Q56.The centre of the circle passing through the point (0, 1) and touching the parabola y = x2 at the point (2, 4) is : JEE Main 2020 (06 Sep Shift 2) JEE Main Previous Year Paper (1) ( −5310 , 165 ) (2) ( 65 , 5310 ) (3) ( 103 , 165 ) (4) ( −165 , 5310 )
What This Question Tests
This question requires finding the equation of the normal to a parabola at the point of tangency, understanding that the circle's center lies on this normal, and using distance properties to determine the circle's center.
Concepts Tested
Formulas Used
Equation of circle: (x-h)²+(y-k)²=r²
Slope of tangent (dy/dx)
Slope of normal = -1/(dy/dx)
📚 NCERT Sections This Tests
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2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
2.2 — A Regular Hexagon Of Side 10 Cm Has A Charge 5 Mc At Each Of Its
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2.2 A regular hexagon of side 10 cm has a charge 5 mC at each of its vertices. Calculate the potential at the centre of the hexagon.
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📋 Question Details
- Chapter
- Circles
- Topic
- Equation of circle, tangency condition
- Year
- 2020
- Shift
- 06 Sep Shift 2
- Q Number
- Q56
- Type
- Multi concept
- NCERT Ref
- Class 11 Mathematics Ch 11: Conic Sections, Class 12 Mathematics Ch 6: Applications of Derivatives
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