Practice Questions
3,523 questions across 23 years of JEE Main β find and practise any topic!
Found 3,523 results
Q72.The sum of all the local minimum values of the twice differentiable function f : R βR defined by β²β²(2) x + f β²β²(1) is: f(x) = x3 β3x2 β3f 2 (1) β22 (2) 5 (3) β27 (4) 0
Q73.Let ΞΈ β(0, Ο2 ). If the system of linear equations (1 + cos2 ΞΈ)x + sin2 ΞΈy + 4 sin 3ΞΈz = 0 cos2 ΞΈx + (1 + sin2 ΞΈ)y + 4 sin 3ΞΈz = 0 cos2 ΞΈx + sin2 ΞΈy + (1 + 4 sin 3ΞΈ)z = 0 has a non-trivial solution, then the value of ΞΈ is: (1) 4Ο (2) 5Ο 9 18 (3) 7Ο (4) Ο 18 18 = tanβ1 0 < x < 1. Then: x
Q73.The value of the integral, β«31 [x2 β2x β2]dx, where [x] denotes the greatest integer less than or equal to x, is (1) β4 (2) β5 (3) ββ2 ββ3 + 1 (4) ββ2 ββ3 β1
Q73.Let f : R βR be defined as f(x) = { β43 x3 +3xex2x2 + 3x,, xx >β€00 . Then f is increasing function in the interval (1) (β12 , 2) (2) (0, 2) (3) (β1, 23 ) (4) (β3, β1) , Ξ± βR where [x] is the greatest integer less than or equal to x, then the value of
Q73.Let f : R βR be defined as f(x + y) + f(x βy) = 2f(x)f(y), f( 21 ) = β1. Then the value of β20k=1 sin(k) sin(k+f(k))1 is equal to : (1) cosec2 (21) cos(20) cos(2) (2) sec2(1) sec(21) cos(20) (3) cosec2 (1) cosec (21) sin(20) (4) sec2(21) sin(20) sin(2) . Then which of
Q73.The function f(x) = x2 β2x β3 β e9x2β12x+4 is not differentiable at exactly : (1) Four points (2) Two points (3) three points (4) one point 1 1+ xaQ74. , x < 0 β§ x loge( 1βxb ) If the function f(x) = k , x = 0 β¨ cos2 xβsin2 xβ1 , x > 0 β© βx2+1β1 is continuous at x = 0, then a1 + 1b + k4 is equal to : (1) 4 (2) 5 (3) β4 (4) β5
Q73.An angle of intersection of the curves, π₯2 + π¦2 = 1 and π₯2 + π¦2 = ππ, π> π, is : π2 π2 (1) tan-12βππ (2) tan-1π+ π βππ (3) tan-1π- π (4) tan-1 π- π βππ 2βππ
Q73.If the tangent to the curve π¦= π₯3 at the point ππ‘, π‘3 meets the curve again at π, then the ordinate of the point which divides ππ internally in the ratio 1: 2 is: (1) 0 (2) -2π‘3 (3) -π‘3 (4) 2π‘3
Q73.Let f : R β{3} βR β{1} be defined by f(x) = xβ3xβ2 . Let g : R βR be given as g(x) = 2x β3 . Then, the sum of all the values of x for which f β1(x) + gβ1(x) = 132 is equal to (1) 7 (2) 2 (3) 5 (4) 3
Q73.A wire of length 20 m is to be cut into two pieces. One of the pieces is to be made into a square and the other into a regular hexagon. Then the length of the side (in meters) of the hexagon, so that the combined area of the square and the hexagon is minimum, is (1) 10 (2) 5 2+3β3 3+β3 (3) 10 (4) 5 3+2β3 2+β3 + β¦ + n2
Q73.Let M and m respectively be the maximum and minimum values of the function f(x) = tanβ1(sin x + cos x) in [0, Ο2 ]. Then the value of tan(M βm) is equal to: (1) 2 ββ3 (2) 3 β2β2 (3) 3 + 2β2 (4) 2 + β3
