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MathsMediumMCQ2022 Β· 28 Jul Shift 1

Q66.Let 𝐢 be the centre of the circle π‘₯2 + 𝑦2 - π‘₯+ 2𝑦= and 𝑃 be a point on the circle. A line passes through the 4 point 𝐢, makes an angle of πœ‹ with the line 𝐢𝑃 and intersects the circle at the points 𝑄 and 𝑅. Then the area of 4 the triangle 𝑃𝑄𝑅 (in unit2) is (1) 2 (2) 2√2 πœ‹ πœ‹ (3) 8sin (4) 8cos 8 8

What This Question Tests

This problem tests the geometric understanding of circles, specifically how a line passing through the center and making an angle with a radius creates a triangle. It requires calculating the radius, chord length, and then the area of the triangle.

Concepts Tested

Equation of a circlePerpendicularity of radius and tangentArea of a triangleTrigonometric relations in a triangle

Formulas Used

Area of triangle = (1/2)ab sin(C)

Distance formula

Equation of circle: x^2 + y^2 + 2gx + 2fy + c = 0

πŸ“š NCERT Sections This Tests

8.2 β€” A Parallel Plate Capacitor (Fig. 8.6) Made Of Circular Plates Each Of Radius

Physics Class 11 Β· Chapter 8

72% match

8.2 A parallel plate capacitor (Fig. 8.6) made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to 213 a 230 V ac supply with a (angular) frequency of 300 rad s–1. Reprint 2025-26 Physics (a) What is the rms value of the conduction current? (b) Is the conduction current equal to the displacement current? (c) Determine the amplitude of B at a point 3.0 cm from the axis between the plates. FIGURE 8.6 8.3 What physical quantity is the same for X-rays of wavelength 10–10 m, red light of wavelength 6800 Γ… and radiowaves of wavelength 500m? 8.4 A plane electromagnetic wave travels in vacuum along z-direction. What can you say about the directions of its electric and magnetic field vectors? If the frequency of the wave is 30 MHz, what is its wavelength? 8.5 A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band? 8.6 A charged particle oscillates about its mean equilibrium position with a frequency of 10 9 Hz. What is the frequency of the electromagnetic waves produced by the oscillator? 8.7 The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave? 8.8 Suppose that the electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is n = 50.0 MHz. (a) Determine, B0,w, k, and l. (b) Find expressions for E and B. 8.9 The terminology of different parts of the electromagnetic spectrum is given in the text. Use the formula E = hn (for energy of a quantum of radiation: photon) and obtain the photon energy in units of eV for different parts of the electromagnetic spectrum. In what way are the different scales of photon energies that you obtain related to the sources of electromagnetic radiation? 8.10 In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 Γ— 1010 Hz and amplitude 48 V m–1. (a) What is the wavelength of the wave? (b) What is the amplitude of the oscillating magnetic field? (c) Show that the average energy density of the E field equals the average energy density of the B field. [c = 3 Γ— 108 m s–1.] Reprint 2025-26

2.2 β€” A Regular Hexagon Of Side 10 Cm Has A Charge 5 Mc At Each Of Its

Physics Class 11 Β· Chapter 2

71% match

2.2 A regular hexagon of side 10 cm has a charge 5 mC at each of its vertices. Calculate the potential at the centre of the hexagon.

9.17 β€” (A) Sin IΒ’C = 1.44/1.68 Which Gives IΒ’C = 59Β°. Total Internal Reflection

Physics Class 12 Β· Chapter 9

71% match

9.17 (a) sin iΒ’c = 1.44/1.68 which gives iΒ’c = 59Β°. Total internal reflection takes place when i > 59Β° or when r < rmax = 31Β°. Now, (sin i /sin r max max ) = 1.68 , which gives imax ~ 60Β°. Thus, all incident rays of angles in the range 0 < i < 60Β° will suffer total internal reflections in the pipe. (If the length of the pipe is finite, which it is in practice, there will be a lower limit on i determined by the ratio of the diameter to the length of the pipe.) (b) If there is no outer coating, iΒ’c = sin–1(1/1.68) = 36.5Β°. Now, i = 90Β° will have r = 36.5Β° and iΒ’ = 53.5Β° which is greater than iΒ’c. Thus, all incident rays (in the range 53.5Β° < i < 90Β°) will suffer total internal reflections.