then y(0) is (1) 2 1 (eΟ/2 β1) (2) 21 (1 βeΟ/2) (3) 4 1 (1 βeΟ/2) (4) 14 (eΟ/2 β1)
Q77.Let OAβ =βa, OBβ = 12βa+ 4βb and OCβ = βb, where O is the origin. If S is the parallelogram with adjacent sides OA and OC, then area of the areaquadrilateralof S OABC is equal to _____ (1) 6 (2) 10 (3) 7 (4) 8
Q77.Let π¦= π¦π₯ be the solution of the differential equation ππ¦ 2π₯π₯+ π¦3 βπ₯π₯+ π¦β1, π¦0 = 1. Then, 1 + π¦1 ππ₯= β2 β2 equals: (1) 4 (2) 3 4 + βπ 3 ββπ 2 1 (3) (4) 1 + βπ 2 ββπ
Q78.The distance of the point π( 0, 2, β 2 ) form the line passing through the point π( 5, β 4, 3 ) and perpendicular to the lines βπ= β3 ^π+ 2 ^π+ π2 ^π+ 3 ^π+ 5 ^π, πββ and βπ= ^πβ2 ^π+ ^π+ πβ ^π+ 3 ^π+ 2 ^π, πββ is (1) β86 (2) β20 (3) β54 (4) β74
Q78.If the mirror image of the point π( 3, 4, 9 ) in the line π₯β1 = π¦+ 1 = π§β2 is πΌ, π½, πΎ, then 14πΌ+ π½+ πΎ is: 3 2 1 (1) 102 (2) 138 (3) 108 (4) 132 π₯+ 3 π¦β4 π§+ 1
Q78.If βa = Λi + 2Λj + Λk, b = 3(Λi βΛj + Λk) is equal to Γ β b βaβ ((βc β β b) ββc) (1) 32 (2) 24 (3) 20 (4) 36
Q78.If the shortest distance between the lines is βn L2 : βr = 2(1 + ΞΌ)^i + 3(1 + ΞΌ)^j + (5 + ΞΌ)^k, ΞΌ βR , where gcd(m, n) = 1, then the value of m + n equals (1) 390 (2) 384 (3) 377 (4) 387
Q78.Let y = y(x) be the solution of the differential equation (2x loge x) dxdy + 2y = x3 loge x, x > 0 and y (eβ1) = 0. Then, y(e) is equal to (1) β3e (2) β32e (3) β23e (4) β2e
Q78.Let a unit vector which makes an angle of 60β with 2^i + 2^j β^k and angle 45β with ^i β^k be C. Then β is : C + + (β12^i 1 ^j ββ23 ^k) 3β2 (1) β2 + β + 3 + 21 )^i 1 )^j + β23 )^k ^i β12 ^k (2) ( β31 ( β31 3β2 ( β31 2β2 (3) β2 ^i + + 3 3β2 1 ^j β12 ^k (4) ββ23 ^i + β23 ^j + ( 21 3 )^k
Q78.Let βa = 2^i + 5^j β^k,βb = 2^i β2^j + 2^k andβcbe three vectors such that (βc +^i) Γ (βa + βb +^i) = βa Γ (βc +^i). If βa β βc = β29, then βc β (β2^i + ^j + ^k) is equal to: (1) 15 (2) 12 (3) 10 (4) 5
Q78.Let βa = aiΛi + a2Λj + a3Λk and b = b1Λi + b2Λj + b3Λk be two vectors such that βa = 1;βaβ b = 2 and b = 4. If Γ β3b, then the angle between b and βcis equal to : βc= 2(βa β β β b) JEE Main 2024 (30 Jan Shift 1) JEE Main Previous Year Paper (1) cosβ1( β32 ) (2) cosβ1(β1β3 ) 2 ) 3 (3) cosβ1(ββ32 ) (4) cosβ1(