Q79.If x = sin−1(sin 10) and y = cos−1 (cos 10), then y −x is equal to: (1) 10 (2) π (3) 0 (4) 7π
What This Question Tests
This question requires careful application of the principal value branches for inverse trigonometric functions, specifically sin⁻¹(sin x) and cos⁻¹(cos x), to correctly evaluate expressions involving angles outside the standard range.
Concepts Tested
Formulas Used
sin⁻¹(sin θ) = θ if θ ∈ [-π/2, π/2]
cos⁻¹(cos θ) = θ if θ ∈ [0, π]
Trigonometric identities for periodicity and symmetry
📚 NCERT Sections This Tests
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5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
9.17 — (A) Sin I¢C = 1.44/1.68 Which Gives I¢C = 59°. Total Internal Reflection
Physics Class 12 · Chapter 9
9.17 (a) sin i¢c = 1.44/1.68 which gives i¢c = 59°. Total internal reflection takes place when i > 59° or when r < rmax = 31°. Now, (sin i /sin r max max ) = 1.68 , which gives imax ~ 60°. Thus, all incident rays of angles in the range 0 < i < 60° will suffer total internal reflections in the pipe. (If the length of the pipe is finite, which it is in practice, there will be a lower limit on i determined by the ratio of the diameter to the length of the pipe.) (b) If there is no outer coating, i¢c = sin–1(1/1.68) = 36.5°. Now, i = 90° will have r = 36.5° and i¢ = 53.5° which is greater than i¢c. Thus, all incident rays (in the range 53.5° < i < 90°) will suffer total internal reflections.
📋 Question Details
- Chapter
- Inverse Trigonometric Functions
- Topic
- Properties of Inverse Trigonometric Functions, Principal Value Branch
- Year
- 2019
- Shift
- 09 Jan Shift 2
- Q Number
- Q79
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 2: Inverse Trigonometric Functions
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