Q69.The equation of the circle described on the chord 3x + y + 5 = 0 of the circle x2 + y2 = 16 as the diameter is (1) x2 + y2 + 3x + y + 1 = 0 (2) x2 + y2 + 3x + y −22 = 0 (3) x2 + y2 + 3x + y −11 = 0 (4) x2 + y2 + 3x + y −2 = 0
What This Question Tests
The question tests the ability to form the equation of a circle having a given chord as its diameter, using the general form S + λL = 0, and then finding λ.
Concepts Tested
Formulas Used
Equation of a circle through intersection of S=0 and L=0 is S + λL = 0
Equation of circle with (x1,y1) and (x2,y2) as diameter: (x-x1)(x-x2) + (y-y1)(y-y2) = 0
📚 NCERT Sections This Tests
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
5.11 — Draw All The Isomers (Geometrical And Optical) Of:
Chemistry Class 11 · Chapter 5
5.11 Draw all the isomers (geometrical and optical) of: (i) [CoCl2(en)2] + (ii) [Co(NH3)Cl(en)2] 2+ (iii) [Co(NH3)2Cl2(en)]+
2.4 — A Spherical Conductor Of Radius 12 Cm Has A Charge Of 1.6 × 10–7C
Physics Class 11 · Chapter 2
2.4 A spherical conductor of radius 12 cm has a charge of 1.6 × 10–7C distributed uniformly on its surface. What is the electric field (a) inside the sphere (b) just outside the sphere (c) at a point 18 cm from the centre of the sphere?
📋 Question Details
- Chapter
- Circles
- Topic
- Equation of circle through intersection of circle and line
- Year
- 2014
- Shift
- 19 Apr Online
- Q Number
- Q69
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 11: Conic Sections (briefly mentioned for general circle properties)
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