Practice Questions
10,208 questions across 23 years of JEE Main β find and practise any topic!
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Q76.If y = y ( x ) is the solution curve of the differential equation x2 - 4dy - y2 - 3ydx = 0, x > 2, y(4) = 3 and 2 the slope of the curve is never zero, then the value of y ( 10 ) equals : 3 3 (1) 1 (2) 1 + 2β2 1 + ( 8 ) 4 3 3 (3) (4) 1 1 - 2β2 1 - ( 8 ) 4
Q76.A function y = f(x) satisfies f(x) sin 2x + sin x β(1 + cos2 x)f β²(x) = 0 with condition f(0) = 0. Then f( Ο2 ) is equal to (1) 1 (2) 0 (3) β1 (4) 2 β β β
Q76.Let y = y(x) be the solution of the differential equation (1 + y2)etan xdx + cos2 x (1 + e2 tan x)dy = 0, y(0) = 1. Then y ( Ο4 ) is equal to (1) 2 (2) 2 e e2 (3) 1 (4) 1 e e2
Q76.The area enclosed by the curves π₯π¦+ 4π¦= 16 and π₯+ π¦= 6 is equal to: (1) 28 β30logπ2 (2) 30 β28logπ2 (3) 30 β32logπ2 (4) 32 β30logπ2 2
Q76.Let π¦= π¦( π₯) be the solution of the differential equation ππ¦ tanπ₯+ π¦ π ππ₯= sinπ₯secπ₯- sinπ₯tanπ₯, π₯β0, 2 satisfying the π π condition π¦ = 2. Then, π¦ is 4 3 2 + logπ3 (1) β32 + logπβ3 (2) β32 (3) β31 + 2logπ3 (4) β32 + logπ3 β
Q76.Let y = y(x) be the solution of the differential equation sec xdy + {2(1 βx) tan x + x(2 βx)}dx = 0 such that y(0) = 2. Then y(2) is equal to : (1) 2 (2) 2{1 βsin(2)} (3) 2{sin(2) + 1} (4) 1
Q76.Let π: π βπ be defined ππ₯= ππ2π₯+ πππ₯+ ππ₯. If π(0) = - 1, π'logπ2 = 21 and β«0log4 2 the value of |π+ π+ π| equals: (1) 16 (2) 10 (3) 12 (4) 8 2
Q76.Let y = y(x) be the solution curve of the differential equation sec y dydx + 2x sin y = x3 cos y, y(1) = 0. Then y(β3) is equal to : (1) Ο (2) Ο 3 6 (3) Ο (4) Ο 12 4
Q76.One of the points of intersection of the curves y = 1 + 3x β2x2 and y = x1 is ( 21 , 2). Let the area of the region enclosed by these curves be 1 (lβ5 + m) βn loge(1 + β5), where l, m, n βN. Then l + m + n is 24 equal to (1) 29 (2) 31 (3) 30 (4) 32
Q76.Let the area of the region enclosed by the curves y = 3x, 2y = 27 β3x and y = 3x βxβx be A . Then 10A is equal to (1) 172 (2) 162 (3) 154 (4) 184
Q76.The area (in sq. units) of the region described by {(x, y) : y2 β€2x, and y β₯4x β1} is (1) 11 (2) 8 32 9 (3) 11 (4) 9 12 32
Q76.The area (in square units) of the region enclosed by the ellipse x2 + 3y2 = 18 in the first quadrant below the line y = x is (1) β3Ο β34 (2) β3Ο + 1 (3) β3Ο (4) β3Ο + 34
Q77.Let βa = 2^i + ^j β^k, b = ((βaΓ (^i + ^j)) Γ^i) Γ^i. Then the square of the projection of βa on b is : (1) 1 (2) 2 3 3 (3) 2 (4) 1 5 β
Q77.The set of all Ξ±, for which the vectors βa = Ξ±t^i + 6^j β3^k and βb = t^i β2^j β2Ξ±t^k are inclined at an obtuse angle for all t βR, is (1) (β43 , 1) (2) [0, 1) (3) (β43 , 0] (4) (β2, 0] L1 : βr = (2 + Ξ»)^i + (1 β3Ξ»)^j + (3 + 4Ξ»)^k, Ξ» βR m
