Practice Questions
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Q90.Let y = y(x) be the solution of the differential equation x+2 ) + (y + = (x + 2)dy, y(1) = 1. If the domain of y = y(x) is an open interval (Ξ±, Ξ²), + 2)e( 1))dx ((x y+1 then |Ξ± + Ξ²| is equal to ___________. JEE Main 2021 (22 Jul Shift 1) JEE Main Previous Year Paper
Q90.A line l passing through origin is perpendicular to the lines l1 :βr= (3 + t)Λi + (β1 + 2t)Λj + (4 + 2t)Λk l2 :βr= (3 + 2s)Λi + (3 + 2s)Λj + (2 + s)Λk If the co-ordinates of the point in the first octant on l2 at a distance of β17 from the point of intersection of l and l1 are (a, b, c), then 18(a + b + c) is equal to ___ . JEE Main 2021 (25 Feb Shift 2) JEE Main Previous Year Paper
Q90.Let π΅ππ= 1, 2, 3 be three independent events in a sample space. The probability that only π΅1 occur is πΌ, only π΅2 occurs is π½ and only π΅3 occurs is πΎ. Let π be the probability that none of the events π΅π occurs and these 4 probabilities satisfy the equations πΌ- 2π½π= πΌπ½ and π½- 3πΎπ= 2π½πΎ (All the probabilities are assumed to lie in ππ΅1 the interval 0, 1 Then is equal to______. ππ΅3 JEE Main 2021 (24 Feb Shift 1) JEE Main Previous Year Paper
Q90.If the shortest distance between the lines r1 = Ξ±Λi + 2Λj + 2Λk + Ξ»(Λi β2Λj 2Λk), β ΞΌ βR is 9, then Ξ± is equal to_____. r2 = β4Λi βΛk + ΞΌ(3Λi β2Λj β2Λk), JEE Main 2021 (20 Jul Shift 1) JEE Main Previous Year Paper
Q51.If the equation x2 + bx + 45 = 0, b βR has conjugate complex roots and they satisfy |z + 1| = 2β10, then (1) b2 βb = 30 (2) b2 + b = 72 (3) b2 βb = 42 (4) b2 + b = 12
Q51.Let S , be the set of all real roots of the equation, 3x(3x β1) + 2 = |3x β1| + |3x β2|, then (1) contains exactly two elements. (2) is a singleton. (3) is an empty set. (4) contains at least four elements.
Q51.Let [t] denote the greatest integer β€t. Then the equation in x, [x]2 + 2[x + 2] β7 = 0 has : (1) exactly two solutions (2) exactly four integral solutions (3) no integral solution (4) infinitely many solutions
Q51.If Ξ± and Ξ² are the roots of the equation 2x(2x + 1) = 1, then Ξ² is equal to : (1) 2Ξ±(Ξ± + 1) (2) β2Ξ±(Ξ± + 1) (3) 2Ξ±(Ξ± β1) (4) 2Ξ±2
Q51.Let Ξ» β 0 be in R. If Ξ± and Ξ² are the roots of the equation, x2 βx + 2Ξ» = 0 and Ξ± and Ξ³ are the roots of the equation, 3x2 β10x + 27Ξ» = 0, then Ξ²Ξ³Ξ» is equal to: (1) 27 (2) 18 (3) 9 (4) 36 a + b is equal to:
Q51.If A = {x βR : |x| < 2} and B = {x βR : |x β2| β₯3}; then (1) A β©B = (β2, β1) (2) B βA = R β(β2, 5) (3) A βͺB = R β(2, 5) (4) A βB = [β1, 2)
