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PhysicsMediumNumerical2020 · 08 Jan Shift 2

Q25.The first member of the Balmer series of hydrogen atom has a wavelength of 6561 A . The wavelength of the second member of the Balmer series (in nm) is_____________

What This Question Tests

Tests the application of the Rydberg formula for the Balmer series of the hydrogen atom to calculate the wavelength of a specific spectral line given another.

Concepts Tested

Rydberg formulaBalmer seriesWavelength of spectral lines

Formulas Used

1/λ = R (1/n_1^2 - 1/n_2^2)

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