Practice Questions
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Q54.If the constant term in the binomial expansion of (βx β x2k ) 10 (1) 9 (2) 1 (3) 3 (4) 2
Q54.If for some positive integer n, the coefficients of three consecutive terms in the binomial expansion of (1 + x)n+5 are in the ratio 5 : 10 : 14, then the largest coefficient in the expansion is : (1) 462 (2) 330 (3) 792 (4) 252
Q54.Let an be the nth term of a G.P. of positive terms. If β100n=1 a2n+1 = 200 and β100n=1 a2n = 100, then β200n=1 an is equal to: (1) 300 (2) 225 (3) 175 (4) 150
Q54.If 32 sin 2Ξ±β1, 14 and 34β2 sin 2Ξ± are the first three terms of an A.P. for some Ξ± , then the sixth term of this A.P. is (1) 66 (2) 81 (3) 65 (4) 78
Q54.Five numbers are in A. P. , whose sum is 25 and product is 2520. If one of these five numbers is β12 , then the greatest number amongst them is (1) 27 (2) 7 (3) 21 (4) 16 2
Q54.If |x| < 1, |y| < 1 and x β 1 , then the sum to infinity of the following series (x + y) + (x2 + xy + y2) + (x3 + x2y + xy2 + y3)+. . . . . is (1) x+yβxy (2) x+y+xy (1+x)(1+y) (1+x)(1+y) (3) x+yβxy (4) x+y+xy (1βx)(1βy) (1βx)(1βy)
Q54.The value of ( 2 β 1 P0 β3 β 2 P1 + 4 β 3 P2β. . . . . . . . up to 51th term) +( 1! β2! + 3!β. . . . . . . up to 51th term) is equal to (1) 1 β51(51)! (2) 1 + (51)! (3) 1 + (52)! (4) 1 1 1 n 2 + 5 8 is exactly 33, then the least value of n is
Q54.If Ξ± and Ξ², be the coefficients of x4 and x2 , respectively in the expansion of 6 6 + βx2 + ββx2 (x β1) (x β1) , then (1) Ξ± + Ξ² = 60 (2) Ξ± + Ξ² = β30 (3) Ξ± βΞ² = 60 (4) Ξ± βΞ² = β132
Q54.If 1 + (1 β22 β 1) + (1 β42 β 3) + (1 β62 β 5) + β¦ β¦ + (1 β202 β 19) = Ξ± β220 Ξ² , then an ordered pair (Ξ±, Ξ²) is equal to: (1) (10, 97) (2) (11, 103) (3) (10, 103) (4) (11, 97)
Q54.The product 2 41 β4 161 β8 481 β16 1 128 β. . . . to β is equal to: (1) 2 21 (2) 2 41 (3) 1 (4) 2
Q54.Let two points be A(1, β1) and B(0, 2). If a point P(x', y') be such that the area of ΞPAB = 5 sq. units and it lies on the line 3x + y β4Ξ» = 0, then a value of Ξ» is (1) 4 (2) 3 (3) 1 (4) β3
Q54.If the sum of first 11 terms of an A.P. , a1, a2, a3 β¦ β¦ is 0(a1 β 0) then the sum of the A.P a1, a3, a5, β¦ . . a23 is ka1 where k is equal to (1) β12110 (2) 12110 (3) 725 (4) β725
Q55.If the number of integral terms in the expansion of (3 ) (1) 264 (2) 128 (3) 256 (4) 248
Q55.If the sum of the first 20 terms of the series log(71/2) x + log(71/3) x + log(71/4) x + β¦ is 460 , then x is equal to: (1) 72 (2) 71/2 (3) e2 (4) 746/21
Q55.If the perpendicular bisector of the line segment joining the points P(1, 4) and Q(k, 3) has y-intercept equal to β4, then a value of k is; (1) β2 (2) β4 (3) β14 (4) β15
Q55.The greatest positive integer k, for which 49k + 1 is a factor of the sum 49125 + 49124 + β¦ + 492 + 49 + 1, is (1) 32 (2) 63 (3) 60 (4) 35
Q55.If x = ββn=0 (β1)ntan2ΞΈ and y = ββn=0 cos2nΞΈ, for 0 < ΞΈ < Ο4 , then: (1) x(1 + y) = 1 (2) y(1 βx) = 1 (3) y(1 + x) = 1 (4) x(1 βy) = 1 x when Ο
Q55.If a ΞABC has vertices A(β1, 7), B(β7, 1) and C(5, β5), then its orthocentre has coordinates: (1) (β 3, 3) (2) (3, β3) (3) (β35 , 53 ) (4) ( 53 , β35 )
Q55.The locus of a point which divides the line segment joining the point (0, β1) and a point on the parabola x2 = 4y internally in the ratio 1 : 2 is: (1) 9x2 β12y = 8 (2) 9x2 β3y = 2 (3) x2 β3y = 2 (4) 4x2 β3y = 2
Q55.If {p} denotes the fractional part of the number p, then { 32008 } (1) 5 (2) 7 8 8 (3) 3 (4) 1 8 8 is incident at an angle 30Β° on the line x = 1 at the point A . The
Q55.If the common tangent to the parabolas, y2 = 4 x and x2 = 4 y also touches the circle, x2 + y2 = c2, then c is equal to : (1) 1 (2) 1 2β2 β2 (3) 41 (4) 12 P is any point on the
Q55.The coefficient of x7 in the expression (1 + x)10 + x(1 + x)9 + x2(1 + x)8+. . . . +x10 , is (1) 210 (2) 330 (3) 120 (4) 420
Q55.Let L denote the line in the xy-plane with x and y intercepts as 3 and 1 respectively. Then the image of the point (β1, β4) in the line is : (1) ( 115 , 285 ) (2) ( 295 , 85 ) (3) ( 85 , 295 ) (4) ( 295 , 115 )
Q55.Let Ξ± > 0, Ξ² > 0 be such that Ξ±3 + Ξ²2 = 4 . If the maximum value of the term independent of x in the 1 10 10k, then k is equal to binomial expansion of (Ξ±x 9 + Ξ²xβ16 ) is (1) 336 (2) 352 (3) 84 (4) 176
Q55.Let S be the sum of the first 9 term of the series : {x + ka} + {x2 + (k + 2)a} + {x3 + (k + 4)a} + {x4 + (k + 6)a} + β¦ where a β 0 and x β 1 . If x10βx+45a(xβ1) S = xβ1 , then k is equal to (1) β5 (2) 1 (3) β3 (4) 3