Practice Questions
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Q19.Let I(x) = β« 11 15 . If I(37) βI(24) = 4 1 β 1 b, c βN (xβ11) 13 (x+15) 13 ( b 13 c 13 ), (1) 22 (2) 39 (3) 40 (4) 26
Q19.Let S = N βͺ{0}. Define a relation R from S to R by : R = {(x, y) : loge y = x loge ( 25 ), x β S, y βR} Then, the sum of all the elements in the range of R is equal to : (1) 10 (2) 3 9 2 (3) 5 (4) 5 2 3
Q20.Let the area of the region {(x, y) : 2y β€x2 + 3, y + |x| β€3, y β©Ύ|x β1|} be A. Then 6 A is equal to : (1) 16 (2) 12 (3) 14 (4) 18
Q20.If sin x + sin2 x = 1, x β(0, Ο2 ), then (cos12 x + tan12 x) + 3 (cos10 x + tan10 x + cos8 x + tan8 x) + (cos6 x + tan6 x) is equal to : (1) 4 (2) 1 (3) 3 (4) 2 Ο
Q20.If Ξ± > Ξ² > Ξ³ > 0, then the expression cotβ1 {Ξ² (Ξ±βΞ²) } + cotβ1 {Ξ³ (Ξ²βΞ³) } + cotβ1 {Ξ± (Ξ³βΞ±) } equal to : (1) Ο (2) 0 (3) Ο 2 β(Ξ± + Ξ² + Ξ³) (4) 3Ο L.
Q20.Let E : x2 + y2 = 1, a > b and H : x2 β y2 = 1. Let the distance between the foci of E and the foci of H a2 b2 A2 B2 be 2β3. If a βA = 2, and the ratio of the eccentricities of E and H is 13 , then the sum of the lengths of their latus rectums is equal to: (1) 10 (2) 9 (3) 8 (4) 7 = Ξ± Γ 229 , then Ξ± is equal to ______
Q20.If Ο 2 β€x β€3Ο4 , then cosβ1 ( 1213 cos x + 135 sin x) is equal to (1) x βtanβ1 43 (2) x + tanβ1 45 (3) x βtanβ1 125 (4) x + tanβ1 125
Q20.Two equal sides of an isosceles triangle are along βx + 2y = 4 and x + y = 4. If m is the slope of its third side, then the sum, of all possible distinct values of m, is : (1) β2β10 (2) 12 (3) 6 (4) β6
Q20.If the area of the region {(x, y) : β1 β€x β€1, 0 β€y β€a + e|x| βeβx, a > 0} is e2+8e+1e , then the value of is : (1) 8 (2) 7 (3) 5 (4) 6
Q20.Let βa = ^i + 2^j + 3^k,βb = 3^i + ^j β^k and βc be three vectors such that βc is coplanar with βa and βb. If the vector βC is perpendicular to βb and βa β βc = 5, then |βc| is equal to (1) β116 (2) 3β21 (3) 16 (4) 18
Q20.Let z1, z2 and z3 be three complex numbers on the circle |z| = 1 with arg (z1) = βΟ4 , arg (z2) = 0 and arg (z3) = Ο4 . If |z1Β―z2 + z2Β―z3 + z3Β―z1|2 = Ξ± + Ξ²β2, Ξ±, Ξ² βZ, then the value of Ξ±2 + Ξ²2 is : (1) 24 (2) 29 (3) 41 (4) 31
Q21.The variance of the numbers 8, 21, 34, 47, β¦ , 320 is
Q21.Let S = {p1, p2 β¦ . , p10} be the set of first ten prime numbers. Let A = S βͺP , where P is the set of all possible products of distinct elements of S . Then the number of all ordered pairs ( x, y ), x βS , y βA , such that x divides y, is ______.
Q64. Choose the correct answer from the options given below : (1) (A)-(III), (B)-(IV), (C)-(II), (D)-(I) (2) (A)-(I), (B)-(III), (C)-(II), (D)-(IV) (3) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) (4) (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Q68. Choose the correct answer from the options given below : (1) (A)-(IV), (B)-(III), (C)-(II), (D)-(I) (2) (A)-(III), (B)-(IV), (C)-(II), (D)-(I) (3) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) (4) (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
Q61.Let r and ΞΈ respectively be the modulus and amplitude of the complex number z = 2 βi(2 tan 5Ο8 ), then (r, ΞΈ) is equal to (1) (2 sec 3Ο8 , 3Ο8 ) (2) (2 sec 3Ο8 , 5Ο8 ) (3) (2 sec 5Ο8 , 3Ο8 ) (4) (2 sec 11Ο8 , 11Ο8 )
Q61.Let π= π₯βπ : β3 + β2 π₯+ β3 ββ2 π₯= 10. Then the number of elements in π is: (1) 4 (2) 0 (3) 2 (4) 1
Q61.Let Ξ±, Ξ²; Ξ± > Ξ² , be the roots of the equation x2 ββ2x ββ3 = 0. Let Pn = Ξ±n βΞ²n, n βN . Then (11β3 β10β2)P10 + (11β2 + 10)P11 β11P12 is equal to (1) 10β3P9 (2) 11β3P9 (3) 10β2P9 (4) 11β2P9
Q61.If z = 21 β2i, is such that z + 1 = Ξ±z + Ξ²(1 i), (1) β4 (2) 3 (3) 2 (4) β1
Q61.Let π be the set of positive integral values of π for which ππ₯2 + 2π+ 1π₯+ 9π+ 4 < 0, βπ₯ββ. Then, the number π₯2 - 8π₯+ 32 of elements in π is: (1) 1 (2) 0 (3) β (4) 3
Q61.Let Ξ±, Ξ² be the roots of the equation x2 + 2β2x β1 = 0. The quadratic equation, whose roots are Ξ±4 + Ξ²4 and 1 (Ξ±6 + Ξ²6), is : 10 (1) x2 β190x + 9466 = 0 (2) x2 β180x + 9506 = 0 (3) x2 β195x + 9506 = 0 (4) x2 β195x + 9466 = 0
Q61.The number of solutions, of the equation πsinπ₯β2πβsinπ₯= 2 is (1) 2 (2) more than 2 (3) 1 (4) 0
Q61.The sum of all the solutions of the equation (8)2x β16 β (8)x + 48 = 0 is : (1) 1 + log8(6) (2) 1 + log6(8) (3) log8(6) (4) log8(4) βz+1 1
Q61.If S = z βC : |z βi| = |z + i| = |z β1|, then, n(S) is: (1) 1 (2) 0 (3) 3 (4) 2
Q61.Let πΌ and π½ be the roots of the equation ππ₯2 + ππ₯βπ= 0, where πβ 0. If π, π and π be the consecutive terms of a non-constant G.P and 1 1 3 then the value of πΌβπ½2 is: πΌ+ π½= 4, (1) 80 (2) 9 9 20 (3) (4) 8 3