Practice Questions
4,685 questions across 23 years of JEE Main β find and practise any topic!
Found 4,685 results
Q57.The contrapositive of the statement "If I reach the station in time, then I will catch the train" is (1) If I do not reach the station in time, then I will (2) If do not reach the station in time, then I will not catch the train. catch the train. (3) If I will catch the train, then I reach the station in (4) If I will not catch the train, then I do not reach time. the station in time.
Q57.If one end of a focal chord AB of the parabola y2 = 8x is at A( 12 , β2), then the equation of the tangent to it at B is: (1) 2x + y β24 = 0 (2) x β2y + 8 = 0 (3) x + 2y + 8 = 0 (4) 2x βy β24 = 0
Q57.Let e1 and e2 be the eccentricities of the ellipse x225 + y2b2 = 1 (b < 5) and the hyperbola x216 βy2b2 respectively satisfying e1e2 = 1. If Ξ± and Ξ² are the distances between the foci of the ellipse and the foci of the hyperbola respectively, then the ordered pair (Ξ±, Ξ²) is equal to: (1) (8, 10) (2) ( 203 , 12) (3) (8, 12) (4) ( 245 , 10) JEE Main 2020 (03 Sep Shift 2) JEE Main Previous Year Paper
Q57.The set of all possible values of ΞΈ in the interval (0, Ο) for which the points (1, 2) and (sin ΞΈ, cos ΞΈ) lie on the same side of the line x + y = 1 is? (1) (0, Ο2 ) (2) ( Ο4 , 3Ο4 ) (3) (0, 3Ο4 ) (4) (0, Ο4 )
Q57.Which of the following statement is a tautology? (1) p β¨(~q) βp β§q (2) ~(p β§~q) βp β¨q (3) ~(p β¨~q) βp β§q (4) ~(p β¨~q) βp β¨q JEE Main 2020 (08 Jan Shift 2) JEE Main Previous Year Paper
Q57.If the point P on the curve, 4x2 + 5y2 = 20 is farthest from the point Q(0, β4), then PQ2 is equal to (1) 36 (2) 48 (3) 21 (4) 29
Q57.Let x2 a2 + b2 = 1(a > b) be a given ellipse, length of whose latus rectum is 10. If its eccentricity is the maximum value of the function, Ο(t) = 125 + t βt2 , then a2 + b2 is equal to : (1) 145 (2) 116 (3) 126 (4) 135
Q57.A hyperbola having the transverse axis of length, β2 has the same foci as that of the ellipse, 3x2 + 4y2 = 12 then this hyperbola does not pass through which of the following points? 2 , (1) ( β21 , 0) (2) (ββ3 1) (3) (1, β1β2 ) (4) (β3 2 , β21 )
Q57.Let L1 be a tangent to the parabola y2 = 4(x + 1) and L2 be a tangent to the parabola y2 = 8(x + 2) such that L1 and L2 intersect at right angles. Then L1 and L2 meet on the straight line: (1) x + 3 = 0 (2) 2x + 1 = 0 (3) x + 2 = 0 (4) x + 2y = 0
Q57.If the length of the chord of the circle, x2 + y2 = r2(r > 0) along the line, y β2x = 3 is r, then r2 is equal to: (1) 9 (2) 12 5 (3) 24 (4) 12 5 5 JEE Main 2020 (05 Sep Shift 2) JEE Main Previous Year Paper
Q57.Let the line y = mx and the ellipse 2x2 + y2 = 1 intersect at a point P in the first quadrant. If the normal to , (0, Ξ²), then Ξ² is equal to 0) and this ellipse at P meets the co-ordinate axes at (β 3β21 (1) 2β2 (2) 2 3 β3 (3) 2 (4) β2 3 3 JEE Main 2020 (08 Jan Shift 1) JEE Main Previous Year Paper Q58. 3x2+2 x21 lim is equal to xβ0 ( 7x2+2 ) (1) 1 (2) 1 e e2 (3) e2 (4) e
Q57.If the distance between the foci of an ellipse is 6 and the distance between its directrix is 12, then the length of its latus rectum is (1) β3 (2) 3β2 (3) 3 (4) 2β3 β2
