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10,208 questions across 23 years of JEE Main β€” find and practise any topic!

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Q77.Let y = y(x) be the solution of the differential equation (x2 + 4)2dy + (2x3y + 8xy βˆ’2)dx = 0. If y(0) = 0, then y(2) is equal to (1) Ο€ (2) 2Ο€ 32 (3) Ο€ (4) Ο€ 8 16

202404 Apr Shift 2Differential Equations
MathsHard

Q77.Let 𝑦= 𝑦π‘₯ be the solution of the differential equation 𝑑𝑦 2π‘₯π‘₯+ 𝑦3 βˆ’π‘₯π‘₯+ π‘¦βˆ’1, 𝑦0 = 1. Then, 1 + 𝑦1 𝑑π‘₯= √2 √2 equals: (1) 4 (2) 3 4 + βˆšπ‘’ 3 βˆ’βˆšπ‘’ 2 1 (3) (4) 1 + βˆšπ‘’ 2 βˆ’βˆšπ‘’

202401 Feb Shift 1Definite Integration & Area
MathsMedium

Q77.Let β†’π‘Ž= 3 ^𝑖+ ^π‘—βˆ’2 ^π‘˜, 𝑏= 4 ^𝑖+ ^𝑗+ 7 ^π‘˜ and →𝑐= ^π‘–βˆ’3 ^𝑗+ 4 ^π‘˜ be three vectors. If a vectors →𝑝 satisfies →𝑝× →𝑏= →𝑐× →𝑏 and β†’π‘β‹…β†’π‘Ž= 0, then →𝑝⋅ ^π‘–βˆ’ ^π‘—βˆ’ ^π‘˜ is equal to (1) 24 (2) 36 (3) 28 (4) 32

202431 Jan Shift 1Vectors
MathsMedium

Q77.If the solution y = y(x) of the differential equation (x4 + 2x3 + 3x2 + 2x + 2)dy βˆ’(2x2 + 2x + 3)dx = 0 satisfies y(βˆ’1) = βˆ’Ο€4 , then y(0) is equal to : (1) Ο€ 2 (2) βˆ’Ο€2 (3) 0 (4) Ο€ 4 β†’

202404 Apr Shift 1Differential Equations
MathsHard

Q77.Consider three vectors β†’a,β†’b, β†’c. Let |β†’a| = 2, |β†’b| = 3 and β†’a = β†’b Γ— β†’c. If Ξ± ∈[0, 3 ] is the angle between the vectors β†’b and β†’c, then the minimum value of 27|β†’c βˆ’β†’a|2 is equal to: (1) 110 (2) 124 (3) 121 (4) 105

202405 Apr Shift 2Differential Equations
MathsMedium

Q77.Let OA→ =→a, OB→ = 12→a+ 4→b and OC→ = →b, where O is the origin. If S is the parallelogram with adjacent sides OA and OC, then area of the areaquadrilateralof S OABC is equal to _____ (1) 6 (2) 10 (3) 7 (4) 8

202429 Jan Shift 2Vectors
MathsMedium

Q78.If the line 2βˆ’x 3 = 4Ξ»+13yβˆ’2 = 4 βˆ’z makes a right angle with the line x+33ΞΌ = 1βˆ’2y6 = 5βˆ’z7 , then 4Ξ» + 9ΞΌ is equal to : (1) 4 (2) 13 (3) 5 (4) 6

202405 Apr Shift 13D Geometry
MathsMedium

Q78.The distance of the point 𝑄( 0, 2, – 2 ) form the line passing through the point 𝑃( 5, – 4, 3 ) and perpendicular to the lines β†’π‘Ÿ= βˆ’3 ^𝑖+ 2 ^π‘˜+ πœ†2 ^𝑖+ 3 ^𝑗+ 5 ^π‘˜, πœ†βˆˆβ„ and β†’π‘Ÿ= ^π‘–βˆ’2 ^𝑗+ ^π‘˜+ πœ‡βˆ’ ^𝑖+ 3 ^𝑗+ 2 ^π‘˜, πœ‡βˆˆβ„ is (1) √86 (2) √20 (3) √54 (4) √74

