Practice Questions

Q51.In Hall-Heroult process, the following is used for reducing Al2 O3 :- (1) Magnesium (2) Na3 AlF6 (3) Graphite (4) CaF2

Q52. KMnO4 oxidises I− in acidic and neutral/faintly alkaline solution, respectively to (1) I2 and IO−3 (2) IO−3 and I2 (3) IO−3 and IO−3 (4) I2 and I2

Q52.The pair of lanthanides in which both elements have high third-ionization energy is: (1) Dy, Gd (2) Lu, Yb (3) Eu, Yb (4) Eu, Gd

Q52.Correct order of spin only magnetic moment of the following complex ions is: (Given At. No. Fe : 26, Co : 27 ) (1) [FeF6]3−> [CoF6]3−> [Co (C2O4)3]3− (2) [Co (C2O4)3]3−> [CoF6]3−> [FeF6]3− (3) [FeF6]3−> [Co (C2O4)3]3−> [CoF6]3− (4) [CoF6]3−> [FeF6]3−> [Co (C2O4)3]3−

Q52.Which halogen is known to cause the reaction given below? (1) All halogens (2) Only Bromine (3) Only Iodine (4) Only Chlorine

Q52.Which of the following cannot be explained by crystal field theory? (1) The order of spectrochemical series (2) Magnetic properties of transition metal complexes (3) Colour of metal complexes (4) Stability of metal complexes

Q52.Match List I with List II JEE Main 2023 (25 Jan Shift 2) JEE Main Previous Year Paper List I List II Coordination entity Wavelength of light absorbed in nm A [CoCl (NH3)5]2+ I. 310 B [Co (NH3)6]3+ II. 475 C [Co(CN)6]3− III. 535 D [Cu (H2O)4]2+ IV. 600 Choose the correct answer from the options given below :- (1) A −IV, B −I, C −III, D −II (2) A −III, B −II, C −I, D −IV (3) A −III, B −I, C −II, D −IV (4) A − II, B −III, C −IV, D −I

Q52.Which of the following elements have half-filled f-orbitals in their ground state ? (Given : atomic number Sm −62; Eu = 63; Tb = 65; Gd = 64, Pm = 61) Choose the correct answer from the options given below : (1) A and B only (2) C and D only (3) B and D only (4) A and E only

Q52.The incorrect statement regarding the reaction given below is (1) The product ‘ B’ formed in the above reaction is p (2) ‘ B’ is N-nitroso ammonium compound -nitroso compound at low temperature (3) The reaction occurs at low temperature (4) The electrophile involved in the reaction is NO+ JEE Main 2023 (12 Apr Shift 1) JEE Main Previous Year Paper

Q52.One mole of P4 reacts with 8 moles of SOCl2 to give 4 moles of A , x mole of SO2 and 2 moles of B . A, B and x respectively are (1) POCl3, S2 Cl2 and 2 (2) PCl3, S2 Cl2 and 4 (3) PCl3, S2 Cl2 and 2 (4) POCl3, S2 Cl2 and 4

Q53.Which of the following complex is octahedral, diamagnetic and the most stable? (1) Na3[CoCl6] (2) [Ni (NH3)6] Cl2 (3) K3[Co(CN)6] (4) [Co (H2O)6] Cl2

Q53.Match List I with List II: List I List II (Complexes) (Hybridisation) (A) [Ni(CO)4] I sp3 (B) [Cu (NH3)4]2+ II dsp2 (C) [Fe (NH3)6]2+ III sp3 d2 (D) [Fe (H2O)6]2+ IV d2 sp3 (1) A – II, B – I, C – III, D – IV (2) A – I, B – II, C – III, D – IV (3) A – II, B – I, C – IV, D – III (4) A – I, B– II, C – IV, D – III Q54. 1 L, 0. 02M solution of [Co (NH3)5 SO4] Br is mixed with 1 L, 0. 02M solution of [Co (NH3)5 Br] SO4 . The resulting solution is divided into two equal parts (X) and treated with excess AgNO3 solution and BaCl2 solution respectively as shown below: 1 L Solution (X) + AgNO3 solution (excess) →Y 1 L Solution (X) + BaCl2 solution (excess) →Z The number of moles of Y and Z respectively are (1) 0. 02, 0. 02 (2) 0. 01, 0. 01 (3) 0. 02, 0. 01 (4) 0. 01, 0. 02

Q53.In the cumene to phenol preparation in presence of air, the intermediate is (1) (2) (3) (4)

Q53.The hybridization and magnetic behaviour of cobalt ion in [Co(NH3)6]3+ complex, respectively is (1) sp3 d2 and diamagnetic (2) d2 sp3 and paramagnetic (3) d2 sp3 and diamagnetic (4) sp3 d2 and paramagnetic

