Practice Questions
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Q63.The value of βπ=22 0 22πΆπΒ· 23πΆπ is (1) 45πΆ23 (2) 44πΆ23 (3) 45πΆ24 (4) 44πΆ22
Q63.Let S = {z βC β{i, 2i} z2β3izβ2 βR}. JEE Main 2023 (11 Apr Shift 2) JEE Main Previous Year Paper
Q63.The number of numbers, strictly between 5000 and 10000 can be formed using the digits 1, 3, 5, 7, 9 without repetition, is (1) 6 (2) 12 (3) 120 (4) 72
Q63.The number of arrangements of the letters of the word "INDEPENDENCE" in which all the vowels always occur together is (1) 16800 (2) 33600 (3) 18000 (4) 14800
Q63.Let a1, a2, a3, β¦ β¦. be an A.P. If a7 = 3, the product (a1a4) is minimum and the sum of its first n terms is zero then n! β4an(n+2) is equal to (1) 381 (2) 9 4 (3) 33 (4) 24 4
Q63.The sum to 10 terms of the series 1 2 3 + + + β¦ is :- 1 + 12 + 14 1 + 22 + 24 1 + 32 + 34 59 55 (1) (2) 111 111 (3) 56 (4) 58 111 111
Q63.All the letters of the word PUBLIC are written in all possible orders and these words are written as in a dictionary with serial numbers. Then the serial number of the word PUBLIC is (1) 576 (2) 578 (3) 580 (4) 582
Q63.The number of five-digit numbers, greater than 40000 and divisible by 5 , which can be formed using the digits 0, 1, 3, 5, 7 and 9 without repetition, is equal to (1) 132 (2) 120 (3) 72 (4) 96
Q63.Let s1, s2, s3. . . . , s10 respectively be the sum of 12 terms of 10 A. Ps whose first terms are 1, 2, 3, . . . . , 10 and the common differences are 1, 3, 5, . . . , 19 respectively. Then β10i=1 si is equal to (1) 7220 (2) 7360 (3) 7260 (4) 7380
Q63.If ππ= 4 + 11 + 21 + 34 + 50 + β¦ to π terms, then 60π29 - π9 is equal to (1) 223 (2) 226 (3) 220 (4) 227
Q63.Let π1, π2, π3, . . . . , ππ be n positive consecutive terms of an arithmetic progression. If π> 0 is its common difference, then lim π 1 + 1 + β¦ + 1 is πβββ π βπ1 + βπ2 βπ2 + βπ3 βππ- 1 + βππ (1) 1 (2) βπ βπ (3) 1 (4) 2 π
Q63.If the coefficient of π₯7 in ππ₯- and the coefficient of π₯-5 in ππ₯+ are equal, then π4π4 is equal to: ππ₯2 ππ₯2 (1) 11 (2) 44 (3) 22 (4) 33. π 2π 4π 8π 16π Q64.96 cos cos cos cos cos is equal to 33 33 33 33 33 (1) 3 (2) 1 (3) 4 (4) 2
Q63.The letters of the word OUGHT are written in all possible ways and these words are arranged as in a dictionary, in a series. Then the serial number of the word TOUGH is : (1) 89 (2) 84 (3) 86 (4) 79
Q63.The total number of three-digit numbers, divisible by 3, which can be formed using the digits 1, 3, 5, 8, if repetition of digits is allowed, is (1) 21 (2) 20 (3) 22 (4) 18
Q63.The number of integers, greater than 7000 that can be formed, using the digits 3, 5, 6, 7, 8 without repetition is (1) 120 (2) 168 (3) 220 (4) 48 13+23+33......upto n terms
Q63.If the coefficient of π₯15 in the expansion of ππ₯3 + 1 is equal to the coefficient of π₯-15 in the expansion of ππ₯ 3 1 15 1 ππ₯ 3 - , where π and π are positive real numbers, then for each such ordered pair π, π: ππ₯3 (1) π= π (2) ππ= 1 (3) π= 3π (4) ππ= 3
Q63.The number of triplets π₯, π¦, π§ where π₯, π¦, π§ are distinct non negative integers satisfying π₯+ π¦+ π§= 15, is (1) 80 (2) 136 (3) 114 (4) 92
Q63.If the number of words, with or without meaning. which can be made using all the letters of the word MATHEMATICS in which C and S do not come together, is (6!)k then k is equal to (1) 2835 (2) 5670 (3) 1890 (4) 945
Q63.If the sum and product of four positive consecutive terms of a G.P., are 126 and 1296, respectively, then the sum of common ratios of all such GPs is 9 (1) 7 (2) 2 (3) 3 (4) 14
Q64.Let π1, π2, π3, β¦ . be a G.P. of increasing positive numbers. Let the sum of its 6th and 8th terms be 2 and the + π4π4 + π6 is equal to product of its 3rd and 5th terms be 19. Then 6π2 (1) 3 (2) 3β3 (3) 2 (4) 2β2
Q64.Let a tangent to the curve π¦2 = 24π₯ meet the curve π₯π¦ = 2 at the points π΄ and π΅. Then the mid- points of such line segments π΄π΅ lie on a parabola with the (1) directrix 4π₯= 3 (2) directrix 4π₯= - 3 3 (3) Length of latus rectum (4) Length of latus rectum 2 2 Q65. 1 1 1 1 sin2π‘ π‘β01lim sin 2π‘+ 2 sin 2π‘+ 3 sin 2π‘. . . . . . π sin 2π‘ is equal to (1) π2 + π (2) π ππ+ 1 (3) (4) π2 2
Q64.If the letters of the word MATHS are permuted and all possible words so formed are arranged as in a dictionary with serial numbers, then the serial number of the word THAMS is (1) 103 (2) 102 (3) 101 (4) 104
Q64.Let a circle πΆ1 be obtained on rolling the circle π₯2 + π¦2 - 4π₯- 6π¦+ 11 = 0 upwards 4 units on the tangent T to it at the point 3, 2. Let πΆ2 be the image of πΆ1 in π. Let π΄ and π΅ be the centers of circles πΆ1 and πΆ2 respectively, and π and π be respectively the feet of perpendiculars drawn from π΄ and π΅ on the π₯-axis. Then the area of the trapezium AMNB is: (1) 22 + β2 (2) 41 + β2 (3) 3 + 2β2 (4) 21 + β2
Q64.The value of 1 1 1 1 1 + + + β¦ . + + is 1!50! 3!48! 5!46! 49!2! 51!1! (1) 250 (2) 250 50! 51! (3) 251 (4) 251 51! 50!
Q64.The number of ways, in which 5 girls and 7 boys can be seated at a round table so that no two girls sit together is (1) 720 (2) 126(5!)2 (3) 7(360)2 (4) 7(720)2