202431 Jan Shift 13D Geometry
MathsMedium

Q78.Let OAβ†’ = 2β†’a, OB = 6β†’a + 5β†’b and OC = 3β†’b, where O is the origin. If the area of the parallelogram with βˆ’βˆ’β†’ β†’ adjacent sides OA and OC is 15 sq. units, then the area (in sq. units) of the quadrilateral OABC is equal to : (1) 32 (2) 40 (3) 38 (4) 35

202409 Apr Shift 1Vectors
MathsMedium

Q78.Let a unit vector which makes an angle of 60∘ with 2^i + 2^j βˆ’^k and angle 45∘ with ^i βˆ’^k be C. Then β†’ is : C + + (βˆ’12^i 1 ^j βˆ’βˆš23 ^k) 3√2 (1) √2 + βˆ’ + 3 + 21 )^i 1 )^j + √23 )^k ^i βˆ’12 ^k (2) ( √31 ( √31 3√2 ( √31 2√2 (3) √2 ^i + + 3 3√2 1 ^j βˆ’12 ^k (4) βˆ’βˆš23 ^i + √23 ^j + ( 21 3 )^k

202404 Apr Shift 1Vectors
MathsMedium

Q78.Let β†’a = ^i + 2^j + 3^k, b = 2^i + 3^j βˆ’5^k andβ†’c= 3^i βˆ’^j + Ξ»^k be three vectors. Letβ†’rbe anit vector along β†’b + β†’c. If β†’r β‹…β†’a = 3, then 3Ξ» is equal to: (1) 21 (2) 30 (3) 25 (4) 27

202408 Apr Shift 2Vectors
MathsMedium

Q78.Let O be the origin and the position vector of A and B be 2Λ†i + 2Λ†j + Λ†k and 2Λ†i + 4Λ†j + 4Λ†k respectively. If the internal bisector of ∠AOB meets the line AB at C , then the length of OC is (1) 3 2 √31 (2) 32 √34 (3) 3 4 √34 (4) 23 √31

202429 Jan Shift 1Differential Equations
MathsMedium

Q78.Let a unit vector Λ†u = xΛ†i + yΛ†j + zΛ†k make angles Ο€2 , Ο€3 and 2Ο€3 with the vectors √2Λ†i1 + √21 Λ†k, √21 Λ†j + √21 Λ†k and 1 + 1 Λ†j respectively. If β†’v= 1 + 1 Λ†j + 1 Λ†k, then |^u βˆ’β†’v|2 is equal to √2Λ†i √2 √2Λ†i √2 √2 (1) 11 (2) 5 2 2 (3) 9 (4) 7

202429 Jan Shift 2Vectors
MathsHard

Q78.Let β†’π‘Ž= βˆ’5 ^𝑖+ ^π‘—βˆ’3 ^π‘˜, →𝑏= ^𝑖+ 2 ^π‘—βˆ’4 ^π‘˜ and →𝑐= β†’π‘ŽΓ— →𝑏× ^𝑖× ^𝑖× ^𝑖. Then β†’π‘β‹…βˆ’ ^𝑖+ ^𝑗+ ^π‘˜ is equal to (1) -12 (2) -10 (3) -13 (4) -15

202401 Feb Shift 1Differential Equations
MathsHard

Q78.Let y = y(x) be the solution of the differential equation (2x loge x) dxdy + 2y = x3 loge x, x > 0 and y (eβˆ’1) = 0. Then, y(e) is equal to (1) βˆ’3e (2) βˆ’32e (3) βˆ’23e (4) βˆ’2e

202406 Apr Shift 1Differential Equations
MathsMedium

Q78.Let 𝛼, 𝛽, 𝛾 be mirror image of the point 2, 3, 5 in the line π‘₯βˆ’1 = π‘¦βˆ’2 = π‘§βˆ’3 . Then 2𝛼+ 3𝛽+ 4𝛾 is equal to 2 3 4 (1) 32 (2) 33 (3) 31 (4) 34 π‘₯βˆ’1 𝑦+ 1 𝑧+ 4

202431 Jan Shift 23D Geometry
MathsMedium

Q78.Let β†’π‘Ž and →𝑏 be two vectors such that | →𝑏| = 1 and | →𝑏× β†’π‘Ž| = 2 Then |( →𝑏× β†’π‘Ž) - →𝑏| (1) 3 (2) 5 (3) 1 (4) 4

