Q27.An electron of a hydrogen like atom, having Z = 4 , jumps from 4th energy state to 2nd energy state, The energy released in this process, will be: (Given Rch = 13. 6 eV ) Where R = Rydberg constant c = Speed of light in vacuum h = Planck's constant (1) 13. 6 eV (2) 10. 5 eV (3) 3. 4 eV (4) 40. 8 eV
What This Question Tests
This question uses Bohr's model for hydrogen-like atoms to calculate the energy released during an electronic transition from a higher energy state to a lower energy state.
Concepts Tested
Formulas Used
E_n = -13.6 Z²/n² eV
ΔE = E_final - E_initial
📚 NCERT Sections This Tests
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.4 — The Ground State Energy Of Hydrogen Atom Is –13.6 Ev. What Are The
Physics Class 12 · Chapter 12
12.4 The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?
📋 Question Details
- Chapter
- Atoms
- Topic
- Bohr's model of hydrogen-like atoms
- Year
- 2023
- Shift
- 01 Feb Shift 2
- Q Number
- Q27
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 12: Atoms
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