Q30.An npn transistor operates as a common emitter amplifier with a power gain of 106. The input circuit resistance is 100 Ω and the output load resistance is 10 kΩ. The common emitter current gain β will be (Round off to the Nearest Integer)
What This Question Tests
This question requires calculating the common emitter current gain (beta) of an npn transistor amplifier using the given power gain, input resistance, and load resistance.
Concepts Tested
Formulas Used
P_gain = A_v * β
A_v = β * (R_out / R_in)
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📋 Question Details
- Chapter
- Semiconductor
- Topic
- Transistor amplifier
- Year
- 2021
- Shift
- 18 Mar Shift 1
- Q Number
- Q30
- Type
- Numerical
- NCERT Ref
- Class 12 Physics Ch 14: Semiconductor Electronics: Materials, Devices and Simple Circuits
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