Q26.In a Frank - Hertz experiment, an electron of energy 5.6 eV passes through mercury vapour and emerges with an energy 0.7 eV . The minimum wavelength of photons emitted by mercury atoms is close to: (1) 250 nm (2) 1700nm (3) 220nm (4) 2020nm
What This Question Tests
This question relates the energy lost by an electron in a Frank-Hertz experiment to the energy of the emitted photon and then uses the energy-wavelength relationship to find the photon's wavelength.
Concepts Tested
Formulas Used
ΔE = hc/λ
📚 NCERT Sections This Tests
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
12.8 — A 12.5 Ev Electron Beam Is Used To Bombard Gaseous Hydrogen At
Physics Class 12 · Chapter 12
12.8 A 12.5 eV electron beam is used to bombard gaseous hydrogen at room temperature. What series of wavelengths will be emitted?
📋 Question Details
- Chapter
- Atoms
- Topic
- Frank-Hertz experiment and photon emission
- Year
- 2019
- Shift
- 12 Jan Shift 2
- Q Number
- Q26
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 12: Atoms
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