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MathsHardNumerical2021 · 31 Aug Shift 1

Q84.If the variable line 3x + 4y = α lies between the two circles (x −1)2 + (y −1)2 = 1 and (x −9)2 + (y −1)2 = 4, without intercepting a chord on either circle, then the sum of all the integral values of α is

What This Question Tests

This problem requires determining the range of a parameter such that a given line lies between two circles without intersecting them, demanding a strong understanding of circle properties and coordinate geometry.

Concepts Tested

Equation of circleDistance of a point from a lineCondition for line not intercepting a chord

Formulas Used

Distance of point (x0, y0) from Ax+By+C=0 is |Ax0+By0+C|/sqrt(A^2+B^2)

Distance from center > radius for no chord interception

📚 NCERT Sections This Tests

2.1Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At

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2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

2.4A Spherical Conductor Of Radius 12 Cm Has A Charge Of 1.6 × 10–7C

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2.4 A spherical conductor of radius 12 cm has a charge of 1.6 × 10–7C distributed uniformly on its surface. What is the electric field (a) inside the sphere (b) just outside the sphere (c) at a point 18 cm from the centre of the sphere?

9.17(A) Sin I¢C = 1.44/1.68 Which Gives I¢C = 59°. Total Internal Reflection

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9.17 (a) sin i¢c = 1.44/1.68 which gives i¢c = 59°. Total internal reflection takes place when i > 59° or when r < rmax = 31°. Now, (sin i /sin r max max ) = 1.68 , which gives imax ~ 60°. Thus, all incident rays of angles in the range 0 < i < 60° will suffer total internal reflections in the pipe. (If the length of the pipe is finite, which it is in practice, there will be a lower limit on i determined by the ratio of the diameter to the length of the pipe.) (b) If there is no outer coating, i¢c = sin–1(1/1.68) = 36.5°. Now, i = 90° will have r = 36.5° and i¢ = 53.5° which is greater than i¢c. Thus, all incident rays (in the range 53.5° < i < 90°) will suffer total internal reflections.