RankLab
Back to Concepts
MathsMediumClass 11

Range of Quadratic Expression

Quadratic Equations

7

JEE Qs

8%

Hard

60

min

Always visualize the graph of the parabola and its vertex to correctly determine the range, especially for restricted domains.

🧮 Key Formulas

f(x) = ax^2 + bx + c
Discriminant D = b^2 - 4ac
Vertex coordinates = (-b/(2a), -D/(4a))
If a > 0, Range of f(x) for x ∈ R is [-D/(4a), infinity)
If a < 0, Range of f(x) for x ∈ R is (-infinity, -D/(4a)]

āœ… Key Points for JEE

  • 1The range of a quadratic expression f(x) = ax^2 + bx + c (a ≠ 0) over real numbers R is determined by the y-coordinate of its vertex, -D/(4a), and the sign of the leading coefficient 'a'.
  • 2If 'a' > 0, the parabola opens upwards, indicating a minimum value at the vertex (-b/(2a), -D/(4a)), and no maximum value. The range is [-D/(4a), āˆž).
  • 3If 'a' < 0, the parabola opens downwards, indicating a maximum value at the vertex (-b/(2a), -D/(4a)), and no minimum value. The range is (-āˆž, -D/(4a)].
  • 4For a restricted domain [x1, x2], the range is found by evaluating f(x1), f(x2), and f(-b/(2a)) (only if -b/(2a) lies within [x1, x2]), and then identifying the minimum and maximum among these relevant values.

āš ļø Common Mistakes

  • āœ•Incorrectly identifying whether the parabola opens upwards or downwards, leading to errors in determining minimum vs. maximum values.
  • āœ•Making calculation errors while finding the vertex coordinates (-b/(2a), -D/(4a)).
  • āœ•Failing to consider the vertex's y-coordinate when the domain is restricted, or not checking if the vertex lies within the restricted domain.

NCERT Chapters

  • Class 11 Maths Ch 5: Quadratic Equations
  • Class 11 Maths Ch 2: Relations and Functions