Q26.An electron in a hydrogen atom makes a transition from n = 2 to n = 1 and emits a photon. This photon strikes a doubly ionized lithium atom which was already in an excited state and completely removes the orbiting electron. The least quantum number for the excited state of the lithium-ion for the process is (1) 2 (2) 4 (3) 5 (4) 3
What This Question Tests
This question combines the calculation of photon energy from a hydrogen atom transition with the ionization energy of a lithium ion from an excited state using the Bohr model.
Concepts Tested
Formulas Used
E_n = -13.6 Z²/n² eV
E_photon = E_initial - E_final
📚 NCERT Sections This Tests
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
12.4 — The Ground State Energy Of Hydrogen Atom Is –13.6 Ev. What Are The
Physics Class 12 · Chapter 12
12.4 The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?
📋 Question Details
- Chapter
- Atoms
- Topic
- Bohr model, hydrogen spectrum, ionization energy
- Year
- 2016
- Shift
- 09 Apr Online
- Q Number
- Q26
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 12: Atoms
More from this Chapter
Q70.If 13.6eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is (1) 10.2eV (2) 0eV (3) 3.4eV (4) 6.8eV
Q79.In a hydrogen atom, if energy of an electron in ground state is 13.6 eV, then that in the 2nd excited state is JEE Main 2002 JEE Main Previous Year Paper (1) 1.51 eV (2) 3.4 eV (3) 6.04 eV (4) 13.6 eV
Q69.The wavelengths involved in the spectrum of deuterium (21D) are slightly different from that of hydrogen spectrum, because (1) the size of the two nuclei are different (2) the nuclear forces are different in the two cases (3) the masses of the two nuclei are different (4) the attraction between the electron and the nucleus is different in the two cases
Q70.If the binding energy of the electron in a hydrogen atom is 13.6eV, the energy required to remove the electron from the first excited state of Li++ is (1) 30.6eV (2) 13.6eV (3) 3.4eV (4) 122.4eV