RankLab
Back to Questions
MathsMediumMCQ2023 · 24 Jan Shift 1

Q71.tan-1 1 + √3 + sec-1√ 8 + 4√3 = 3 + √3 6 + 3√3 π π (1) (2) 4 2 (3) π (4) π 3 6

What This Question Tests

This question tests the ability to simplify expressions involving inverse trigonometric functions by recognizing specific values or converting them to more manageable forms using identities and properties.

Concepts Tested

Inverse tangentInverse secantTrigonometric identitiesSimplification of expressions

Formulas Used

tan⁻¹x + tan⁻¹y = tan⁻¹((x+y)/(1-xy))

sec⁻¹x = cos⁻¹(1/x)

📚 NCERT Sections This Tests

2.1Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At

Physics Class 11 · Chapter 2

70% match

2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

14.2Which Of The Statements Given In Exercise 14.1 Is True For P-Type

Physics Class 12 · Chapter 14

69% match

14.2 Which of the statements given in Exercise 14.1 is true for p-type semiconductos.

1.3Define The Following Terms:

Chemistry Class 11 · Chapter 1

69% match

1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.