Q12.A magnet hung at 45° with magnetic meridian makes an angle of 60° with the horizontal. The actual value of the angle of dip is 2 (1) tan−1(√3 ) (2) tan−1(√6) (3) (4) 3 2 tan−1(√2 ) tan−1(√1 )
What This Question Tests
This question requires the application of the formula relating the true angle of dip to the apparent angle of dip when a magnet is suspended in a plane inclined to the magnetic meridian.
Concepts Tested
Formulas Used
tan φ' = tan φ / cos α
B_H = B cos φ
B_V = B sin φ
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📋 Question Details
- Chapter
- Magnetism & Matter
- Topic
- Angle of dip
- Year
- 2022
- Shift
- 27 Jul Shift 1
- Q Number
- Q12
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 5: Magnetism and Matter
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