Q75.How many different words can be formed by jumbling the letters in the word MISSISSIPPI in which no two S are adjacent? (1) 8 ⋅6C4 ⋅7C4 (2) 6.8 ⋅7C4 (3) 6 ⋅7 ⋅8C4 (4) 7 ⋅6C4 ⋅8C4
What This Question Tests
This question requires the application of the 'gap method' to arrange objects with a restriction (no two 'S's adjacent) combined with the permutation of identical objects for the remaining letters.
Concepts Tested
Formulas Used
n!/(n₁!n₂!...) for permutations with repetitions
Gap method for non-adjacent arrangements
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📋 Question Details
- Chapter
- Permutation & Combination
- Topic
- Permutations with restrictions
- Year
- 2008
- Shift
- Unknown
- Q Number
- Q75
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 7: Permutation and Combinations
More from this Chapter
Q85.The set S = {1, 2, 3, … , 12) is to be partitioned into three sets A, B, C of equal size. Thus, A ∪B ∪C = S, A ∩B = B ∩C = A ∩C = ϕ . The number of ways to partition S is (1) 12! (2) 12! 3!(4!)3 3!(3!)4 (3) 12! (4) 12! (4!)3 (3!)4
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