Q53.Which element is not present in Nessler’s reagent? (1) Mercury (2) Potassium (3) Iodine (4) Oxygen

Q53.The mismatched combinations are A. Chlorophyll – Co B. Water hardness – EDTA C. Photography −[Ag(CN)2]− D. Wilkinson catalyst −[(Ph3 P)3 RhCl] E. Chelating ligand –D−Penicillamine Choose the correct answer from the options given below. (1) A, C and E only (2) A and C only (3) A and E only (4) D and E only Q54. 2−Methyl propyl bromide reacts with C2H5O− and gives ‵A′ whereas on reaction with C2H5 OH it gives ‵B′. The mechanism followed in these reactions and the products ‵A′ and ‵B′ respectively are: (1) SN2, A =iso-butyl ethyl ether; SN1, B =tert-butyl (2) SN1, A =tert-butyl ethyl ether; SN1, B = 2− ethyl ether butyl ethyl ether (3) SN2, A = 2−butyl ethyl ether; SN2, B =iso- (4) SN1, A =tert-butyl ethyl ether; SN2, B =iso- butyl ethyl ether butyl ethyl ether

Q53.Chiral complex from the following is : Here en = ethylene diamine (1) cis −[PtCl2(en)2]2+ (2) trans −[PtCl2(en)2]2+ (3) cis −[PtCl2 (NH3)2] (4) trans −[Co (NH3)4 Cl2]+

Q53.Match List I with List II List I Complex List II CFSE (Δ0) A. [Cu(NH3)6]2+ I. −0. 6 B. [Ti(H2O)6]3+ II. −2. 0 C. [Fe(CN)6]3− III. −1. 2 D. [NiF6]4− IV. −0. 4 Choose the correct answer from the options given below: (1) A(III), B(IV), C(I), D(II) (2) A(I), B(IV), C(II), D(III) (3) A(I), B(II), C(IV), D(III) (4) A(II), B(III), C(I), D(IV)

Q53.Match List-I with List-II LIST-I LIST-II Coordination Number of unpaired electrons Complex A. [Cr(CN)6]3− I. 0 B. [Fe (H2O)6]2+ II. 3 C. [Co (NH3)6]3+ III. 2 JEE Main 2023 (08 Apr Shift 2) JEE Main Previous Year Paper D. [Ni (NH3)6]2+ IV. 4 Choose the correct answer from the options given below: (1) A-II, B-IV, C-I, D-III (2) A-III, B-IV, C-I, D-II (3) A-II, B-I, C-IV, D-III (4) A-IV, B-III, C-II, D-I

Q53.If Ni2+ is replaced by Pt2+ in the complex [NiCl2 Br2]2− , which of the following properties are expected to get changed? A. Geometry B. Geometrical isomerism C. Optical isomerism D. Magnetic properties (1) A and D (2) A, B and C (3) B and C (4) A, B and D

Q53.Element not present in Nessler’s reagent is (1) N (2) Hg (3) I (4) K

Q54.Match List I with List II LIST-I LIST-II Complex Colour JEE Main 2023 (11 Apr Shift 2) JEE Main Previous Year Paper A. Mg(NH4) PO4 I. brown B. K3[Co (NO2)6] II. white C. MnO (OH)2 III. yellow D. Fe4 [Fe (CN)6]3 IV. blue Choose the correct answer from the options given below: (1) A-III, B-IV, C-II, D-I (2) A-II, B-III, C-I, D-IV (3) A-II, B-IV, C-I, D-III (4) A-II, B-III, C-IV, D-I

Q54.The correct order of spin only magnetic moments for the following complex ions is (1) [Fe(CN)6]3−< [CoF6]3−< [MnBr4]2−< [Mn(CN)6]3−(2) [CoF6]3−< [MnBr4]2−< [Fe(CN)6]3−< [Mn(CN)6]3− (3) [Fe(CN)6]3−< [Mn(CN)6]3−< [CoF6]3−< [MnBr4]2−(4) [MnBr4]2−< [CoF6]3−< [Fe(CN)6]3−< [Mn(CN)6]3−

Q54.Find out the major product from the following reaction. (1) (2) (3) (4) Q55.' A ' in the given reaction is JEE Main 2023 (25 Jan Shift 2) JEE Main Previous Year Paper (1) (2) (3) (4)

Q54.The complex cation which has two isomers is: (1) [Co (H2O)6]3+ (2) [Co (NH3)5 Cl]2+ (3) [Co (NH3)5 NO2]2+ (4) [Co (NH3)5 Cl]+