Q77.Let A(2, 3, 5) and C(β3, 4, β2) be opposite vertices of a parallelogram ABCD if the diagonal ββ BD = Λi + 2Λj + 3Λk then the area of the parallelogram is equal to (1) 1 2 β410 (2) 21 β474 (3) 1 2 β586 (4) 21 β306 β β β
Q77.Let x = x(t) and y = y(t) be solutions of the differential equations dxdt + ax = 0 and dydt + by = 0 respectively, a, b βR. Given that x(0) = 2 ; y(0) = 1 and 3 y(1) = 2 x(1), the value of t, for which x(t) = y(t), is : (1) log 2 2 (2) log4 3 3 4 2 (3) log3 4 (4) log 3 β β andβcbe the vector such that βaΓβc= b and βaβ βc= 3, then
Q77.Let y = y(x) be the solution of the differential equation (1 + x2) dxdy + y = etanβ1 x , y(1) = 0. Then y(0) is (1) 2 1 (eΟ/2 β1) (2) 21 (1 βeΟ/2) (3) 4 1 (1 βeΟ/2) (4) 14 (eΟ/2 β1)
Q77.Consider a π₯π΄π΅πΆ where π΄1, 3, 2, π΅β2, 8, 0 and πΆ3, 6, 7. If the angle bisector of β π΅π΄πΆ meets the line π΅πΆ at π·, then the length of the projection of the vector βπ΄π· on the vector βπ΄πΆ is: (1) 37 (2) β38 2β38 2 39 (3) (4) β19 2β38
Q77.The temperature ππ‘ of a body at time π‘= 0 is 160Β° πΉ and it decreases continuously as per the differential ππ equation ππ‘= βπΎπβ80, where πΎ is positive constant. If π15 = 120Β° πΉ, then π45 is equal to (1) 85Β° πΉ (2) 95Β° πΉ (3) 90Β° πΉ (4) 80Β° πΉ
Q77.Let βa = 4^i β^j + ^k,βb = 11^i β^j + ^k and βc be a vector such that (βa + βb) Γ βc = βc Γ (β2βa + 3βb). If (2βa + 3βb) β βc = 1670, then |βc|2 is equal to : (1) 1609 (2) 1618 (3) 1600 (4) 1627 β
Q77.The position vectors of the vertices A, B and C of a triangle are 2 ^i - 3 ^j + 3 ^k, 2 ^i + 2 ^j + 3 ^k and - ^i + ^j + 3 ^k respectively. Let π denotes the length of the angle bisector AD of β BAC where D is on the line segment BC, then 2π2 equals : (1) 49 (2) 42 (3) 50 (4) 45
Q77.Let three vectors βa = Ξ±^i + 4^j + 2^k, b = 5^i + 3^j + 4^k,βc= x^i + y^j + z^k form a triangle such that βc = βa ββb and the area of the triangle is 5β6. If Ξ± is a positive real number, then |βc|2 is equal to: (1) 16 (2) 14 (3) 12 (4) 10 β ββββ
Q77.Let βa, b andβcbe three non-zero vectors such that b andβcare non-collinear if βa+ 5b is collinear with βc,βb + 6βcis collinear with βa and βa+ Ξ±βb + Ξ²βc= β0, then Ξ± + Ξ² is equal to (1) 35 (2) 30 (3) β30 (4) β25
Q77.If y = y(x) is the solution of the differential equation dydx + 2y = sin(2x), y(0) = 43 , then y ( Ο8 ) is equal to: JEE Main 2024 (05 Apr Shift 1) JEE Main Previous Year Paper (1) eΟ/8 (2) eΟ/4 (3) eβΟ/4 (4) eβΟ/8
Q77.Let βπ= ^π+ πΌ ^π+ π½ ^π , πΌ, π½βπ . Let a vector βπ be such that the angle between βπ and βπ is π and βπ = 6, If 4 βπΒ· βπ= 3β2, then the value of πΌ2 + π½2 | βπΓ βπ|2 is equal to (1) 90 (2) 75 (3) 95 (4) 85 2 is equal to