Q83.If one of the diameters of the circle x2 + y2 −2√2x −6√2y + 14 = 0 is a chord of the circle 2 (x −2√2) 2 = r2 , then the value of r2 is equal to +(y −2√2)
What This Question Tests
This problem requires finding the radius of a circle given that one of its diameters acts as a chord for another circle, using geometric properties involving radii and distances.
Concepts Tested
Formulas Used
(x-h)^2 + (y-k)^2 = R^2
Distance between two points: sqrt((x2-x1)^2 + (y2-y1)^2)
Relationship between radius, half-chord length, and distance from center to chord
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📋 Question Details
- Chapter
- Circles
- Topic
- Properties of circles and chords
- Year
- 2022
- Shift
- 28 Jun Shift 2
- Q Number
- Q83
- Type
- Numerical
- NCERT Ref
- Class 11 Mathematics Ch 11: Conic Sections
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