202430 Jan Shift 2Vectors
MathsEasy

Q78.If β†’a = Λ†i + 2Λ†j + Λ†k, b = 3(Λ†i βˆ’Λ†j + Λ†k) is equal to Γ— βˆ’ b β†’aβ‹…((β†’c β†’ β†’ b) βˆ’β†’c) (1) 32 (2) 24 (3) 20 (4) 36

202427 Jan Shift 1Vectors
MathsMedium

Q78.Let β†’a = ^i + ^j + ^k,β†’b = 2^i + 4^j βˆ’5^k and β†’c = x^i + 2^j + 3^k, x ∈R. If β†’d is the unit vector in the direction of β†’b + β†’c such that β†’a β‹…β†’d = 1, then (β†’a Γ— β†’b) β‹…β†’c is equal to (1) 11 (2) 3 (3) 9 (4) 6

202404 Apr Shift 2Vectors
MathsMedium

Q78.If the mirror image of the point 𝑃( 3, 4, 9 ) in the line π‘₯βˆ’1 = 𝑦+ 1 = π‘§βˆ’2 is 𝛼, 𝛽, 𝛾, then 14𝛼+ 𝛽+ 𝛾 is: 3 2 1 (1) 102 (2) 138 (3) 108 (4) 132 π‘₯+ 3 π‘¦βˆ’4 𝑧+ 1

202401 Feb Shift 23D Geometry
MathsMedium

Q78.Let β†’a = aiΛ†i + a2Λ†j + a3Λ†k and b = b1Λ†i + b2Λ†j + b3Λ†k be two vectors such that β†’a = 1;β†’aβ‹… b = 2 and b = 4. If Γ— βˆ’3b, then the angle between b and β†’cis equal to : β†’c= 2(β†’a β†’ β†’ β†’ b) JEE Main 2024 (30 Jan Shift 1) JEE Main Previous Year Paper (1) cosβˆ’1( √32 ) (2) cosβˆ’1(βˆ’1√3 ) 2 ) 3 (3) cosβˆ’1(βˆ’βˆš32 ) (4) cosβˆ’1(

202430 Jan Shift 1Vectors
MathsMedium

Q78.If the shortest distance between the lines is √n L2 : β†’r = 2(1 + ΞΌ)^i + 3(1 + ΞΌ)^j + (5 + ΞΌ)^k, ΞΌ ∈R , where gcd(m, n) = 1, then the value of m + n equals (1) 390 (2) 384 (3) 377 (4) 387

202408 Apr Shift 1Vectors
MathsMedium

Q78.Let β†’a = 6^i + ^j βˆ’^k and b = ^i + ^j. Ifβ†’cis a is vector such that |β†’c| β‰₯6,β†’aβ‹…β†’c= 6|β†’c|, |β†’cβˆ’β†’a| = 2√2 and the angle between β†’a Γ— β†’b and β†’c is 60∘ , then |(β†’a Γ— β†’b) Γ— β†’c| is equal to: (1) 9 2 (6 βˆ’βˆš6) (2) 23 √6 (3) 9 2 (6 + √6) (4) 23 √3

202406 Apr Shift 2Vectors
MathsHard

Q78.Let β†’a = 2^i + 5^j βˆ’^k,β†’b = 2^i βˆ’2^j + 2^k andβ†’cbe three vectors such that (β†’c +^i) Γ— (β†’a + β†’b +^i) = β†’a Γ— (β†’c +^i). If β†’a β‹…β†’c = βˆ’29, then β†’c β‹…(βˆ’2^i + ^j + ^k) is equal to: (1) 15 (2) 12 (3) 10 (4) 5

202405 Apr Shift 2Vectors
MathsMedium

Q79.Let the point, on the line passing through the points P(1, βˆ’2, 3) and Q(5, βˆ’4, 7), farther from the origin and at distance of 9 units from the point P, be (Ξ±, Ξ², Ξ³). Then Ξ±2 + Ξ²2 + Ξ³ 2 is equal to : (1) 165 (2) 160 (3) 155 (4) 150

202404 Apr Shift 13D Geometry
MathsMedium

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