Q57.If the normal at an end of latus rectum of an ellipse passes through an extremity of the minor axis, then the eccentricity e of the ellipse satisfies : (1) e4 + 2e2 β1 = 0 (2) e2 + e β1 = 0 (3) e4 + e2 β1 = 0 (4) e2 + 2e β1 = 0
Q57.The locus of the mid-points of the perpendiculars drawn from points on the line x = 2y, to the line x = y, is. (1) 2x β3y = 0 (2) 5x β7y = 0 (3) 3x β2y = 0 (4) 7x β5y = 0
Q57.Let x = 4 be a directrix to an ellipse whose centre is at the origin and its eccentricity is 12 . If P(1, Ξ²), Ξ² > 0 is a point on this ellipse, then the equation of the normal to it at P is JEE Main 2020 (04 Sep Shift 2) JEE Main Previous Year Paper (1) 4xβ3y = 2 (2) 8xβ2y = 5 (3) 7xβ4y = 1 (4) 4xβ2y = 1
Q58.Negation of the statement: β5 is an integer or 5 is irrational is: (1) β5 is not an integer 5 is not irrational (2) β5 is not an integer and 5 is not irrational (3) β5 is irrational or 5 is an integer (4) β5 is an integer and 5 irrational JEE Main 2020 (09 Jan Shift 1) JEE Main Previous Year Paper
Q58.Let X = {x βN : 1 β€x β€17} and Y = {ax + b : x βX and a, b βR, a > 0} . If mean and variance of elements of Y are 17 and 216 respectively then a + b is equal to (1) 7 (2) β7 (3) β27 (4) 9
Q58. (a+2x) 31 β(3x) 31 lim 1 1 (a β 0) is equal to: xβa (3a+x) 3 β(4x) 3 (1) 2 2 31 (2) 2 34 ( 9 )( 3 ) ( 3 ) (3) 2 34 (4) 2 2 31 ( 9 ) ( 3 )( 9 )
Q58.The area (in sq. units) of an equilateral triangle inscribed in the parabola y2 = 8x, with one of its vertices on the vertex of this parabola is (1) 64β3 (2) 256β3 (3) 192β3 (4) 128β3 JEE Main 2020 (02 Sep Shift 2) JEE Main Previous Year Paper
Q58.The length of the minor axis (along y-axis) of an ellipse in the standard form is 4 . If this ellipse touches the β3 line x + 6y = 8 then its eccentricity is: (1) 1 (2) 2 β113 β56 (3) 1 (4) 1 2 β53 3 β113
Q58.The mean and variance of 20 observations are found to be 10 and 4, respectively. On rechecking, it was found that an observation 9 was incorrect and the correct observation was 11, then the correct variance is (1) 3.99 (2) 4.01 (3) 4.02 (4) 3.98
Q58.If Ξ± is the positive root of the equation, p(x) = x2 βx β2 = 0, then lim β1βcosx+Ξ±β4p(x) is equal to xβΞ±+ (1) 23 (2) β23 (3) 1 (4) 12 β2
Q58.Consider the statement: "For an integer n, if n3 β1 is even, then n is odd". The contrapositive statement of this statement is: (1) For an integer n, if n is even, then n3 β1 is odd. (2) For an integer n, if n3 β1 is not even, then n is not odd. (3) For an integer n, if n is even, then n3 β1 is even.(4) For an integer n , if n is odd, then n3 β1 is even.
Q58.For two statements p and q , the logical statement (p βq) β§(q β~p) is equivalent to (1) p (2) q (3) ~p (4) ~q JEE Main 2020 (07 Jan Shift 1) JEE Main Previous Year Paper Q59. β‘ 1 1 1 β€ Let Ξ± be a root of the equation x2 + x + 1 = 0 and the matrix A = 1 1 Ξ± Ξ±2 , then the matrix A31 is β3 β£ 1 Ξ±2 Ξ±4 β¦ equal to (1) A3 (2) I3 (3) A2 (4) A
Q58.Let [t] denote the greatest integer β€t. If Ξ» Ξ΅ R β{0, 1}, lim 1βx+|x| = L, then L is equal to xβ0 Ξ»βx+[x] (1) 1 (2) 2 (3) 1 (4) 0 2