Q27.If the binding energy of the electron in a hydrogen atom is 13. 6 eV , the energy required to remove the electron from the first excited state of Li++ is : (1) 13. 6 eV (2) 3. 4 eV (3) 122. 4 eV (4) 30. 6 eV
What This Question Tests
This question requires calculating the energy needed to ionize a lithium ion from its first excited state using the Bohr model's energy formula for hydrogenic atoms.
Concepts Tested
Formulas Used
E_n = -13.6 ZĀ²/nĀ² eV
š NCERT Sections This Tests
12.4 ā The Ground State Energy Of Hydrogen Atom Is ā13.6 Ev. What Are The
Physics Class 12 Ā· Chapter 12
12.4 The ground state energy of hydrogen atom is ā13.6 eV. What are the kinetic and potential energies of the electron in this state?
12.7 ā The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 Ā· Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3Ć10ā11 m. What are the radii of the n = 2 and n =3 orbits?
12.5 ā A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 Ā· Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
š Question Details
- Chapter
- Atoms
- Topic
- Bohr model for hydrogenic atoms
- Year
- 2014
- Shift
- 09 Apr Online
- Q Number
- Q27
- Type
- Numerical
- NCERT Ref
- Class 12 Physics Ch 12: Atoms
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Q70.If the binding energy of the electron in a hydrogen atom is 13.6eV, the energy required to remove the electron from the first excited state of Li++ is (1) 30.6eV (2) 13.6eV (3) 3.4eV (4) 122.4eV