Q73.Let x denote the total number of one-one functions from a set A with 3 elements to a set B with 5 elements and y denote the total number of one-one functions from the set A to the set A Γ B. Then : JEE Main 2021 (25 Feb Shift 2) JEE Main Previous Year Paper (1) y = 273x (2) 2y = 273x (3) 2y = 91x (4) y = 91x
Q73.Let [t] denote the greatest integer less than or equal to t. Let f(x) = x β[x], g(x) = 1 βx + [x], and h(x) = min{f(x), g(x)}, x β[β2, 2]. Then h is : (1) continuous in [β2, 2] but not differentiable at (2) Continous in [β2, 2] but not differentiable at more than four points in (β2, 2) exactly three poionts in (β2, 2) (3) not continuous at exactly four points in [β2, 2] (4) not continuous at exactly three points in [β2, 2] is
Q73.If [x] denotes the greatest integer less than or equal to x, then the value of the integral β«Ο/2βΟ/2[[x] βsin x]dx is equal to: (1) βΟ (2) Ο (3) 0 (4) 1
Q73.The maximum slope of the curve y = 21 x4 β5x3 + 18x2 β19x occurs at the point (1) (3, 212 ) (2) (2, 2) (3) (2, 9) (4) (0, 0)
Q73.If cotβ1(Ξ±) = cotβ1 2 + cotβ1 8 + cotβ1 18 + cotβ1 32 + β¦ . upto 100 terms, then Ξ± is: JEE Main 2021 (17 Mar Shift 1) JEE Main Previous Year Paper (1) 1. 01 (2) 1. 00 (3) 1. 02 (4) 1. 03
Q73.For x > 0 , if f(x) = β«x1 (1+t)loge t (1) 0 (2) 21 (3) β1 (4) 1 x βR. Then f(x) equals :
Q73.Consider the function f : R βR defined by f(x) = { (2 βsin(0, x1 )) x , xx =β 00 (1) monotonic on (ββ, 0) βͺ(0, β) (2) not monotonic on (ββ, 0) and (0, β) (3) monotonic on (0, β) only (4) monotonic on (ββ, 0) only
Q73.Let ππ₯= 3sin4π₯+ 10sin3π₯+ 6sin2π₯- 3, π₯β- 6, 2. Then, π is : (1) increasing in -π π (2) decreasing in 0, π 6, 2 2 π π (3) increasing in - 6, 0 (4) decreasing in - 6, 0
Q73.If [x] be the greatest integer less than or equal to x, then 100β [ (β1)nn2 ] n=8 (1) 0 (2) 4 (3) β2 (4) 2
Q73.If Rolle's theorem holds for the function f(x) = x3 βax2 + bx β4, x β[1, 2] with f β²( 43 ) = 0 , then ordered pair (a, b) is equal to : (1) (β5, β8) (2) (β5, 8) (3) (5, 8) (4) (5, β8) dΞΈ is (where c is a constant of integration)
Q73.Consider the integral I = β«100 [x]e[x]exβ1 value of I is equal to : (1) 9(e β1) (2) 45(e + 1) (3) 45(e β1) (4) 9(e + 1)
Q74.Let f(x) = β«x0 etf(t)dt + ex be a differentiable function for all (1) e(exβ1) (2) eex β1 (3) 2eex β1 (4) 2e(exβ1) β1
Q74.The sum of possible values of x for tanβ1(x + 1) + cotβ1( xβ11 ) = tanβ1( 318 ) is: (1) β324 (2) β314 (3) β304 (4) β334
Q74.Let P(x) = x2 + bx + c be a quadratic polynomial with real coefficients such that β«10 P(x)dx = 1 and P(x) leaves remainder 5 when it is divided by (x β2) Then the value of 9(b + c) is equal to: (1) 9 (2) 15 (3) 7 (4) 11