Q68.A circle passes through the points (2, 3) and (4, 5). If its centre lies on the line y −4x + 3 = 0, then its radius is equal to : (1) √5 (2) √2 (3) 2 (4) 1
What This Question Tests
This problem tests the ability to find the equation of a circle. The center of the circle is found by solving a system of equations derived from the conditions that it lies on a given line and is equidistant from two given points.
Concepts Tested
Formulas Used
Distance formula between two points
Equation of a line
Equation of perpendicular bisector
📚 NCERT Sections This Tests
2.2 — A Regular Hexagon Of Side 10 Cm Has A Charge 5 Mc At Each Of Its
Physics Class 11 · Chapter 2
2.2 A regular hexagon of side 10 cm has a charge 5 mC at each of its vertices. Calculate the potential at the centre of the hexagon.
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
12.7 — The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 · Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
📋 Question Details
- Chapter
- Circles
- Topic
- Equation of a circle, properties of chords
- Year
- 2018
- Shift
- 15 Apr
- Q Number
- Q68
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 11: Conic Sections
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