Q28.If the binding energy of ground state electron in a hydrogen atom is 13. 6 eV , then, the energy required to remove the electron from the second excited state of Li 2+ will be: x × 10−1 eV . The value of x is _____.
What This Question Tests
This question requires calculating the energy of an electron in a specific excited state for a hydrogen-like ion (Li²⁺) using Bohr's model formula to find the ionization energy.
Concepts Tested
Formulas Used
E_n = -13.6 Z²/n² eV
📚 NCERT Sections This Tests
12.4 — The Ground State Energy Of Hydrogen Atom Is –13.6 Ev. What Are The
Physics Class 12 · Chapter 12
12.4 The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
📋 Question Details
- Chapter
- Atoms
- Topic
- Ionization energy in hydrogen-like atoms
- Year
- 2023
- Shift
- 31 Jan Shift 2
- Q Number
- Q28
- Type
- Numerical
- NCERT Ref
- Class 12 Physics Ch 12: Atoms
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