Q26.For the Balmer series, in the spectrum of H atom, −v = RH{ n211 2 }, the correct statements among (IV) are, (I) As wavelength decreases, the lines in the series converge. (II) The integer n1 is equal to 2 / (III) The lines of the longest wavelength correspond to n2 = 3 . (IV) The ionization energy of hydrogen can be calculated from the wave number of these lines. (1) (I), (III), (IV) (2) (I), (II), (III) (3) (I), (II), (IV) (4) (II), (III), (IV)
What This Question Tests
This question tests the conceptual understanding of the Balmer series in the hydrogen spectrum, including the Rydberg formula, convergence of spectral lines, and relation to ionization energy.
Concepts Tested
Formulas Used
1/λ = v̅ = R_H (1/n₁² - 1/n₂²)
📚 NCERT Sections This Tests
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.8 — A 12.5 Ev Electron Beam Is Used To Bombard Gaseous Hydrogen At
Physics Class 12 · Chapter 12
12.8 A 12.5 eV electron beam is used to bombard gaseous hydrogen at room temperature. What series of wavelengths will be emitted?
12.7 — The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 · Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
📋 Question Details
- Chapter
- Atoms
- Topic
- Hydrogen Spectrum (Balmer series)
- Year
- 2020
- Shift
- 08 Jan Shift 1
- Q Number
- Q26
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 12: Atoms
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