Q18.A free electron of 2 . 6 eV energy collides with a H+ ion. This results in the formation of a hydrogen atom in the first excited state and a photon is released. Find the frequency of the emitted photon. ℎ= 6 . 6 × 10-34 J s (1) 9 . 0 × 1027 MHz (2) 1 . 45 × 109 MHz (3) 0 . 19 × 1015 MHz (4) 1 . 45 × 1016 MHz
What This Question Tests
This problem tests the understanding of energy levels in the hydrogen atom and the conservation of energy during electron capture and photon emission, involving calculations with eV to Joules conversion.
Concepts Tested
Formulas Used
E_n = -13.6/n² eV
E_photon = E_initial - E_final
E_photon = hf
📚 NCERT Sections This Tests
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
12.6 — (A) Using The Bohr’S Model Calculate The Speed Of The Electron In A
Physics Class 12 · Chapter 12
12.6 (a) Using the Bohr’s model calculate the speed of the electron in a hydrogen atom in the n = 1, 2, and 3 levels. (b) Calculate the orbital period in each of these levels.
📋 Question Details
- Chapter
- Atoms
- Topic
- Bohr model and energy levels
- Year
- 2021
- Shift
- 31 Aug Shift 2
- Q Number
- Q18
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 12: Atoms
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