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MathsHardMCQ2019 ยท 10 Apr Shift 2

Q69.The locus of the centres of the circles, which touch the circle, ๐‘ฅ2 + ๐‘ฆ2 = 1 externally, also touch the ๐‘ฆ-axis and lie in the first quadrant, is: (1) ๐‘ฆ= โˆš1 + 2๐‘ฅ, ๐‘ฅโ‰ฅ0 (2) ๐‘ฆ= โˆš1 + 4๐‘ฅ, ๐‘ฅโ‰ฅ0 (3) ๐‘ฅ= โˆš1 + 2๐‘ฆ, ๐‘ฆโ‰ฅ0 (4) ๐‘ฅ= โˆš1 + 4๐‘ฆ, ๐‘ฆโ‰ฅ0

What This Question Tests

This problem involves finding the locus of the center of a circle satisfying multiple geometric conditions: external tangency to another circle and tangency to the y-axis, requiring careful application of distance formulas.

Concepts Tested

Equation of a circleDistance between centers of touching circlesDistance of a point from a lineLocus

Formulas Used

Distance between centers = sum of radii for external touch

Distance from y-axis = x-coordinate of center

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