Q19.The acceptor level of a p-type semiconductor is 6eV. The maximum wavelength of light which can create a hole would be : Given hc = 1242eVnm. (1) 414 nm (2) 103.5 nm (3) 207 nm (4) 407 nm
What This Question Tests
This question tests the understanding that light energy must be at least equal to the acceptor level energy to create a hole in a p-type semiconductor, and requires converting energy to wavelength.
Concepts Tested
Formulas Used
E = hc/λ
📚 NCERT Sections This Tests
14.2 — Which Of The Statements Given In Exercise 14.1 Is True For P-Type
Physics Class 12 · Chapter 14
14.2 Which of the statements given in Exercise 14.1 is true for p-type semiconductos.
14.1 — In An N-Type Silicon, Which Of The Following Statement Is True:
Physics Class 12 · Chapter 14
14.1 In an n-type silicon, which of the following statement is true: (a) Electrons are majority carriers and trivalent atoms are the dopants. (b) Electrons are minority carriers and pentavalent atoms are the dopants. (c) Holes are minority carriers and pentavalent atoms are the dopants. (d) Holes are majority carriers and trivalent atoms are the dopants.
11.7 — The Work Function For A Certain Metal Is 4.2 Ev. Will This Metal Give
Physics Class 12 · Chapter 11
11.7 The work function for a certain metal is 4.2 eV. Will this metal give hotoelectric emission for incident radiation of wavelength 330 nm?
📋 Question Details
- Chapter
- Semiconductor
- Topic
- Semiconductor physics
- Year
- 2024
- Shift
- 06 Apr Shift 2
- Q Number
- Q19
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 14: Semiconductor Electronics: Materials, Devices and Simple Circuits
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