Q51.The number of real roots of the equation, e4x + e3x β4e2x + ex + 1 = 0 is: (1) 1 (2) 3 (3) 2 (4) 4
Q51.Consider the two sets: A = {m βR : both the roots of x2 β(m + 1)x + m + 4 = 0 are real } and B = [β3, 5) Which of the following is not true? (1) A βB = (ββ, β3) βͺ(5, β) (2) A β©B = {β3} (3) B βA = (β3, 5) (4) A βͺB = R
Q51.If Ξ± and Ξ² are the roots of the equation, 7x2 β3x β2 = 0, then the value of Ξ± + Ξ² is equal to: 1βΞ±2 1βΞ²2 (1) 27 (2) 1 32 24 (3) 3 (4) 27 8 16
Q51.If Ξ± and Ξ² be two roots of the equation x2 β64x + 256 = 0. Then the value of 1 1 + ( Ξ²5 ) ( Ξ±5 ) JEE Main 2020 (06 Sep Shift 1) JEE Main Previous Year Paper (1) 2 (2) 3 (3) 1 (4) 4
Q51.Let Ξ± and Ξ² be the roots of the equation, 5x2 + 6x β2 = 0. If Sn = Ξ±n + Ξ²n, n = 1, 2, 3, . . . . , then (1) 6S6 + 5S5 = 2S4 (2) 5S6 + 6S5 + 2S4 = 0 (3) 5S6 + 6S5 = 2S4 (4) 6S6 + 5S5 + 2S4 = 0 1+sin 9 +i cos
Q51.The product of the roots of the equation 9x2 β18 x + 5 = 0 is : (1) 59 (2) 2581 (3) 275 (4) 259 Β―Β―
Q51.The set of all real values of Ξ» for which the quadratic equation (Ξ»2 + 1)x2 β4Ξ»x + 2 = 0 always have exactly one root in the interval (0, 1) is : (1) (β3, β1) (2) (0, 2) (3) (1, 3] (4) (2, 4]
Q51.Let f(x) be a quadratic polynomial such that f(β1) + f(2) = 0. If one of the roots of f(x) = 0 is 3 , then its other root lies in (1) (β1, 0) (2) (1, 3) (3) (β3, β1) (4) (0, 1) 1 1 2 2 +
Q51.Let Ξ± and Ξ² be two real roots of the equation (k + 1)tan2x ββ2 β Ξ» tan x = (1 βk), where k(β β1) and Ξ» are real numbers. If tan2(Ξ± + Ξ²) = 50, then a value of Ξ» is (1) 10β2 (2) 10 (3) 5 (4) 5β2
Q52.Let Ξ± = β1+iβ32 . If a = (1 + Ξ±) β100k=0 Ξ±2k and b = β100k=0 Ξ±3k , then a and b, are the roots of the quadratic equation. (1) x2 + 101x + 100 = 0 (2) x2 β102x + 101 = 0 (3) x2 β101x + 100 = 0 (4) x2 + 102x + 101 = 0
Q52.The value of 2Ο 2Ο 3 2Ο 2Ο ( 1+sin 9 βi cos 99 ) is (1) 1 (2) 1 2 (1 βiβ3) 2 (β3 βi) (3) β12 (β3 βi) (4) β12 (1 βiβ3)
Q52.If Re( 2z+izβ1 ) = 1, where z = x + iy, then the point (x, y) lies on a (1) circle whose centre is at (β12 , β32 ) (2) straight line whose slope is β23 (3) straight line whose slope is 3 2 (4) circle whose diameter is β52
Q52.If z1, z2 are complex numbers such that Re (z1) = |z1 β1| and Re (z2) = |z2 β1| and arg(z1 βz2) = Ο6 , then Im(z1 + z2) is equal to : (1) 2β3 (2) β3 2 (3) 1 (4) 2 β3 β3
Q52.Let z be a complex number such that z+2i zβi = 1 and |z| = 52 . Then, the value of |z + 3i| is (1) β10 (2) 72 (3) 15 (4) 2β3 4
Q52.If 3+isinΞΈ , ΞΈ β[0 ,2 Ο], is a real number, then an argument of sinΞΈ + icosΞΈ is 4βicosΞΈ (1) Ο βtanβ1( 34 ) (2) Ο βtanβ1( 43 ) (3) βtanβ1( 43 ) (4) tanβ1( 43 )