Practice Questions
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Q63.Let A = {n β[100, 700] β©N : n is neither a multiple of 3 nor a multiple of 4 }. Then the number of elements in A is (1) 290 (2) 280 (3) 300 (4) 310
Q64.If the coefficients of x4, x5 and x6 in the expansion of (1 + x)n are in the arithmetic progression, then the maximum value of n is: (1) 7 (2) 21 (3) 28 (4) 14
Q64.If the term independent of x in the expansion of (βax2 + 2x31 )10 is 105 , then a2 is equal to : (1) 2 (2) 4 (3) 6 (4) 9 JEE Main 2024 (08 Apr Shift 2) JEE Main Previous Year Paper cos 36β+5 sin 18β
Q64.For πΌ, π½β0, let 3sin ( πΌ+ π½) = 2sin ( πΌ- π½) and a real number π be such that tanπΌ= tanπ½. Then the 2 value of π is equal to (1) -5 (2) 5 (3) 2 (4) -2 3 3
Q64.Let |cos ΞΈ cos(60 βΞΈ) cos(60 + ΞΈ)| β€18 , ΞΈΟ΅[0, 2Ο]. Then, the sum of all ΞΈΟ΅[0, 2Ο], where cos 3ΞΈ attains its maximum value, is : (1) 15Ο (2) 18Ο (3) 6Ο (4) 9Ο
Q64.If 2tan2π- 5secπ= 1 has exactly 7 solutions in the interval 0, nπ , for the least value of n βN then n k is 2 βk = 1 2k equal to : - 15 (1) 2152141 - 14 (2) 2142151 15 1 (3) 1 - (4) - 15 213 213214
Q64.Let 3, π, π, π be in π΄. π. and 3, πβ1, π+ 1, π+ 9 be in πΊ. π. Then, the arithmetic mean of π, π and π is: (1) -4 (2) -1 (3) 13 (4) 11 1 βπ₯
Q64.Let ABC be an equilateral triangle. A new triangle is formed by joining the middle points of all sides of the triangle ABC and the same process is repeated infinitely many times. If P is the sum of perimeters and Q is be the sum of areas of all the triangles formed in this process, then : (1) P2 = 6β3Q (2) P2 = 36β3Q (3) P = 36β3Q2 (4) P2 = 72β3Q
Q64. nβ1Cr = (k2 β8)nCr+1 if and only if : (1) 2β2 < k β€3 (2) 2β3 < k β€3β2 (3) 2β3 < k < 3β3 (4) 2β2 < k < 2β3 JEE Main 2024 (27 Jan Shift 1) JEE Main Previous Year Paper
Q64.If each term of a geometric progression a1, a2, a3, β¦ with a1 = 18 and a2 β a1 , is the arithmetic mean of the next two terms and Sn = a1 + a2 + β¦ + an , then S20 βS18 is equal to (1) 215 (2) β218 (3) 218 (4) β215
Q64.Let the first three terms 2, p and q , with q β 2, of a G.P. be respectively the 7th , 8th and 13th terms of an A.P. If the 5th term of the G.P. is the nth term of the A.P., then n is equal to: (1) 163 (2) 151 (3) 177 (4) 169
Q64.The sum of the coefficient of x2/3 and xβ2/5 in the binomial expansion of (x2/3 + 12 xβ2/5) 9 (1) 21/4 (2) 63/16 (3) 19/4 (4) 69/16
Q64.If Ξ±, βΟ2 < Ξ± < Ο2 is the solution of 4 cos ΞΈ + 5 sin ΞΈ = 1, then the value of tan Ξ± is (1) 10ββ10 (2) 10ββ10 6 12 (3) β10β10 (4) β10β10 12 6
Q64.Let a variable line of slope m > 0 passing through the point (4, β9) intersect the coordinate axes at the points A and B. The minimum value of the sum of the distances of A and B from the origin is JEE Main 2024 (06 Apr Shift 1) JEE Main Previous Year Paper (1) 30 (2) 25 (3) 15 (4) 10
Q64.If sin x = β35 , where Ο < x < 3Ο2 , then 80 (tan2 x βcos x) is equal to (1) 108 (2) 109 (3) 18 (4) 19 JEE Main 2024 (08 Apr Shift 1) JEE Main Previous Year Paper
Q64.A line passing through the point A(9, 0) makes an angle of 30Β° with the positive direction of x-axis. If this line is rotated about A through an angle of 15Β° in the clockwise direction, then its equation in the new position is (1) y + x = 9 (2) x + y = 9 β3β2 β3β2 (3) x + y = 9 (4) y + x = 9 β3+2 β3+2
Q64.Let πΌ, π½, πΎ, πΏβπ and let π΄πΌ, π½, π΅1, 0, πΆπΎ, πΏ and π·1, 2 be the vertices of a parallelogram π΄π΅πΆπ·. If π΄π΅= β10 and the points π΄ and πΆ lie on the line 3π¦= 2π₯+ 1, then 2πΌ+ π½+ πΎ+ πΏ is equal to (1) 10 (2) 5 (3) 12 (4) 8
Q64.Let two straight lines drawn from the origin O intersect the line 3x + 4y = 12 at the points P and Q such that β³OPQ is an isosceles triangle and β POQ = 90β . If l = OP2 + PQ2 + QO2 , then the greatest integer less than or equal to l is : (1) 42 (2) 46 (3) 44 (4) 48
Q64.If the constant term in the expansion of 12 + , x β 0, is Ξ± Γ 28 Γ 5β3, then 25Ξ± is equal to : ( 5β3x 2x ) 3β5 (1) 724 (2) 742 (3) 639 (4) 693
Q64.Let π and π be the coefficients of seventh and thirteenth terms respectively in the expansion of 3 + 2 3π₯ 2π₯ 3 1 . Then π 3 is: π (1) 4 (2) 1 9 9 1 9 (3) (4) 4 4
Q64.Let 2nd, 8th and 44th, terms of a non-constant π΄. π. be respectively the 1st, 2nd and 3rd terms of πΊ. π. If the first term of A.P. is 1 then the sum of first 20 terms is equal to- (1) 980 (2) 960 (3) 990 (4) 970
Q65.Let C be a circle with radius β10 units and centre at the origin. Let the line x + y = 2 intersects the circle C at the points P and Q. Let MN be a chord of C of length 2 unit and slope -1. Then, a distance (in units) between the chord PQ and the chord MN is (1) 3 ββ2 (2) β2 + 1 (3) β2 β1 (4) 2 ββ3
Q65.If π₯2 - π¦2 + 2βπ₯π¦+ 2ππ₯+ 2ππ¦+ π= 0 is the locus of a point, which moves such that it is always equidistant from the lines π₯+ 2π¦+ 7 = 0 and 2π₯- π¦+ 8 = 0, then the value of π+ π+ β- π equals (1) 14 (2) 6 (3) 8 (4) 29
Q65.A ray of light coming from the point P(1, 2) gets reflected from the point Q on the x-axis and then passes through the point R(4, 3). If the point S(h, k) is such that PQRS is a parallelogram, then hk2 is equal to : (1) 70 (2) 80 (3) 60 (4) 90
Q65.If tanπ΄= 1 tanπ΅= and tanπΆ= π₯β3 + π₯β2 + π₯β1 2, 0 < π΄, π΅, πΆ< π then π΄+ π΅ is equal βπ₯π₯2 + π₯+ 1, βπ₯2 + π₯+ 1 2, to: (1) πΆ (2) πβπΆ (3) 2πβπΆ (4) π βπΆ 2 JEE Main 2024 (01 Feb Shift 1) JEE Main Previous Year Paper