Practice Questions

Q59.Match List I with List II List I List II (Example) (Type) A 2-chloro- 1, 3-butadiene I Biodegradable polymer B Nylon 2-nylon 6 II Synthetic Rubber C Polyacrylonitrile III Polyester D Dacron IV Addition Polymer Choose the correct answer from the options given below: (1) A(II), B(IV), C(I), D(III) (2) A(II), B(I), C(IV), D(III) (3) A(IV), B(I), C(III), D(II) (4) A(IV), B(III), C(I), D(II)

Q59.A doctor prescribed the drug Equanil to a patient. The patient was likely to have symptoms of which disease? (1) Stomach ulcers (2) Hyperacidity (3) Anxiety and stress (4) Depression and hypertension

Q60.Match the following Column −A Column −B a. Nylon 6 I. Natural Rubber b. Vulcanized Rubber II. Cross Linked c. cis −1, 4−polyisoprene III. Caprolactam d. Polychloroprene IV. Neoprene Choose the correct answer from options given below: (1) a →III, b →II, c →I, d →IV (2) a →III, b →IV, c →I, d →II (3) a →IV, b →III, c →II, d →I (4) a →II, b →III, c →IV, d →I ¯

Q60.Following tetrapeptide can be represented as JEE Main 2023 (29 Jan Shift 2) JEE Main Previous Year Paper ( F, L, D, Y, I, Q, P are one letter codes for amino acids) (1) FIQY (2) FLDY (3) YQLF (4) PLDY

Q60.Compound A, C5H10O5 , given a tetraacetate with AC2 O and oxidation of A with Br2 −H2O gives an acid, C5H10O6 . Reduction of A with HI gives isopentane. The possible structure of A is : JEE Main 2023 (31 Jan Shift 2) JEE Main Previous Year Paper (1) (2) (3) (4)

Q60.Match List-I with List-II. List-I List-II Natural Amino One Letter acid Code (A) Arginine (I) D (B) Aspartic acid (II) N (C) Asparagine (III) A (D) Alanine (IV) R Choose the correct answer from the options given below: JEE Main 2023 (06 Apr Shift 2) JEE Main Previous Year Paper (1) (A)–IV, B–I, (C)–II, (D)–III (2) (A)–I, B–III, (C)–IV, (D)–II (3) (A)–III, B–I, (C)–II, (D)–IV (4) (A)–IV, B–I, (C)–III, (D)–II

Q60.Sulphur (S) containing amino acids from the following are: (a) isoleucine (b) cysteine (c) lysine (d) methionine (e) glutamic acid (1) b, c, e (2) a, b, c (3) b, d (4) a, d

Q60.Match List I with List II List II List I One Letter Natural amino acid Code (A) Glutamic acid (I) Q (B) Glutamine (II) W (C) Tyrosine (III) E JEE Main 2023 (08 Apr Shift 2) JEE Main Previous Year Paper (D) Tryptophan (IV) Y Choose the correct answer from the options given below: (1) (A)-III, B-IV, (C)-I, (D)-II (2) (A)-IV, B-III, (C)-I, (D)-II (3) (A)-III, B-I, (C)-IV, (D)-II (4) (A)-II, B-I, (C)-IV, (D)-III

Q60.A. Ammonium salts produce haze in atmosphere. B. Ozone gets produced when atmospheric oxygen reacts with chlorine radicals. C. Polychlorinated biphenyls act as cleansing solvents. D. ‘Blue baby’ syndrome occurs due to the presence of excess of sulphate ions in water. JEE Main 2023 (25 Jan Shift 2) JEE Main Previous Year Paper Choose the correct answer from the options given below:- (1) A, B and C only (2) B and C only (3) A and D only (4) A and C only

Q31.Which of the following pair is not isoelectronic species? (Atomic numbers Sm = 62; Er = 68; Yb = 70; Lu = 71; Eu = 63; Tb = 65; Tm= 69 ) (1) Sm2+ and Er3+ (2) Yb2+ and Lu3+ (3) Eu2+ and Tb4+ (4) Tb2+ and Tm4+

Q31.The pair, in which ions are isoelectronic with Al3 + is (1) Br- and Be2 + (2) Cl- and Li+ (3) S2 - and K+ (4) O2 - and Mg2 +

Q31.A commercially sold conc. HCl is 35% HCl by mass. If the density of this commercial acid is 1. 46 g/ mL , the molarity of this solution is : (Atomic mass : Cl = 35. 5 amu, H = 1 amu ) (1) 10. 2 M (2) 14. 0 M (3) 12. 5 M (4) 18. 2 M

