Q69.A possible value of tan( 41 sin−1 √638 ) (1) 2√2 −1 (2) 1 2√2 (3) √7 −1 (4) 1 √7
What This Question Tests
The question tests the ability to evaluate an expression involving inverse trigonometric functions by converting it into a trigonometric ratio using a right-angled triangle or identities.
Concepts Tested
Formulas Used
sin⁻¹(x) = θ ⇒ sin(θ) = x
tan(θ) = sin(θ)/cos(θ)
sin²θ + cos²θ = 1
📚 NCERT Sections This Tests
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📋 Question Details
- Chapter
- Inverse Trigonometric Functions
- Topic
- Properties of Inverse Trigonometric Functions
- Year
- 2021
- Shift
- 24 Feb Shift 2
- Q Number
- Q69
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 2: Inverse Trigonometric Functions
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