Q31.The correct order of ionic size of N3−, Na+, F−, Mg2+ and O2− is : (1) Mg2+ < Na+ < F−< O2−< N3− (2) N3−< O2−< F < Na+ < Mg2+ (3) F−< Na+ < O2−< Mg2+ < N3− (4) Na+ < F−< Mg2+ < O2−< N3−

Q31.SO2Cl2 on reaction with excess of water results into acidic mixture SO2Cl2 + 2H2O →H2SO4 + 2HCl 16 moles of NaOH is required for the complete neutralisation of the resultant acidic mixture. The number of moles of SO2Cl2 used is (1) 16 (2) 8 (3) 4 (4) 2

Q31.The first ionization enthalpies of Be, B, N and O follow the order (1) B < Be < O < N (2) O < N < B < Be (3) Be < B < N < O (4) B < Be < N < O JEE Main 2022 (25 Jul Shift 2) JEE Main Previous Year Paper

Q31.Production of iron in blast furnace follows the following equation Fe3 O4(s) + 4 CO(g) →3 Fe(l) + 4 CO2(g) when 4. 640 kg of Fe3 O4 and 2. 520 kg of CO are allowed to react then the amount of iror (in g) produced is : [Given: Molar Atomic mass (gmol−1) : Fe = 56 Molar Atomic mass (gmolm−1) : O = 16 Molar Atomic mass (gmolm−1) : C = 12] (1) 1400 (2) 2200 (3) 3360 (4) 4200

Q31.Compound A contains 8. 7% Hydrogen, 74% Carbon and 17. 3% Nitrogen. The molecular formula of the compound is, Given : Atomic masses of C, H and N are 12, 1 and 14 amu respectively. The molar mass of the compound A is 162 g mol−1 . (1) C4H6N2 (2) C2H3N (3) C5H7N (4) C10H14N2

Q31.Consider the reaction 4HNO3l + 3KCls →Cl2g + NOClg + 2H2Og + 3KNO3s The amount of HNO3 required to produce110 . 0 g of KNO3 is (Given : Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively.) (1) 32 . 2 g (2) 69 . 4 g (3) 91 . 5 g (4) 162 . 5 g

Q31.The correct decreasing order of energy, for the orbitals having, following set of quantum numbers: (A) n = 3, 1 = 0, m = 0 (B) n = 4, l = 0, m = 0 (C) n = 3, l = 1, m = 0 (D) n = 3, 1 = 2, m = 1 (1) (D) > (B) > (C) > (A) (2) (B) > (D) > (C) > (A) (3) (C) > (B) > (D) > (A) (4) (B) > (C) > (D) > (A)

Q31.Using the rules for significant figures, the correct answer for the expression 0.02858×0.112 will be: 0.5702 (1) 0. 005613 (2) 0. 00561 (3) 0. 0056 (4) 0. 006

Q31.If a rocket runs on a fuel (C15H30) and liquid oxygen, the weight of oxygen required and CO2 released for every litre of fuel respectively are : (Given : density of the fuel is 0. 756 g/ mL ) (1) 1188 g and 1296 g (2) 2376 g and 2592 g (3) 2592 g and 2376 g (4) 3429 g and 3142 g

Q31.Element " E" belongs to the period 4 and group 16 of the periodic table. The valence shell electron configuration of the element, which is just above " E" in the group is (1) 2s22p4 (2) 3d10, 4s2, 4p4 (3) 3s23p4 (4) 4d10, 5s2, 5p4

Q31.The number of radial and angular nodes in 4 d orbital are, respectively (1) 1 & 2 (2) 3 & 2 (3) 1 & 0 (4) 2 & 1

Q31. N2(g) + 3H2(g) ⇌2 NH3(g) 20 g 5 g Consider the above reaction. If 20g of dinitrogen reacts with 5g of dihydrogen, then the limiting reagent of the reaction and number of moles of NH3 formed respectively are (1) H2, 1. 42 moles (2) H2, 0. 71 moles (3) N2, 1. 42 moles (4) N2, 0. 71 moles

Q31.Hemoglobin contains 0 . 34% of iron by mass. The number of Fe atoms in 3 . 3 g of hemoglobin is (Given : Atomic mass of Fe is 56u, NA in6 . 022 × 1023 mol-1) (1) 1 . 21 × 105 (2) 12 . 0 × 1016 (3) 1 . 21 × 1020 (4) 3 . 4 × 1022